tìm x biết : -8/11.x=2/5.1/4
a) x=15/80
b) x=-2/75
c) x=11/90
d)-11/80
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15 - [ 80 - 12 . ( x + 5 ) ] : 2 = 11
[ 80 - 12 . ( x + 5 ) ] : 2 = 15 - 11 = 4
80 - 12 . ( x + 5 ) = 4 . 2 = 8
12 ( x + 5 ) = 80 - 8 = 72
x + 5 = 72 : 12 = 6
x + 5 = 6
x = 6 - 5 = 1
1: x=3/4-1/2=3/4-2/4=1/4
2: x-1/5=2/11
=>x=2/11+1/5=21/55
3: x-5/6=16/42-8/56
=>x-5/6=8/21-4/28=5/21
=>x=5/21+5/6=15/14
4: x/5=5/6-19/30
=>x/5=25/30-19/30=6/30=1/5
=>x=1
5: =>|x|=1/3+1/4=7/12
=>x=7/12 hoặc x=-7/12
6: x=-1/2+3/4
=>x=3/4-1/2=1/4
11: x-(-6/12)=9/48
=>x+1/2=3/16
=>x=3/16-1/2=-5/16
1)x= 1/4
2)x= 2/11+ 1/5
x= 21/55
3)x - 5/6 = 5/21
x = 5/21+5/6
x = 15/14
4)x/5 = 5/6 + -19/30
x:5 = 1/5
x = 1/5.5
x = 1
5) |x| - 1/4 = 6/18
|x| = 6/18 - 1/4
|x| =7/12
⇒x= 7/12 hoặc -7/12
6)x = -1/2 +3/4
x= 1/4
7) x/15 = 3/5 + -2/3
x:15 = -1/15
x = -1/15. 15
x = -1
8)11/8 + 13/6 = 85/x
85/24 = 85/x
⇒ x = 24
9) x - 7/8 = 13/12
x = 13/12 + 7/8
x = 47/24
10)x - -6/15 = 4/27
x = 4/27 + (-6/15)
x = -34/135
11) -(-6/12)+x = 9/48
x= 9/48 - 6/12
x = -5/16
12) x - 4/6 = 5/25 + -7/15
x -4/6 = -4/15
x = -4/15 + 4/6
x = 2/5
\(-4+x=-4+7\)
\(\Rightarrow x=-4+7+4\)
\(\Rightarrow x=7\)
\(\left(-3\right)-\left(-5-x\right)=-15+\left(-6+15\right)\)
\(\Rightarrow x=-15-6+15+3-5\)
\(\Rightarrow x=-8\)
\(-\left(x+2\right)+2=\left(8-15\right)+15\)
\(\Rightarrow-x+2+2=-7+15\)
\(\Rightarrow-x=-7+15-2-2\)
\(\Rightarrow x=-4\)
\(4+\left(x-4\right)=-\left(11-2\right)+\left(11+4\right)\)
\(\Rightarrow4+x-4=-11+2+11+4\)
\(\Rightarrow x=-11+2+11+4-4+4\)
\(\Rightarrow x=6\)
a) -4 + x = -4 + 7 b) (-3) - (-5-x) = -15 + (-6+15)
-4 + x + 4 - 7 = 0 (-3) + 5 + x = -6
x - 7 = 0 2 + 6 = -x
x= 7 8 = -x
Vậy x= 7 x= -8 =) Vậy x= -8
c) -(x+2)+2=(8-15)+15 d) 4+(x-4)= -(11-2) + (11+4 )
-x - 2 + 2 = 8 4+x-4 = 6
-x = 8 x=6
x= -8 Vậy x=6
Vậy x= -8
Bài 7:
a, \(x\) = \(\dfrac{1}{5}\) + \(\dfrac{2}{11}\)
\(x\) = \(\dfrac{11}{55}\) + \(\dfrac{10}{55}\)
\(x=\dfrac{21}{55}\)
b, \(\dfrac{x}{15}\) = \(\dfrac{3}{5}\) - \(\dfrac{2}{3}\)
\(\dfrac{x}{15}\) = \(\dfrac{9}{15}\) - \(\dfrac{10}{15}\)
\(\dfrac{x}{15}\) = \(\dfrac{1}{15}\)
\(x\) = 1
c, \(\dfrac{11}{8}\) + \(\dfrac{13}{6}\)= \(\dfrac{85}{x}\)
\(\dfrac{33}{24}\) + \(\dfrac{52}{24}\) = \(\dfrac{85}{x}\)
\(\dfrac{85}{24}\) = \(\dfrac{85}{x}\)
24 = \(x\)
a) \(\frac{x}{y}=\frac{15}{7}\Leftrightarrow\)\(\frac{x}{15}=\frac{y}{17}\)
Áp dụng tc của dãy tỉ số bằng nhau ta có:
\(\frac{x}{15}=\frac{y}{17}=\frac{x-2y}{15-2\cdot17}=\frac{16}{-19}\)
=> \(\begin{cases}x=-\frac{240}{19}\\y=-\frac{272}{19}\end{cases}\)
b) \(\frac{x}{y}=\frac{8}{11};\frac{z}{y}=\frac{3}{11}\)
\(\Leftrightarrow\)\(\frac{x}{8}=\frac{y}{11};\frac{z}{3}=\frac{y}{11}\)
\(\Leftrightarrow\)\(\frac{x}{8}=\frac{y}{11}=\frac{z}{3}\)
Áp dụng tc của dãy tỉ số bằng nhau ta có:
\(\frac{x}{8}=\frac{y}{11}=\frac{z}{3}=\frac{x+y-z}{8+11-3}=\frac{80}{16}=5\)
