Question

[Pham Trong Bach]

Quy đồng mẫu thức hai phân thức:  $\frac{x+y}{x^{2}y+x^2};\frac{2x-y}{y+1}$

A.  $\frac{x-y}{x^{2}y+x^2}=\frac{x-y}{x^2(y+1)};\frac{2x+y}{y+1}=\frac{x^2(2x-y)}{x^2(y+1)}$ 

B.  $\frac{x+y}{x^{2}y-x^2}=\frac{x+y}{x^2(y-1)};\frac{2x-y}{y+1}=\frac{x^2(2x-y)}{x^2(y+1)}$

C.  $\frac{x+y}{x^{2}y+x^2}=\frac{x+y}{x^2(y+1)};\frac{2x-y}{y+1}=\frac{x^2(2x-y)}{x^2(y+1)}$ 

D.  $\frac{x+y}{x^{2}y+x^2}=\frac{x+y}{x(y+1)};\frac{2x-y}{y+1}=\frac{2x-y}{x^2(y+1)}$ 

Answer 1

[Cao Minh Tâm]