Phân tích đa thức thành nhân tử: 5a^3-10a^2b+5ab^2-10a+10b
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4a2=4b2-4a+1
=(2a)2-2*2a*1+12-4b2= (2a-1)2-(2b)2(2a-1-2b)(2a-1+2b)
\(5a^3-10a^2b+5ab^2-10a+10b\)
\(=5\left(a^3-2a^2b+ab^2-2a+2b\right)\)
\(=5\left[\left(a^3-2a^2b+ab^2\right)-2a+2b\right]\)
\(=5\left[a\left(a^2-2ab+b^2\right)-2\left(a-b\right)\right]\)
\(=5\left[a\left(a-b\right)^2-2\left(a-b\right)\right]\)
\(=5\left[\left(a-b\right)\left(a^2-ab\right)-2\left(a-b\right)\right]\)
\(=5\left(a-b\right)\left(a^2-ab-2\right)\)
a) \(3xy^2-12xy+12x\)
\(=3x\left(y-4y+4\right)\)
b) \(3x^3y-6x^2y-3xy^3-6axy^2-3a^2xy+3xy\)
\(=3xy\left(x^2-2x-y^2-2ay-a^2+1\right)\)
\(=3xy\left[\left(x^2-2\cdot x\cdot1+1^2\right)-\left(y^2+2\cdot y\cdot a+a^2\right)\right]\)
\(=3xy\left[\left(x-1\right)^2-\left(y+a\right)^2\right]\)
\(=3xy\left(x-1-y-a\right)\left(x-1+y+a\right)\)
c) \(36-4a^2+20ab-25b^2\)
\(=6^2-\left[\left(2a\right)^2-2\cdot2a\cdot5b+\left(5b\right)^2\right]\)
\(=6^2-\left(2a-5b\right)^2\)
\(=\left(6-2a+5b\right)\left(6+2a-5b\right)\)
d) \(5a^3-10a^2b+5ab^2-10a+10b\)
\(=5a\left(a^2-2ab+b^2\right)-10\left(a-b\right)\)
\(=5a\left(a-b\right)^2-10\left(a-b\right)\)
\(=\left(a-b\right)\left[5a\left(a-b\right)-10\right]\)
\(=5\left(a-b\right)\left[a\left(a-b\right)-2\right]\)
\(=5\left(a-b\right)\left(a^2-ab-2\right)\)
a. 3xy2-12xy+12x
= 3x(y2-4y+4)
= 3x(y-2)2
b. 3x3y-6x2y-3xy3-6axy2-3a2xy+3xy
= 3xy( x2-2x-y2-2ay-a2+1)
= 3xy ((x2-2x+1)-(a2-2ay-y2))
=3xy((x-1)2-(a-y)2)
= 3xy((x-1+a-y)(x-1-(a-y))
=3xy(x-1+a-y)(x-1-a+y)
d. =( 5a(a2-2ab+b2))-(10(a+b))
= 5a(a-b)2-10(a-b)
=5a(a-b)(a-b)-10(a-b)
=(a-b)(5a(a-b)-10)
Hình như mik làm sai hết rồi
\(5a^3-10a^2b+5ab^2-10a+10b\)
\(=5a\left(a^2-2ab+b^2\right)-5\left(2a-2b\right)\)
\(=5a\left(a-b\right)^2-5\left(2a-2b\right)\)
\(=5\left[a\left(a-b\right)^2-\left(2a-2b\right)\right]\)
\(=5\left[a\left(a-b\right)^2-2\left(a-b\right)\right]\)
\(=5\left(a-b\right)\left[a\left(a-b\right)-2\right]\)
\(x^6-x^4+2x^3+2x^2\)
\(=x^4\left(x^2-1\right)+2x^2\left(x+1\right)\)
\(=x^4\left(x-1\right)\left(x+1\right)+2x^2\left(x+1\right)\)
\(=\left[x^4\left(x-1\right)+2x^2\right]\left(x+1\right)\)
\(=\left[x^5-x^4+2x^2\right]\left(x+1\right)\)
\(=x^2\left(x^3-x^2+2\right)\left(x+1\right)\)
5a3-10a2b+5ab2-10a+10b
=5a.(a2-2ab+b2) - 10.(a-b)
=5a.(a-b)2-10.(a-b)
=5(a-b).[a.(a-b) - 2]
x6-x4+2x3+2x2
= x4.(x2-1)+2x2.( x+1)
= x4.(x+1).(x-1) +2x2.(x+1)
= x2.(x+1).[x2.(x-1) + 2]
= x2.(x+1).(x3-x2+2)
\(a,36-4a^2+20ab-25b^2\)
\(=6^2-\left(2a-5b\right)^2=\left(6-2a+5b\right)\left(6+2a-5b\right)\)\(b,x^2+2xy+y^2-xz-yz\)
\(=\left(x+y\right)^2-z\left(x+y\right)\)
\(=\left(x+y\right)\left(x+y-z\right)\)
\(d,5a^2-10a^2b+5ab^2-10a+10b\)
\(=5a^2-5a^2b-5a^2b+5ab^2-10a+10b\)
\(=5a\left(a-b\right)-5ab\left(a-b\right)-10\left(a-b\right)\)
\(=\left(a-b\right)\left(5a-5ab-10\right)\)