Tính bằng cách thuận tiện nhất:
A,,1/2 x 3/4 + 1/4 x 1/2
B,A=1212/2121 x 151515/161616
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a: =8/15x1/4=2/15
b: \(=\dfrac{5}{3}\cdot\dfrac{4}{5}\cdot\dfrac{6}{7}=\dfrac{24}{21}=\dfrac{8}{7}\)
c: \(=\dfrac{2}{5}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)=\dfrac{2}{5}\)
`a,`
`34,67+5,42+4,58`
`= 34,67+(5,42+4,58)=34,67+10=44,67`
`b,`
`15,27 \times 2 \times 0,5`
`= 15,27 \times (2 \times 0,5)`
`= 15,27 \times 1=15,27`
`c,`
`45,28 \times 45 + 45,28 \times 55`
`= 45,28 \times (45+55)`
`= 45,28 \times 100=4528`
a.
34,67 + 5,42 + 4,58
= (34,67 + 5,42) + 4,58= 40,09 + 4,58 = 44,67
b. 15,27 x 2 x 0.5
= (15,27 x 2) x 0.5 = 30,54 x 0,5 = 15,27
c. 45,28 x45 + 45,28 x 55
= 45,28 x (45 + 55)
= 45,28 x 100 = 4528
Ta thấy : 1313/2121 = 1313 : 101 = 13 , 1515 : 101 = 15 , 424242 : 30303 = 14 ,
2121 : 101 = 21 1313 : 101 13 151515 : 30303 5
Vậy 13 x 15 x 14 = 14
21 x 13 x 15 = 21
Bạn k cho mình đi mình nhanh nhất với lại đúng nữa !!!
\(1,\\ a,=\dfrac{7}{19}\times\left(\dfrac{1}{3}+\dfrac{2}{3}\right)=\dfrac{7}{19}\times1=\dfrac{7}{19}\\ b,=\dfrac{2}{5}+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)=\dfrac{2}{5}+1=\dfrac{7}{5}\\ 2,\\ a,=15\times\left(\dfrac{2121}{4343}+\dfrac{222222}{434343}\right)\\ =15\times\left(\dfrac{2121:101}{4343:101}+\dfrac{222222:10101}{434343:10101}\right)\\ =15\times\left(\dfrac{21}{43}+\dfrac{22}{43}\right)=15\times\dfrac{43}{43}=15\times1=15\)
\(3,\)
Cạnh \(AC=\) chu vi ABC \(-AB-BC=\dfrac{4}{5}-\dfrac{1}{5}-\dfrac{1}{4}=\dfrac{3}{5}-\dfrac{1}{4}=\dfrac{7}{20}\left(m\right)\)
Vì \(\dfrac{7}{20}>\dfrac{5}{20}>\dfrac{4}{20}\Rightarrow\dfrac{7}{20}>\dfrac{1}{4}>\dfrac{1}{5}\) nên \(AC>BC>AB\)
1.a,=(54+45+1).113
=100.113
=11300
b,=(3/7+8/14)+(4/9+10/18)
=1+1
=2
2.a,=13/10+1/3
=49/30
b,=12/9.(1/12+1/6)
=12/9.1/4
=1/3
c,=3/4.3/2
=9/8
d,=3/2-1/3
=7/6
1:tính bằng cách thuận tiện nhất:
a)54 x 113 + 45 x 113 + 113
= 54 x 113 + 45 x 113 + 113x1
=113 x(54+45+1)
= 113x100
=1300
b)3/7 + 4/9 + 8/14 + 10/18
=(3/7+8/14)+(4/9+10/18)
= 1 + 1
=2
60x [7/12+4/15]
60x153/180
=9180/180
b 1/2x2/3x3/4x4/5x5/6x6/7x7/8x8/9=40320/4032
\(A=\frac{1}{2}×\frac{3}{4}+\frac{1}{4}×\frac{1}{2}\)
\(A=\frac{1}{2}×\left(\frac{3}{4}+\frac{1}{4}\right)\)
\(A=\frac{1}{2}×\left(\frac{3+1}{4}\right)\)
\(A=\frac{1}{2}×1\)
\(A=\frac{1}{2}\)
\(B=\frac{1212}{2121}×\frac{151515}{161616}\)
\(B=\frac{1212:101}{2121:101}×\frac{151515:10101}{161616:10101}\)
\(B=\frac{12}{21}×\frac{15}{16}\)
\(B=\frac{12×15}{21×16}\)
\(B=\frac{3×4×3×5}{3×7×4×4}\)
\(B=\frac{15}{28}\)