Tìm x:
a) 3136 + x = 5315 b) x x 5 = 8725.
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a, \(x=\dfrac{9,5}{5}=\dfrac{19}{10}\)
b, \(x=\dfrac{15,12}{42}=\dfrac{9}{25}\)
a: \(x\cdot3\cdot5=2,7\)
=>\(x\cdot15=2,7\)
=>\(x=\dfrac{2,7}{15}=0,18\)
b: \(1,2:x\cdot4=20\)
=>\(1,2:x=20:4=5\)
=>\(x=1,2:5=0,24\)
\(a,246:x+34:x=5\\ \Rightarrow\left(246+34\right):x=5\\ \Rightarrow280:x=5\\ \Rightarrow x=56\\ b,360:x-126:x=6\\ \Rightarrow\left(360-126\right):x=6\\ \Rightarrow234:x=6\\ \Rightarrow x=39\)
a) \(\dfrac{x.2}{-15}=\dfrac{-5}{3}\)
\(\dfrac{x.2}{-15}=\dfrac{25}{-15}\)
x.2=25
x=12,5
b) \(\dfrac{x-1}{-12}=\dfrac{-3}{x-1}\)
(x-1)2=-3.(-12)
(x-1)2=36
⇒(x-1)2\(\Rightarrow\left[{}\begin{matrix}x-1=6\\x-1=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=7\\x=-5\end{matrix}\right.\)
a/ 136,5 –x = 5 ,4 x 1,2
136,5 - x = 6,48
x = 136,5 - 6,48
x = 130,02
b/ 259,2 : x = 39 + 4,2
259,2 : x = 43,2
x = 259,2 : 43,2
x = 6
a) Ta có: \(\left(2x-3\right)-\left(x-5\right)=\left(x+2\right)-\left(x-1\right)\)
\(\Leftrightarrow2x-3-x+5=x+2-x+1\)
\(\Leftrightarrow x+2=3\)
hay x=1
Vậy: x=1
b) Ta có: \(2\left(x-1\right)-5\left(x+2\right)=-10\)
\(\Leftrightarrow2x-2-5x-10=-10\)
\(\Leftrightarrow-3x=-10+10+2=2\)
hay \(x=-\dfrac{2}{3}\)
Vậy: \(x=-\dfrac{2}{3}\)
a, (2x - 3) - (x - 5) = (x + 2) - (x - 1)
2x - 3 - x + 5 = x + 2 - x + 1
(2x - x) + (-3 + 5) = (x - x) + (2 + 1)
x + 2 = 3
x = 1
a) 3136 + x = 5315 b) x x 5 = 8725
x = 5315 – 3136 x = 8725 : 5
x = 2179 x = 1745.