\(\Rightarrow\begin{cases}x=40\\y=55\end{cases}\)
c) \(\frac{x}{4}=\frac{y}{3}\Rightarrow\)\(\frac{x}{8}=\frac{y}{6}\)
=> \(\frac{x}{8}=\frac{y}{6}=\frac{z}{11}\)
Đặt \(\frac{x}{8}=\frac{y}{6}=\frac{z}{11}=k\Rightarrow x=8k;y=6k;z=11k\)
Có \(xyz=-528\)
\(\Leftrightarrow8k\cdot6k\cdot11k=-528\)
\(\Leftrightarrow528\cdot k^3=-528\)
\(\Leftrightarrow k^3=-1\Leftrightarrow k=-1\)
Với k=-1 thì : x=-8;y=-6;x=-11
a) Từ \(\frac{x}{y}=\frac{15}{7}\Rightarrow\frac{x}{15}=\frac{y}{7}\)
Áp dụng t/c dãy tỉ số bằng nhau,ta có:
\(\frac{x}{15}=\frac{y}{7}=\frac{x-2y}{15-14}=16\)
=> \(\begin{cases}x=240\\y=112\end{cases}\)
b) Từ \(\frac{x}{y}=\frac{8}{11}\Rightarrow\frac{x}{8}=\frac{y}{11}\)
\(\frac{z}{y}=\frac{3}{11}\Rightarrow\frac{z}{3}=\frac{y}{11}\)
=> \(\frac{x}{8}=\frac{y}{11}=\frac{z}{3}\)
Áp dụng t/c dãy tỉ số bằng nhau, ta có:
\(\frac{x}{8}=\frac{y}{11}=\frac{z}{3}=\frac{x+y-z}{8+11-3}=\frac{80}{16}=5\)
=> \(\begin{cases}x=40\\y=55\\z=15\end{cases}\)
c)Từ \(\frac{x}{4}=\frac{y}{3}\Rightarrow\frac{x}{8}=\frac{y}{6}\)
=> \(\frac{x}{8}=\frac{y}{6}=\frac{z}{11}\)
Đặt \(\frac{x}{8}=\frac{y}{6}=\frac{z}{11}\) = k
=> \(\begin{cases}x=8k\\y=6k\\z=11k\end{cases}\)
=> x.y.z = -528 => 8k.6k.11k = -528 => 528k3 = -528
=> k3 = -1 => k = -1
=> \(\begin{cases}x=-8\\y=-6\\z=-11\end{cases}\)
a) x + 10 = 20
<=> x = 20 - 10 = 10
Vậy x = 10
b) 2x + 15 = 35
<=> 2x = 35 - 15 = 20
<=> x = 10
Vậy x = 10
c) 3(x + 2) = 15
<=> x + 2 = 15 : 3 = 5
<=> x = 5 - 2 = 3
Vậy x = 3
d) 10x + 15.11 = 20.10
<=> 10x + 165 = 200
<=> 10x = 200 - 165 = 35
<=> x = 35 : 10 = 3,5
Vậy x = 3,5
e) 4(x + 2) = 3.4
<=> x + 2 = 3
<=> x = 3 - 2 = 1
Vậy x = 1
f) 33x + 135 = 26.9
<=> 33x + 135 = 234
<=> 33x = 234 - 135 = 99
<=> x = 99 : 33 = 3
Vậy x = 3
g) 2x + 15 + 16 + 17 = 100
<=> 2x + 48 = 100
<=> 2x = 100 - 48 = 52
<=> x = 52 : 2 = 26
Vậy x = 26
h) 2(x + 9 + 10 + 11) = 4.12.5
<=> x + 30 = 120
<=> x = 120 - 30 = 90
Vậy x = 90
\(11-\left(15+11-2.x\right)=x-\left(25-9\right)\)
\(11-15-11+2x=x-16\)
\(2x-x=-16-11+15+11\)
\(1x=-1\)
\(x=-1\)
a: \(3\left(x-3\right)-6x=0\)
=>\(3x-9-6x=0\)
=>-3x-9=0
=>3x+9=0
=>3x=-9
=>\(x=-\dfrac{9}{3}=-3\)
b: Đề thiếu vế phải rồi bạn
c: \(2\left(x-3\right)+3x=9\)
=>2x-6+3x=9
=>5x-6=9
=>5x=6+9=15
=>x=15/5=3
d: \(x\left(x-11\right)+2\left(x-11\right)=0\)
=>\(\left(x-11\right)\left(x+2\right)=0\)
=>\(\left[{}\begin{matrix}x-11=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=11\\x=-2\end{matrix}\right.\)
e: \(x\left(x+2\right)+8=x^2\)
=>\(x^2+2x+8=x^2\)
=>2x+8=0
=>2x=-8
=>x=-8/2=-4
f: \(8\left(x+1\right)+2x=-2\)
=>\(8x+8+2x=-2\)
=>10x=-2-8=-10
=>\(x=-\dfrac{10}{10}=-1\)
g: 12-3(x+2)=0
=>3(x+2)=12
=>x+2=12/3=4
=>x=4-2=2
\(-\dfrac{8}{11}.x=\dfrac{2}{5}.\dfrac{1}{4}\)
\(-\dfrac{8}{11}.x=\dfrac{2}{20}\)
\(-\dfrac{8}{11}.x=\dfrac{1}{10}\)
\(x=\dfrac{1}{10}:-\dfrac{8}{11}\)
\(x=-\dfrac{11}{81}\)
Chọn d
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