(x-59).16-8=120
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`@` `\text {Ans}`
`\downarrow`
`a,`
`(x-1954) \times 5=50`
`x-1954 = 50 \div 5`
`x-1954 = 10`
`x=10 + 1954`
`x= 1964`
`B.`
`48 - 40 \times x=8`
`40 \times x=48-8`
`40 \times x = 40`
` x=40 \div 40`
`x=1`
`C.`
`2+70 \div x = 3`
`70 \div x = 3-2`
`70 \div x = 1`
`x=70 \div 1`
`x=70`
`D. [3 \times (x+2) \div 7] \times 4=120`
`3 \times (x+2) \div 7 = 120 \div 4`
`3 \times (x+2) \div 7 =30`
`3 \times (x+2) = 30 \times 7`
`3 \times (x+2)=210`
`x+2=210 \div 3`
`x+2=70`
`x=70-2`
`x=68`
`E.`
`7,2 \div [ (0,6 \times x+8) \div 20 + 59] = 0,12?` Thiếu ngoặc bạn nhé._.
\(a,\left(x-1954\right)\times5=50\\ x-1954=50:5\\ x-1954=10\\ x=1954+10\\ x=1964\\b.48-40\times x=8\\40\times x=48-8\\40\times x=40\\ x=40:40\\ x=1 \\ c.2+70:X=3\\ 70:x=3-2\\ 70:x=1\\ x=70:1\\ x=70\\ d,\left[3\times\left(x+2\right):7\right]\times4=120\\ 3\times\left(x+2\right):7-120:4\\ 3\times\left(x+2\right):7=30\\ \left(x+2\right):7=30:3\\ \left(x+2\right):7=10\\ x+2=10\times7\\ x+2=70\\ x=70-2\\ x=68\)
1a) x - 7 = -18
=> x = -18 + 7
=> x = -11
b) -2x + 8 = -24
=> -2x = -24 - 8
=> -2x = -32
=> x = -32 : (-2)
=> x = 16
c) 4 - 2x = 59
=> 2x = 4 - 59
=> 2x = -55
=> x = -55 : 2
=> x = -27,5
d) -36 - x = 59
=> x = -36 - 59
=> x = -95
k) -81 : x = (-3)
=> x = -81 : (-3)
=> x = 27
g) -16 : x = 2
=> x = -16 : 2
=> x = -8
m) (6 - 27) - (3 - x) = (-7) . (-8)
=> -21 - (3 - x) = 56
=> 3 - x = -21 - 56
=> 3 - x = -77
=> x = 3 + 77
=> x = 80
a) 10-x-5=-5-7-11
=> 5 - x = -23
=> x = 28
b) |x| -3=0
=> |x| = 3
=> x = 3 hoặc x -3
c) ( 7-|x| ) .(2x-4)=0
=> 7 - |x| = 0 hoặc 2x - 4 = 0
=> |x| = 7 hoặc 2x = 4
=> x = 7 hoặc x = - 7 hoặc x = 2
c)2+3x=-15-19
=> 2 + 3x = -34
=> 3x = 36
=> x = 12
=2x2/1x3 x 3x3/2x4x4/3x5 x ... x 11x11/10x12
=2x2x3x3x4x4x...x11x11/1x3x2x4x3x5x...x10x12
= 2x3x4x...x11)x(2x3x4x...x11)/(1x2x3x4x...x11)/(1x2x3x...x10)x(2x3x4x...x11)
=11x2/1x12
=22/12
=11/6
4/3x9/8x16/15x...x121/120=\(\dfrac{2^2}{1\cdot3}\)x\(\dfrac{3^2}{2\cdot4}\)x\(\dfrac{4^2}{3\cdot5}\)x...x\(\dfrac{11^2}{10\cdot12}\)=\(\dfrac{2}{3}\)x\(\dfrac{11}{10}\)=\(\dfrac{11}{15}\)
a) \(47.69-31\left(-47\right)=47-69-\left(-31\right).47\)
\(=47.69+31.47=47.\left(69+31\right)=47.100=4700\)
b) \(16\left(38-2\right)-38\left(16-1\right)=16.38-16.2-38.16-\left(-38\right).1\)
\(=\left(16.38-38.16\right)-32+38=0-32+38=6\)
c) \(\left(-41\right)\left(59-2\right)+59\left(41-2\right)\) \(=\left(-41\right).59-\left[\left(-41\right).2\right]+59.41-59.2\)
\(=\left[\left(-41\right).59+59.41\right]-\left[\left(-49\right).2-51.2\right]=0-\left(-100\right).2=200\)
d) \(125.\left(-8\right)\left(-25\right)9.4.1000\div3=125.200.9.4.1000\div3\)
\(=\left(125.4\right)\left(9\div3\right)\left(200.1000\right)=500.3.200000=300000000\)
a) \(-524\cdot\left[23+\left(-45\right)\right]+524\cdot\left(-45+123\right)\)
\(=-524\cdot\left[\left(23-45\right)-\left(-45+123\right)\right]\)
\(=-524\cdot\left(23-45+45-123\right)\)
\(=-524\cdot-100\)
\(=52400\)
b) \(47\cdot69-31\cdot\left(-47\right)\)
\(=-47\cdot\left(-69-31\right)\)
\(=-47\cdot-100\)
\(=4700\)
c) \(16\left(38-2\right)-38\left(16-1\right)\)
\(=16\cdot38-16\cdot2-38\cdot16+38\)
\(=-16\cdot2+38\)
\(=-36+38\)
\(=2\)
d) \(\left(-41\right)\cdot\left(59+2\right)+59\cdot\left(41-2\right)\)
\(=-41\cdot59-41\cdot2+41\cdot59-2\cdot59\)
\(=-41\cdot2-2\cdot59\)
\(=-2\left(41+59\right)\)
\(=-2\cdot100\)
\(=-200\)
e) \(25\cdot\left(-8\right)\cdot\left(-25\right)\cdot9\cdot4\cdot100^0:3\)
\(=\left(-1000\right)\cdot\left(-25\right)\cdot9\cdot4\cdot1:3\)
\(=25000\cdot9\cdot4:3\)
\(=25000\cdot3\cdot4\)
\(=100000\cdot3\)
\(=300000\)
a: (x-35)-120=0
=>x-35=120
=>x=120+35=155
b: 59(x-29)=0
=>x-29=0
=>x=29
c: 2x+3x=45:3
=>5x=15
=>x=3
`@` `\text {Ans}`
`\downarrow`
`(x - 35) - 120 = 0`
`x - 35 = 0 + 120`
`x - 35 = 120`
`x = 120+ 35`
`x = 155`
Vậy, `x = 155`
____
`(x - 29)*59 = 0`
`x - 29 = 0 \div 59`
`x - 29 = 0`
`x = 0 + 29`
`x = 29`
Vậy, `x= 29`
____
`2x + 3x = 45 \div 3`
`(2 + 3)x = 15`
`5x = 15`
`x = 15 \div 5`
`x = 3`
Vậy, `x = 3.`
(x - 59).16 - 8 = 120
=> (x - 59).16 = 120 + 8
=> (x - 59).16 = 128
=> x - 59 = 128 : 16
=> x - 59 = 8
=> x = 8 + 59 = 67
Vậy x = 67
[x-59].16-8=120
[x-59].16 =120+8
[x-59].16 =128
x-59 =128:16
x-59 =8
x =8+59
x =67
k cho mình nha