Bài 2:(2điểm) tính bằng cách thuận tiện nhất
A, 128.72 + 14.256
B, (1+3+5+7+………+2007).(125125.127 – 127127.125)
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=(1+3+5+7+........+2007).(125125.127-127127.125)
=(1+3+5+...........+2007). 0
=0
tk mk nha
Theo bài ra , ta có :
(1+3+5+7+..........+2007).(125125.127-127127.125)
= (1+3+5+7+..........+2007) . (125 . 1001 . 127 - 127.1001.125)
= (1+3+5+7+..........+2007) . 0
= 0
Đáp số : 0
(1+3+5+7+..........+2007).(125125.127-127127.125)
= (1+3+5+7+..........+2007) . (125 . 1001 . 127 - 127.1001.125)
= (1+3+5+7+..........+2007) . 0
= 0
1, (1+3+5+....+2007+2009+2011)(125125.127-127127.125)
= (1+3+5+....+2007+2009+2011)(125.1001.127-127127127.125)
= (1+3+5+....+2007+2009+2011)(125.127127-127127.125)
= (1+3+5+....+2007+2009+2011) . 0
=0
còn bài 2 đề hình như thiếu nha bn
chúc bn học tốt!
\(a,1999-2000+1=\left(1999+1\right)-2000=2000-2000=0\\ b,450:5+550:5=\left(450+550\right):5=1000:5=200\\ c,188\times7+188\times4-188=188\times\left(7+4-1\right)=188\times10=1880\)
a,1999−2000+1=(1999+1)−2000=2000−2000=0b,450:5+550:5=(450+550):5=1000:5=200c,188×7+188×4−188=188×(7+4−1)=188×10=1880
a) \(\dfrac{3}{5}\times\dfrac{17}{21}+\dfrac{17}{21}\times\dfrac{2}{5}\)
\(=\dfrac{17}{21}\times\left(\dfrac{3}{5}+\dfrac{2}{5}\right)\)
\(=\dfrac{17}{21}\times1\)
\(=\dfrac{17}{21}\)
b) \(\dfrac{15}{8}:\dfrac{5}{20}-\dfrac{7}{8}:\dfrac{1}{4}\)
\(=\dfrac{15}{8}\times\dfrac{20}{5}-\dfrac{7}{8}\times4\)
\(=\dfrac{15}{8}\times4-\dfrac{7}{8}\times4\)
\(=4\times\left(\dfrac{15}{8}-\dfrac{7}{8}\right)\)
\(=4\times1\)
\(=4\)
\(\dfrac{8}{13}+\dfrac{4}{9}+\dfrac{1}{3}+\dfrac{5}{13}+3\)
\(=1+\dfrac{7}{9}+3\)
\(=4+\dfrac{7}{9}=\dfrac{43}{9}\)
`39/16 : 5/8 - 7/16 : 5/8`
`=39/16 xx 8/5- 7/16 xx 8/5`
`=8/5 xx (39/16 - 7/16)`
`= 8/5 xx2`
`= 16/5`
__
` 4/3 xx 9/8 - 4/3 xx 3/8`
`=4/3 -(9/8 - 3/8)`
`= 4/3 xx 3/4`
`=1`
\(a,\\ \dfrac{39}{16}:\dfrac{5}{8}-\dfrac{7}{16}:\dfrac{5}{8}\\ =\dfrac{39}{16}\cdot\dfrac{8}{5}-\dfrac{7}{16}\cdot\dfrac{8}{5}\\ =\dfrac{8}{5}\cdot\left(\dfrac{39}{16}-\dfrac{7}{16}\right)=\dfrac{8}{5}\cdot2=\dfrac{16}{5}\\ b,\\ \dfrac{4}{3}\cdot\dfrac{9}{8}-\dfrac{4}{3}\cdot\dfrac{3}{8}=\dfrac{3}{2}-\dfrac{1}{2}=1\)
A. 64 : 16 = 4
B. 210 : 30 = 7
C. 504 : 56 = 9
D. 115 : 23 = 5
Bài 2: Tính bằng cách thuận tiện nhất
\(\text{a. 1255 + 436 + 145}\)
\(=\left(1255+145\right)+436\)
\(=1400+436\)
\(=1836\)
\(\text{b. 142 x 12 + 142 x 18}\)
\(=142\times\left(12+18\right)\)
\(=142\times30\)
\(=4260\)
\(\text{c. 4 x 18 x 25}\)
\(=\left(25\times4\right)\times18\)
\(=100\times18\)
\(=1800\)
Bài 2:
a: \(=1400+436=1836\)
b: =142(12+18)
=142*30
=4260
c: \(=100\cdot18=1800\)
Bài 3:
a: \(41m^219dm^2>409dm^2\)
b: \(90000cm^2< 90m^2\)
c: \(30m^26dm^2< 3060dm^2\)
d: \(8012cm^2>8dm^212cm^2\)
e: \(5dm^29cm^2=509cm^2\)
f: \(3940dm^2=39m^240dm^2\)
g: \(300m^26dm^2>3006dm^2\)
h: \(2009cm^2< 21dm^2\)
A, 128.72 + 14.256
=128.72 + 128.(14x2)
=128.72 + 128.28
=128 .(72+28)
=128x100
=12800