Question

[Mochi Bánh Gạo Đáng Yêu]

Bài 1 : Giải các phương trình sau :

1) x – 8 = 3 – 2(x+ 4)

2) 2(x + 3) – 3(x – 1) = 2

3) 4(x – 5) – (3x – 1) = x – 19

4) 7 – ( x – 2) = 5(2x – 3)

5) 32 – 4(0,5y – 5) = 3y + 2

6) 3(x – 1) – x = 2x – 3

7) x2 + 2x – 4 = –12 + 3x + \(x^2\)

8) x( x – 1) – x(x + 3) = 15

9) x( x – 1) = x(x + 3)

10) (x–1)(x +3) – (x+2)(x–3) = 0

11) (x–2)(x –5) – (x–3)(x–4) = 0

12) (3x – 2)(4x + 3) = 2x(6x – 1)

13) \(4x^2\) – (2x + 1)(2x – 1) = 0

14) (4x–5)(x+3) = (2x – 3)(7+2x)

15) (x + 3)(x – 2) = (x + 1)2

16) (x+7)(x–7) + \(x^2\) – 2 = 2(\(x^2\)+5 )

17) \(\left(x-1\right)^2\) + \(\left(x+3\right)^2\) = 2(x– 2)(x+2)

18) \(\left(x-5\right)^2\) = \(\left(x+3\right)^2\) + 2

Mình đang cần , các bạn giúp mình với ạ !!!

Answer 1

[Nguyễn Thị Mai Linh]

1,\(x-8=3-2\left(x+4\right)\)

\(\Leftrightarrow\)\(x-8=3-2x-8\)

\(\Leftrightarrow x-8-3+2x+8=0\)

\(\Leftrightarrow3x-3=0\)

\(\Leftrightarrow3x=3\)

\(\Leftrightarrow x=1\)

Vậy \(S=\left\{1\right\}\)

Answer 2

[Nguyễn Thị Mai Linh]

2,\(2\left(x+3\right)-3\left(x-1\right)=2\)

\(\Leftrightarrow2\left(x+3\right)-3\left(x-1\right)-2=0\)

\(\Leftrightarrow2x+6-3x+3-2=0\)

\(\Leftrightarrow-x+7=0\) \(\Leftrightarrow-x=-7\)

\(\Leftrightarrow x=7\)

Vậy \(S=\left\{1\right\}\)