2.A: Oh. I've just realized. I haven't got any money.
B: Haven't you? Well, don't worry._____________you some. (I/lend)
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a) HBr: axit brom hidric
H2SO3: axit sufurơ
H3PO4: axit photpho ric
H2SO4: axit sufuric (câu này bạn ghi đề sai nhé)
b) Mg(OH)2: Magiê hidroxit
Fe(OH)3: Sắt(III) oxit
Cu(OH)2: Đồng hidroxit
c) Ba(NO3)2: Bari nitrat
Al2(SO4)3: Nhôm sufat
Na2SO3: Natri sufurơ
ZnS: Kẽm sufu
Na2HPO4: Natri hidrophotphat
6NaOH + 2H3PO4 ---> 2Na3PO4 + 6H2O
2KOH + BaCl2 ---> 2KCl + Ba(OH)2
Ba(OH)2 + 2HNO3 ---> Ba(NO3)2 + 2H2O
Ca(OH)2 + 2CO2 ---> Ca(HCO3)2
2NaOH + CuSO4 ---> Na2SO4 + Cu(OH)2
3Ba(OH)2 + 2Na3PO4 ---> 6NaOH + Ba3(PO4)2
SO2 + 2KOH ---> K2SO3 + H2O
3Na2CO3 + 2Fe(OH)3 ---> Fe2(CO3)3 + 6NaOH
Ca(HCO3)2 + 2NaOH ---> 2NaHCO3 + Ca(OH)2
2KHSO3 + Ba(OH)2 ---> 2KOH + Ba(HCO3)2
\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
\(Al_2\left(SO_4\right)_3+6NaOH\rightarrow2Al\left(OH\right)_3+3Na_2SO_4\)
\(2Al\left(OH\right)_3+Ba\left(OH\right)_2\rightarrow Ba\left[Al\left(OH\right)_4\right]_2\)
\(Ba\left[Al\left(OH\right)_4\right]_2+H_2SO_4\rightarrow2Al\left(OH\right)_3+BaSO_4+2H_2O\)
\(2Al\left(OH\right)_3\rightarrow Al_2O_3+3H_2O\)
\(2Al_2O_3\rightarrow4Al+3O_2\)
Fe + H2SO4 => FeSO4 + H2
FeSO4 + BaCl2 => FeCl2 + BaSO4
FeCl2 + 2NaOH => Fe(OH)2 + 2NaCl
Fe(OH)2 + Cu(NO3)2 => Cu(OH)2 + Fe(NO3)2
Fe(NO3)2 + 2NaOH => Fe(OH)2 + 2NaNO3
Fe(OH)2 => FeO + H2O
FeO + H2 => Fe + H2O
Fe + 3/2 Cl2 => FeCl3
FeCl3 + 3AgNO3 => Fe(NO3)3 + 3AgCl
Fe(NO3)3 + 3NaOH => Fe(OH)3 + 3NaNO3
2Fe(OH)3 + 3H2SO4 => Fe2(SO4)3 + 6H2O
Fe2(SO4)3 + 3BaCl2 => 3BaSO4 + 2FeCl3
FeCl3 + Al => AlCl3 + Fe
NH4HCO3 → NH3 + CO2 + H2O
A......................B........C........D
NH4HCO3 + NaCl → NaHCO3 + NH4Cl
A....................................E................F
NaHCO3 → Na2CO3 + CO2 + H2O
E....................G................C......D
NaHCO3 + NaOH → Na2CO3 + H2O
E..................................G..............D
2NH4Cl + Ca(OH)2 → CaCl2 + 2NH3 + 2H2O
F.......................................H...........B........D
Na2CO3 + Ca(OH)2 → CaCO3 + 2NaOH
G.....................................I
NaHCO3 + Ca(OH)2 → CaCO3 + 2H2O + NaOH
E........................................I.............D
Na2CO3 + CO2 + H2O → 2NaHCO3
G..................C......D.............E
P/s: thách nx đi
a. PTHH: CaC2 + 2H2O ===> C2H2 + Ca(OH)2
b. Áp dụng định luật bảo toàn khối lượng, ta có:
\(m_{CaC2}+m_{H2O}=m_{C_2H_2}+m_{Ca\left(OH\right)2}\)
\(\Leftrightarrow m_{H2O}=m_{C_2H_2}+m_{Ca\left(OH\right)2}-m_{CaC2}\)
\(\Leftrightarrow m_{H2O}=13+37-41=9\left(gam\right)\)
Áp dụng công thức \(V=\frac{m}{D}\)
=> Thể tích nước cần dùng là:
\(V_{H2O}=\frac{m_{H2O}}{D_{H2O}}=\frac{9}{1}=9\left(ml\right)\)
Bài 1: \(a,Fe+2HCl\rightarrow FeCl_2+H_2\)
\(b,Cu\left(OH\right)_2+2HCl\rightarrow CuCl_2+2H_2O\)
\(c,Na_2CO_3+2HCl\rightarrow2NaCl+CO_2+H_2O\)
\(d,Cu\left(OH\right)_2\underrightarrow{t^0}CuO+H_2O\)
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
\(CuO+H_2\underrightarrow{t^0}Cu+H_2O\)
Tham khảo
I will lend
2.A: Oh. I've just realized. I haven't got any money.
B: Haven't you? Well, don't worry._______I will lend______you some. (I/lend)