( x + 70 ) : 14 - 40 = (32 . 15 ) : 2
dấu chấm là dấu nhân
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
* \(20+65.4=\left(x+75\right):5+30\)
\(\Leftrightarrow20+260-30=\frac{x}{5}+\frac{75}{5}\)
\(\Leftrightarrow20+260-30-\frac{75}{5}=\frac{x}{5}\)
\(\Leftrightarrow235=\frac{x}{5}\Rightarrow x=235.5=1175\)
* \(2248:\left[119-\left(x-6\right)\right]=24\)
\(\Leftrightarrow2248:\left(119-x+6\right)=24\)
\(\Leftrightarrow2248:\left(125-x\right)=24\)
A mình lỡ tay, để mình tính tiếp nhá!
\(\Leftrightarrow125-x=2248:24\Leftrightarrow125-x=\frac{281}{3}\Rightarrow-x=\frac{94}{3}\Rightarrow x=-\frac{94}{3}\)(bài này mình thấy sai sai sao á, nếu mình làm sai thì thông cảm cho mình nhé!
* \(\left(x+70\right):14-40=\left(32.15\right):2\)
\(\Leftrightarrow\left(x+70\right):14=480:2+40\)
\(\Leftrightarrow\frac{x}{14}+5=280\Leftrightarrow\frac{x}{14}=275\Rightarrow x=3850\)
* \(x-4867=\left(175.2050.70\right):25+23\)
\(\Leftrightarrow x-4867-23=\left(175:25\right).\left(2050:25\right).\left(70:25\right)\)
\(\Leftrightarrow x-4890=7.82.\frac{14}{5}\)
\(\Leftrightarrow x-4890=\frac{8036}{5}\Rightarrow x=\frac{8036}{5}+4890=\frac{32486}{5}\)(bài này mình thấy hình như cũng có cái gì đó sai sai luôn hihi!)
x - 4867 = (175 . 2 - 5 . 70): 25 .23
x - 4867 = ( 52.7.2 - 52.7.2) : 25.23
x - 4867 = 0 : 25 . 23 = 0
x = 0 + 4867
x=4867.
\(445-52+155+452\\ =\left(445+155\right)+\left(452-52\right)\\ =600+4000\\ =1000\\ 102\cdot55-102\cdot73+51\cdot36\\ =102\cdot\left(55-73\right)+51\cdot36\\ =102\cdot\left(-18\right)+102\cdot18\\ =0\\ 4\cdot5\cdot2\cdot25\cdot5-1000\\ =5000-1000\\ =4000\\ 8782-291\cdot13\\ =4999\\ 254+\left\{38\cdot\left[\left(42-16\right):2\right]\right\}\\ =254+\left[38\cdot\left(26:2\right)\right]\\ =254+\left(38\cdot13\right)\\ =748\\ \left(2791\cdot34+7882:14\right)\cdot0+1510-510:2\\ =1510-255\\ =1255\)
a. \(445-52+155+452=\left(445+155\right)+\left(452-52\right)=600+400=1000\)
b. \(102\cdot55-102\cdot73+51\cdot36=102\left(55-73+18\right)=102\cdot0=0\)
c.\(4\cdot5\cdot2\cdot25\cdot5-1000=4\cdot25\cdot5\cdot5\cdot2-1000=100\cdot50-1000=5000-1000=4000\)
d. \(8782-291\cdot13=8782-3783=4999\)
e. \(254+\left\{38\left[\left(42-16\right)\div2\right]\right\}=254+\left\{30\cdot13\right\}=254+494=748\)
f. \(\left(2791\cdot34+7882\div14\right)\cdot0+1510-510\div2=0+1510-255=1255\)\
a) \(5+3^{x+1}=86\)
\(=>3^{x+1}=86-5\)
