[98*17-66*17]/72
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(98x17—17x26):72
=17x(98—26):72
=17x72:72
=17x1
=17
A,(36×28+36×28)÷73
=36x(28+28):73
=36x56:73
=2016:73
=2016/73
B,(98×17-26×17)÷72
=17x(98-26):72
=17x72:72
=17x(72:72)
=17x1
=17
a) ( 36 x 28 + 36 x 45 ) : 73
= 36 x (28 + 45 ):73
=36 x 73 :73
= 36 x (73 : 73)
= 36 x 1
= 36
b) ( 98 x 17 - 26 x 17 ) : 72
= 17 x (98-17):72
= 17 x 72 :72
=17 x (72 :72)
= 17 x 1
= 17
a) ( 36 x 28 + 36 x 45 ) : 73 = 36
b) ( 98 x 17 - 26 x 17 ) : 72 = 17
66x17+32x17+17x2
=(66+32+2)x17
=100x17
=1700
32x20+32x29+32x11+60x68
=32x(20+29+11+68)
=32x100
=3200
12x25x2+24x25+3x50x8
=25x(24+24+48) (mik tách 50 ra là 2x25 rùi nhân 3x2x8 ra 48 còn 24 ở đầu thì mik lấy 12x2=24 nha )
=25x100
=2500
M=2+4+6+...+98+100
có 4-2=2
6-4=2
100-98=2
có số liền trước kém số liền sau 2 đơn vị
SSH là:
(100-2):2+1=50 (số )
Tổng M là :
(100+2)x50 :2= 2550
vậy M =2550
66 x 17 + 32 x 17 + 17 x 2
= 17 ( 66 + 32 + 2 )
= 17 x 100 = 1700
32 x 20 + 32 x 29 + 32 x 11 + 60 x 68
= 32 x ( 20 + 29 + 11 ) + 60 x 68
= 32 x 60 + 60 x 68
= 60 x ( 32 + 68 )
= 60 x 100 = 6000
12 x 25 x 2 + 24 x 25 + 3 x 50 x 8
= 24 x 25 + 24 x 25 + 48 x 25
= 25 ( 24 + 24 + 48 )
= 25 x 96
a) \(48.19+48.15+134.52\)
\(=48\left(19+15\right)+6968\)
\(=48.34+6968\)
\(=1632+6968\)
\(=8600.\)
b) \(27.121-87.27+73.34\)
\(=27\left(121-87\right)+73.34\)
\(=27.34+73.34\)
\(=34\left(27+73\right)\)
\(=34.100\)
\(=3400.\)
c) \(125.98-125.46-52-25\)
\(=125\left(98-46\right)-52-25\)
\(=125.52-52-25\)
\(=52\left(125-1\right)-25\)
\(=52.124-25\)
\(=6448-25\)
\(=6423.\)
d) \(136.23+136.17-40.36\)
\(=136\left(23+17\right)-40.36\)
\(=136.40-40.36\)
\(=40\left(136-36\right)\)
\(=40.100\)
\(=4000.\)
e) \(66.25+5.66+66.14+33.94\)
\(=33\left(2.50+5.2+14.2+94\right)\)
\(=33\left(50+10+28+94\right)\)
\(=33.182\)
\(=6006.\)
a, \(A=\frac{17^{18}+1}{17^{19}+1}< 1\)
\(A=\frac{17^{18}+1}{17^{19}+1}< \frac{17^{18}+1+16}{17^{19}+1+16}=\frac{17^{18}+17}{17^{19}+17}=\frac{17(17^{17}+1)}{17(17^{18}+1)}=B\)
\(\Rightarrow A< B\)
b, Tương tự câu a
a)Ta có : A = \(\frac{17^{18}+1}{17^{19}+1}< \frac{17^{18}+1+16}{17^{19}+1+16}=\frac{17^{18}+17}{17^{19}+17}=\frac{17\left(17^{17}+1\right)}{17\left(17^{18}+1\right)}=\frac{17^{17}+1}{17^{18}+1}\) = B
Vậy A < B
b) Làm tương tự như câu A
\(A=\frac{17^{18}+1}{17^{19}+1}< \frac{17^{18}+1+16}{17^{19}+1+16}\)
\(A=\frac{17^{18}+1}{17^{19}+1}< \frac{17^{18}+17}{17^{19}+17}\)
\(A=\frac{17^{18}+1}{17^{19}+1}< \frac{17^{17}+1}{17^{18}+1}=B\)
=> A < B
Bài 1:
1: \(17A=\dfrac{17^{19}+17}{17^{19}+1}=1+\dfrac{16}{17^{19}+1}\)
\(17B=\dfrac{17^{18}+17}{17^{18}+1}=1+\dfrac{16}{17^{18}+1}\)
mà \(17^{19}+1>17^{18}+1\)
nên 17A>17B
hay A>B
2: \(C=\dfrac{98^{99}+98^{10}+1-98^{10}}{98^{89}+1}=98^{10}+\dfrac{1-98^{10}}{98^{89}+1}\)
\(D=\dfrac{98^{98}+98^{10}+1-98^{10}}{98^{88}+1}=98^{10}+\dfrac{1-98^{10}}{98^{88}+1}\)
mà \(98^{89}+1>98^{88}+1\)
nên C>D
Đề bài là gì thế?
\(\frac{98\cdot17-66\cdot17}{72}\)
\(=\frac{(98-66)\cdot17}{72}\)
\(=\frac{32\cdot17}{72}=\frac{2\cdot16\cdot17}{2\cdot36}=\frac{2\cdot2\cdot2\cdot2\cdot2\cdot17}{2\cdot2\cdot2\cdot3\cdot3}=\frac{2\cdot2\cdot17}{3\cdot3}=\frac{4\cdot17}{3\cdot3}=\frac{68}{9}\)