bài 1: phân tích đa thức thành nhân tử
a) 42-12xy+9y2
b) x2-9x+20
c)x2+7x+12
giúp mk vs ạ
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\(a,4x^2-12xy+9y^2=\left(2x-3y\right)^2\)
\(b,x^2-9x+20=x^2-4x-5x+20\)
\(=x\left(x-4\right)-5\left(x-4\right)\)
\(=\left(x-4\right)\left(x-5\right)\)
\(c,x^2+7x+12=x^2+3x+4x+12\)
\(=x\left(x+3\right)+4\left(x+3\right)\)
\(=\left(x+3\right)\left(x+4\right)\)
a. \(x^2\) - 9y2
= (\(x\))2 - (3y)2
= (\(x\) - 3y)(\(x\) + 3y)
\(a,a^2\left(a-b\right)+ab\left(a-c\right)=a\left(a+b\right)\left(a-c\right)\\ c,=\left(x^2-2x+1\right)\left(x^2+2x+1\right)=\left(x-1\right)^2\left(x+1\right)^2\\ b,=\left(x-5\right)^2-9y^2=\left(x-5-3y\right)\left(x-5+3y\right)\\ d,=4\left(x^2-9x+14\right)=4\left(x-7\right)\left(x-2\right)\)
b) \(x^2y-x^3-10y+10x\)
\(=x^2\left(y-x\right)-10\left(y-x\right)\)
\(=\left(y-x\right)\left(x^2-10\right)\)
c) \(x^2\left(x-2\right)+49\left(2-x\right)\)
\(=\left(x-2\right)\left(x^2-49\right)\)
\(=\left(x-2\right)\left(x-7\right)\left(x+7\right)\)
a: =5x(x-y)-7(x-y)
=(x-y)(5x-7)
b: =x(x+2y)+(x+2y)
=(x+2y)(x+1)
c; =(x-3)^2-9y^2
=(x-3-3y)(x-3+3y)
a
\(5x^2-5xy+7y-7x\\ =5x\left(x-y\right)+7\left(y-x\right)\\ =5x\left(x-y\right)-7\left(x-y\right)\\ =\left(5x-7\right)\left(x-y\right)\)
b
\(x^2+2xy+x+2y\\ =x\left(x+2y\right)+\left(x+2y\right)\\ =\left(x+1\right)\left(x+2y\right)\)
c
\(x^2-6x-9y^2+9\\ =x^2-6x+9-\left(3y\right)^2\\ =x^2-2.x.3+3^2-\left(3y\right)^2\\ =\left(x-3\right)^2-\left(3y\right)^2\\ =\left(x-3-3y\right)\left(x-3+3y\right)\)
\(a,15x-5xy\\ =5x\left(3-y\right)\\ b,\left(x^2+1\right)^2-4x^2\\ =\left(x^2-x+1\right)\left(x^2+x+1\right)\\ c,x^2-10x-9y^2+25\\ =\left(x-5\right)^2-9y^2\\ =\left(x-9y-5\right)\left(x+9y-5\right)\)
a) \(=x\left(x-5\right)\)
b) \(=\left(x+3y-3y\right)\left(x+3y+3y\right)=x\left(x+6y\right)\)
c) \(=x\left(x+y\right)-3\left(x+y\right)=\left(x+y\right)\left(x-3\right)\)
\(A=x^2-y^2+7x+7y\)
\(=\left(x-y\right)\left(x+y\right)+7\left(x+y\right)\)
\(=\left(x+y\right)\left(x-y+7\right)\)
\(B=4x^3-4x^2+x\)
\(=x\left(4x^2-4x+1\right)\)
\(=x\left(2x-1\right)^2\)
\(C=x^2-6xy+9y^2-9\)
\(=\left(x-3y\right)^2-9\)
\(=\left(x-3y-3\right)\left(x-3y+3\right)\)
A=\(x^2+7x+7y-y^2=\left(x^2-y^2\right)+\left(7x+7y\right)=\left(x-y\right)\left(x+y\right)+7\left(x+y\right)=\left(x+y\right)\left(x-y+7\right)\)
B=\(4x^3-4x^2+x=x\left(4x^2-4x+1\right)=x\left(2x-1\right)^2\)
C=\(x^2+9y^2-9-6xy=\left(x^2-6xy+9y^2\right)-9=\left(x-3y\right)^2-3^2=\left(x-3y-3\right)\left(x-3y+3\right)\)
a) \(\left(x^2-7x+12\right).\left(x^2-15x+56\right)-60\)
\(=\left(x-3\right)\left(x-4\right)\left(x-7\right)\left(x-8\right)-60\)
b) \(x^4+2000x^2+1999x+2000\)
\(=\left(x^2-x+2000\right)\left(x^2+x+1\right)\)
\(=\left(x^2+x-1\right)^2+1999\left(x^2+x+1\right)+1\)
\(x^2-9x+20=x^2-5x-4x+20=x\left(x-5\right)-4\left(x-5\right)=\left(x-4\right)\left(x-5\right)\)
\(x^2+7x+12=x^2+3x+4x+12=x\left(x+3\right)+4\left(x+3\right)=\left(x+4\right)\left(x+3\right)\)
b, x2 - 9x + 20
= x2 - 5x - 4x + 20
= ( x2 - 5x ) - ( 4x + 20 )
= x( x - 5 ) - 4( x - 5 )
= ( x - 4 ). ( x - 5 )
c, x2 + 7x + 12
= x2 + 3x + 4x + 12
= ( x2 + 3x ) + ( 4x + 12 )
= x( x + 3 ) + 4( x + 3 )
= ( x + 4 ). ( x + 3 )