\(=>3^{x+1}=81=3^4\)
\(=>x+1=4\) ( cùng cơ số )
\(=>x=4-1\)
\(=>x=3\)
b) \(15:\left(x+2\right)=\left(3^3+3\right):10\)
\(=>15:\left(x+2\right)=\left(27+3\right):10\)
\(=>15:\left(x+2\right)=30:10=3\)
\(=>x+2=15:3\)
\(=>x+2=5\)
\(=>x=5-2\)
\(=>x=3\)
c) \(\left(9x+2\right).4=80\)
\(=>9x+2=80:4\)
\(=>9x+2=20\)
\(=>9x=20-2\)
\(=>9x=18\)
\(=>x=18:9\)
\(=>x=2\)
d) \(\left(245-x\right)+7^2=14\)
\(=>\left(245-x\right)+14=14\)
\(=>245-x=14-14\)
\(=>245-x=0\)
\(=>x=245-0\)
\(=>x=245\)
a: \(\left[\left(10-x\right)\cdot2+51\right]:3-2=3\)
=>\(\left[2\left(10-x\right)+51\right]:3=5\)
=>\(\left[2\left(10-x\right)+51\right]=15\)
=>\(2\left(10-x\right)=15-51=-36\)
=>10-x=-36/2=-18
=>\(x=10-\left(-18\right)=10+18=28\)
b: \(\left(x-12\right)-15=20-\left(17+x\right)\)
=>\(x-12-15=20-17-x\)
=>\(x-27=3-x\)
=>\(2x=30\)
=>\(x=\dfrac{30}{2}=15\)
c: \(720-\left[41-\left(2x-5\right)\right]=2^3\cdot5\)
=>\(720-\left[41-2x+5\right]=8\cdot5=40\)
=>\(\left[41-2x+5\right]=720-40=680\)
=>-2x+46=680
=>-2x=680-46=634
=>\(x=\dfrac{634}{-2}=-317\)
131 . x - 942 = 2^7 . 2^3
131 . x - 942 = 2^10
131 . x - 942 = 1024
131 . x = 1024 + 942
131 . x = 1966
x = 1966 : 131
x \(\approx15\)
b ) [ ( x + 32 ) - 17 ] . 2 = 42
[ ( x + 32 ) - 17 ] = 42 : 2
( x + 32 ) - 17 = 21
x + 32 = 21 + 17
x + 32 = 38
x = 38 - 32
x = 6
- Tính giá trị ở mỗi vế.
- So sánh rồi điền dấu thích hợp vào chỗ trống.
a) 32 + 7 < 40 b) 32 + 14 = 14 + 32
45 + 4 < 54 + 5 69 - 9 < 96 - 6
55 - 5 > 40 + 5 57 - 1 < 57 + 1
\(1500:\left[\left(30x+40\right):x\right]=30\)
\(\left[\left(30x+40\right):x\right]=1500:30\)
\(\left[\left(30x+40\right):x\right]=50\)
\(30x:x+40:x=50\)
\(30+40:x=50\Leftrightarrow40:x=50-30\)
\(40:x=20\Leftrightarrow x=40:20\Leftrightarrow x=2\)
1500 : [(30.x+40):x] = 30
\(\left(30.x+40\right):x=50\)
=> 30.x + 40 = 50.x
=> 30.x - 50.x = -40
-20x = -40
x = 2
a) 0,5 + ( x - 15/2 ) : 1/2 = 9/2
<=> (x - 15/2 ): 1/2 = 9/2 - 0,5
<=> (x - 15/2) : 1/2 = 4
<=> (x - 15/2) = 4 . 1/2
<=> x - 15/2 = 2
<=> x = 2 + 15/2
<=> x = 19/2
b) 2012x - 2010x = 2014
( 2012 - 2010 ) .x = 2014
2x = 2014
x = 2014 :2
x = 1007
( x + 70 ) : 14 - 40 = (32 . 15 ) : 2
( x + 70 ) : 14 - 40 = 240
( x + 70 ) : 14 = 240 + 40 = 280
x + 70 = 280 x 14 = 3920
x = 3920 - 70
x = 3850
Vậy x = 3850.
(x+70):14-40=(32.15):2
(x+70):14-40=480;2
(x+70):14-40=240
(x+70);14=240+40
(x+70):14=280
(x+70)=280.14
(x+70)=3360
x=3360-70
x=3290