Tìm x, biết: 27 mũ x = 3 mũ ×+2
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\(2^{x+1}-2^x=3^2\)
\(\Rightarrow2^x\cdot\left(2-1\right)=9\)
\(\Rightarrow2^x=9\)
\(\Rightarrow x\in\varnothing\)
\(2^{x+1}-2^x=3^2\)
=>2^x*2-2^x=9
=>2^x=9
=>\(x\in\varnothing\)
Bài 6 :
a) \(\dfrac{625}{5^n}=5\Rightarrow\dfrac{5^4}{5^n}=5\Rightarrow5^{4-n}=5^1\Rightarrow4-n=1\Rightarrow n=3\)
b) \(\dfrac{\left(-3\right)^n}{27}=-9\Rightarrow\dfrac{\left(-3\right)^n}{\left(-3\right)^3}=\left(-3\right)^2\Rightarrow\left(-3\right)^{n-3}=\left(-3\right)^2\Rightarrow n-3=2\Rightarrow n=5\)
c) \(3^n.2^n=36\Rightarrow\left(2.3\right)^n=6^2\Rightarrow\left(6\right)^n=6^2\Rightarrow n=6\)
d) \(25^{2n}:5^n=125^2\Rightarrow\left(5^2\right)^{2n}:5^n=\left(5^3\right)^2\Rightarrow5^{4n}:5^n=5^6\Rightarrow\Rightarrow5^{3n}=5^6\Rightarrow3n=6\Rightarrow n=3\)
Bài 7 :
a) \(3^x+3^{x+2}=9^{17}+27^{12}\)
\(\Rightarrow3^x\left(1+3^2\right)=\left(3^2\right)^{17}+\left(3^3\right)^{12}\)
\(\Rightarrow10.3^x=3^{34}+3^{36}\)
\(\Rightarrow10.3^x=3^{34}\left(1+3^2\right)=10.3^{34}\)
\(\Rightarrow3^x=3^{34}\Rightarrow x=34\)
b) \(5^{x+1}-5^x=100.25^{29}\Rightarrow5^x\left(5-1\right)=4.5^2.\left(5^2\right)^{29}\)
\(\Rightarrow4.5^x=4.25^{2.29+2}=4.5^{60}\)
\(\Rightarrow5^x=5^{60}\Rightarrow x=60\)
c) Bài C bạn xem lại đề
d) \(\dfrac{3}{2.4^x}+\dfrac{5}{3.4^{x+2}}=\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{10}}\)
\(\Rightarrow\dfrac{3}{2.4^x}-\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{x+2}}-\dfrac{5}{3.4^{10}}=0\)
\(\Rightarrow\dfrac{3}{2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)+\dfrac{5}{3.4^2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)=0\)
\(\Rightarrow\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)\left(\dfrac{3}{2}+\dfrac{5}{3.4^2}\right)=0\)
\(\Rightarrow\dfrac{1}{4^x}-\dfrac{1}{4^8}=0\)
\(\Rightarrow\dfrac{4^8-4^x}{4^{x+8}}=0\Rightarrow4^8-4^x=0\left(4^{x+8}>0\right)\Rightarrow4^x=4^8\Rightarrow x=8\)
1. 15^x=225
<=>15^x=15^2
=>x=2
vậy....
2. x^3=27
<=>x^3=3^3
=>x=3
vậy......
3. 4.2^x-3=125
4.2^x=128
2^x=32
2^x=2^5
=>x=5
vậy.....
\(15^x=225\)
\(\Leftrightarrow15^x=15^2\)
\(\Leftrightarrow x=2\)
\(x^3=27\)
\(\Leftrightarrow x^3=3^3\)
\(\Leftrightarrow x=3\)
\(4.2^x-3=125\)
\(\Leftrightarrow4.2^x=125+3\)
\(\Leftrightarrow4.2^x=128\)
\(\Leftrightarrow2^x=128:4\)
\(\Leftrightarrow2^x=32\)
\(\Leftrightarrow2^x=2^5\)
\(\Leftrightarrow x=5\)
~ Hok tốt ~
x3 = 125
x3 = 53
x = 5
2x = 128
2x = 27
x = 7
127 < 5x < 630
127 < 625 < 630
127 < 54 < 630
x = 4
a, (3 mũ 2 -x) nhân 3=-27
3 mũ 2-x=-27 chia 3
3 mũ 2-x =-9
9-x =-9
x =9-(-9)
x = 18
vậy x=18
A) \(X+15=4^2\)
=> \(X=16-15\)
=> \(X=1\)
b) 100 : ( 35 - X ) = 5
=> 35 - X = 100 : 5
=> 35 - X = 20
=> X = 35 - 20
=> X = 15
C) \(3X-17=2^2\cdot2^4\)
=> \(3X-17=2^6=64\)
=> \(3X=64+17\)
=> \(3X=81\)
=> \(X=27\)
d) 120 - 20 ( 50 - 4X ) = 0
=> 20 ( 50 - 4X ) = 120
=> 50 - 4X = 120 : 20
=> 50 - 4X = 6
=> 4X = 50 - 6
=> 4X = 44
=> X = 11
toán lớp 7 em lớp 5
câu trả lời của em là
\(\frac{5}{27}\)
Ta có:
\(27^x=3^{x+2}\)
\(\Rightarrow3^{3x}=3^{x+2}\)
\(\Rightarrow3x=x+2\)
\(\Rightarrow3x-x=2\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
Học Tốt!!!