phân tích đa thức thành nhân tử
4x^4-21x^2y^2+y^4
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4x4 - 21 x2y2 + y4
= (4x4 + 4x2y2 + y4) - 25x2y2
= [(2x2)2 + 2x2 . 2 . y2 + (y2)2] - 25x2y2
= (2x2 + y2) - 25x2y2
= (2x2 + y2 - 5xy) (2x2 + y2 + 5xy)
a) x^2+4x+3=x^2+x+3x+3=x(x+1)+3(x+1)=(x+1)(x+3)
b) 4x^2+4x-3=4x^2+4x+1-4=(2x+1)^2-4=(2x+1-2)(2x+1+2)=(2x-1)(2x+3)
c) x^2-x-12=x^2-4x+3x-12=x(x-4)+3(x-4)=(x-4)(x+3)
d) 4x^4+4x^2y^2-8y^4=4(x^4+x^2y^2-2y^4)=4(x^4-x^2y^2+2x^2y^2-2y^4)=4(x^2-y^2)(x^2+2y^2)=4(x-y)(x+y)(x^2+2y^2)
a) \(x^2+4x+3\)
\(=x^2+x+3x+3\)
\(=\left(x^2+x\right)+\left(3x+3\right)\)
\(=x\left(x+1\right)+3\left(x+1\right)\)
\(=\left(x+1\right)\left(x+3\right)\)
c) \(x^2-x-12\)
\(=x^2-4x+3x-12\)
\(=\left(x^2-4x\right)+\left(3x-12\right)\)
\(=x\left(x-4\right)+3\left(x-4\right)\)
\(=\left(x-4\right)\left(x+3\right)\)
4x^4 - 32x^2 +1 = 4x^4 + 4x^2 +1 - 36x^2 = (2x^2 + 1)^2 - 36x^2 = (2x^2 - 6x + 1)(2x^2 + 6x + 1)
4 x4 - 32 x2 + 1
= ( 2 x2 )2 - 2 . 2x2. 8 + 64 - 63
= ( 2 x2 - 8 )2 - 63
= ( 2x2 - 8 + √63 ) ( 2x2 - 8 - √63 )
Xong
\(x^2-4x+4-y^2\)
\(=\left(x-2\right)^2-y^2\)
\(=\left(x-2-y\right)\left(x-2+y\right)\)
\(x^2-4x+4-y^2\)
\(=\left(x-2\right)^2-y^2\)
\(=\left(x-2-y\right)\left(x-2+y\right)\)
4x^4+4x^3+5^2+2x+1 = (4x^4+4x^3+x^2) + (4x^2+2x) + 1 = x^2(2x+1)^2 + 2x(2x+1) + 1 = [x(2x+1)]^2 +2x(2x+1) + 1 = (2x^2+x+1)^2
\(=4x^4+21x^2y^2+y^4-25x^2y^2\)
\(\left(2x^2+y^2\right)-\left(5xy\right)^2\)
\(\left(2x^2+y^2-5xy\right)\left(2x^2+y^2+5xy\right)\)
=4x4+21x2y2+y4−25x2y2=4x4+21x2y2+y4−25x2y2
(2x2+y2)−(5xy)2(2x2+y2)−(5xy)2
(2x2+y2−5xy)(2x2+y2+5xy)