Tìm x
a) / x - 2 / < 3
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bài 1 :
x + 678 = 2813
x = 2813 - 678
x = 2135
4529 + x = 7685
x = 7685 - 4529
x = 3156
x - 358 = 4768
x = 4768 + 358
x = 5126
2495 - x = 698
x = 2495 - 698
x = 1797
x × 23 = 3082
x = 3082 : 23
x = 134
36 × x = 27612
x = 27612 : 36
x = 767
x : 42 = 938
x = 938 x 42
x = 39396
4080 : x = 24
x = 4080 : 24
x =170
bài 2 :
a. x + 6734 = 3478 + 5782
x + 6734 = 9260
x = 9260 - 6734
x = 2526
b. 2054 + x = 4725 - 279
2054 + x = 4446
x = 4446 - 2054
x = 2392
c. x - 3254 = 237 x 145
x - 3254 = 34365
x = 34365 + 3254
x = 37619
d. 124 - x = 44658 : 54
124 - x = 827
x = 827 - 124
x = 703
\(a,\Leftrightarrow\left(x-2\right)^3-3x\left(x-2\right)=0\\ \Leftrightarrow\left(x-2\right)\left(x-2-3x\right)=0\\ \Leftrightarrow\left(x-2\right)\left(-2x-2\right)=0\\ \Leftrightarrow\left(x-2\right)\left(x+1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\\ b,\Leftrightarrow\left(x+3\right)\left(x^2-3x+9\right)+\left(x+3\right)\left(x-9\right)=0\\ \Leftrightarrow\left(x+3\right)\left(x^2-2x\right)=0\\ \Leftrightarrow x\left(x-2\right)\left(x+3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-3\end{matrix}\right.\)
a) Ta có: \(\left(x-3\right)^2-2\left(x-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(x-5\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=5\end{matrix}\right.\)
b) Ta có: \(x:0.25+x:0.2+x:0.1+x=34\)
\(\Leftrightarrow4x+5x+x+x=34\)
\(\Leftrightarrow11x=34\)
hay \(x=\dfrac{34}{11}\)
a) \(\Rightarrow x^2+4x+25-x^2=3\Rightarrow4x=-22\Rightarrow x=-\dfrac{11}{2}\)
b) \(\Rightarrow\left(4x+3-2x+3\right)\left(4x+3+2x-3\right)=0\)
\(\Rightarrow2\left(x+3\right).6x=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)
a) \(\dfrac{3}{5}+x=\dfrac{1}{2}+1\)
\(\dfrac{3}{5}+x=\dfrac{3}{2}\)
\(x=\dfrac{3}{2}-\dfrac{3}{5}\)
\(x=\dfrac{15}{10}-\dfrac{6}{10}\)
\(x=\dfrac{9}{10}\)
b) \(3:x=\dfrac{2}{3}+2\dfrac{1}{2}\)
\(3:x=\dfrac{2}{3}+\dfrac{5}{2}\)
\(3:x=\dfrac{4}{6}+\dfrac{15}{6}\)
\(3:x=\dfrac{19}{6}\)
\(x=3:\dfrac{19}{6}\)
\(x=3\times\dfrac{6}{19}\)
\(x=\dfrac{18}{19}\)
Mik nhớ câu này làm rồi mak!!!
a,\(\dfrac{3}{5}\)+ x=\(\dfrac{1}{2}\)+1
\(\dfrac{3}{5}\)+x=\(\dfrac{3}{2}\)
x=\(\dfrac{3}{2}\)-\(\dfrac{3}{5}\)
x=\(\dfrac{9}{10}\)
b,
b) 3:x=23+2123:x=23+212
3:x=23+523:x=23+52
3:x=46+1563:x=46+156
3:x=1963:x=196
x=3:196x=3:196
x=3×619x=3×619
x=1819
Lời giải:
a.
$\frac{2}{3}+\frac{1}{3}:3\times x=20\text{%}$
$\frac{2}{3}+\frac{1}{9}\times x=\frac{1}{5}$
$\frac{1}{9}\times x=\frac{1}{5}-\frac{2}{3}=\frac{-7}{15}$
$x=\frac{-7}{15}: \frac{1}{9}=\frac{-21}{5}$
b.
$\frac{3-x}{5-x}=\frac{6}{11}$
$\Rightarrow 6(5-x)=11(3-x)$
$\Rightarrow 30-6x=33-11x$
$\Rightarrow 5x=3$
$\Rightarrow x=\frac{3}{5}$
a)
=> \(\left[{}\begin{matrix}x-2< 3\\x-2< -3\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}x=5\\x=-1\end{matrix}\right.\)
TH1
X-2<3
x<5
Th2
x-2<-3
x<-1
Vậy no là x<5 , x<-1