tim x
157-5(x+1)=57
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\(\Leftrightarrow\dfrac{7^x.7^2+7^x.7+7^x}{57}=\dfrac{5^{2x}+5^{2x}.5+5^{2x}.5^3}{131}\)
\(\Leftrightarrow7^x\left(\dfrac{7^2+7+1}{57}\right)=5^{2x}\left(\dfrac{1+5+5^3}{131}\right)\)
\(\Leftrightarrow7^x\dfrac{57}{57}=5^{2x}\dfrac{131}{131}\Leftrightarrow7^x=5^{2x}\Leftrightarrow7^x=25^x\Leftrightarrow x=0\)
1, \(\dfrac{x-1}{2009}+\dfrac{x-2}{2008}=\dfrac{x-3}{2007}+\dfrac{x-4}{2006}\)
\(\Leftrightarrow\left(\dfrac{x-1}{2009}-1\right)+\left(\dfrac{x-2}{2008}-1\right)=\left(\dfrac{x-3}{2007}-1\right)+\left(\dfrac{x-4}{2006}-1\right)\) ( Trừ mỗi vế cho 2 ta được phương trình như này nhé ! )
\(\Leftrightarrow\dfrac{x-2010}{2009}+\dfrac{x-2010}{2008}=\dfrac{x-2010}{2007}+\dfrac{x-2010}{2006}\)
\(\Leftrightarrow\dfrac{x-2010}{2009}+\dfrac{x-2010}{2008}-\dfrac{x-2010}{2007}-\dfrac{x-2010}{2006}=0\)
\(\Leftrightarrow\left(x-2010\right)\left(\dfrac{1}{2009}+\dfrac{1}{2008}-\dfrac{1}{2007}-\dfrac{1}{2006}\right)=0\)
Do \(\dfrac{1}{2009}+\dfrac{1}{2008}-\dfrac{1}{2007}-\dfrac{1}{2006}\ne0\) nên \(x-2010=0\Leftrightarrow x=2010\)
2, \(\dfrac{59-x}{41}+\dfrac{57-x}{43}+\dfrac{55-x}{45}+\dfrac{53-x}{47}+\dfrac{51-x}{49}=-5\)
\(\left(\dfrac{59-x}{41}+1\right)+\left(\dfrac{57-x}{43}+1\right)+\left(\dfrac{55-x}{45}+1\right)+\left(\dfrac{53-x}{47}+1\right)+\left(\dfrac{51-x}{49}+1\right)=0\)
\(\Leftrightarrow\dfrac{100-x}{41}+\dfrac{100-x}{43}+\dfrac{100-x}{45}+\dfrac{100-x}{47}+\dfrac{100-x}{49}=0\) \(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{41}+\dfrac{1}{43}+\dfrac{1}{45}+\dfrac{1}{47}+\dfrac{1}{49}\right)=0\) Do \(\dfrac{1}{41}+\dfrac{1}{43}+\dfrac{1}{45}+\dfrac{1}{47}+\dfrac{1}{49}\ne0\) nên \(100-x=0\Leftrightarrow x=100\)
Tìm x :
\(\dfrac{3}{7}\) . 5 - 9 = \(\dfrac{3\text{x}+57}{x}\) + 161\(\dfrac{1}{7}\)
\(\dfrac{15}{7}\) - 9 = \(\dfrac{3\text{x}}{x}\) + \(\dfrac{57}{x}\) + \(161\dfrac{1}{7}\)
\(\dfrac{15}{7}\) - 9 = 3 + 57 : x + 161\(\dfrac{1}{7}\)
\(\dfrac{-48}{7}\) = \(164\dfrac{1}{7}\) + 57 : x
=> 164\(\dfrac{1}{7}\) + 57 : x = \(\dfrac{-48}{7}\)
=> 57 : x = \(\dfrac{-48}{7}\) - 164\(\dfrac{1}{7}\)
=> 57 : x = -171
=> x = -171 . 57
=> x = -9747
Vậy : x = -9747
Tổng hai số là:
57 x 2 = 114
Số thứ nhất là:
114 : (5 + 3) x 5 = 71,25
Số thứ hai là;
114 - 71,25 = 42,75
Đáp số:...........
rảnh ak,,,,,,gọi 2 số là a và 5/3.a
=> a+5/3a=57.2
=>a=.....................
\(157-5\left(x+1\right)=57\)
\(5\left(x+1\right)=157-57\)
\(5\left(x+1\right)=100\)
\(x+1=100\div5\)
\(x+1=20\)
\(x=20-1\)
\(x=19\)
157 - 5( x +1 ) = 57
5( x +1 ) = 157 - 57
5( x +1 ) = 100
( x +1 ) = 100 : 5
( x +1 ) = 20
x = 20 - 1
x = 19