Question

[Luong Dinh Sy]

Cho \(S=\frac{n-5}{n+1}\) 

Tìm n để S là phân số tối giản

Answer 1

[o0o I am a studious person o0o]

\(\frac{n-5}{n+1}=\frac{n+1-6}{n+1}=1-\frac{6}{n+1}\)

\(\Rightarrow n+1\inƯ\left(6\right)=\left\{-1;1;-6;6\right\}\)

\(\Rightarrow n+1=-1\Rightarrow n=-2\)

\(\Rightarrow n+1=1\Rightarrow n=0\)

\(\Rightarrow n+1=-6\Rightarrow n=-7\)

\(\Rightarrow n+1=6\Rightarrow n=5\)
 

Answer 2

[đỗ huy bình]

bo tay