56 x 5 =
99 x 2 =
x + 3 = 9
Vậy x = ?
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Ta có \(1\frac{1}{5}x+\frac{2}{3}x=-\frac{56}{125}\)
<=> \(\frac{6}{5}x+\frac{2}{3}x=-\frac{56}{125}\)
<=> \(\frac{28}{15}x=-\frac{56}{125}\)
<=> \(x=-\frac{2}{15}\)
b) \(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
<=> \(\left(\frac{x+1}{99}+1\right)+\left(\frac{x+2}{98}+1\right)+\left(\frac{x+3}{97}+1\right)+\left(\frac{x+4}{96}+1\right)=0\)
<=> \(\frac{x+100}{99}+\frac{x+100}{98}+\frac{x+100}{97}+\frac{x+100}{96}=0\)
<=> \(\left(x+100\right)\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\right)=0\)
<=> x + 100 = 0
<=> x = -100
Bài 1:
\(101\cdot125+101\cdot25-101\cdot50\)
\(=101\cdot\left(125+25-50\right)\)
\(=101\cdot100\)
\(=10100\)
Bài 2:
\(76\cdot115+56\cdot24+59\cdot24\)
\(=76\cdot115+24\cdot\left(56+59\right)\)
\(=76\cdot115+24\cdot115\)
\(=115\cdot\left(76+24\right)\)
\(=115\cdot100\)
\(=11500\)
99 x 56 x 82 : 4 : 2 x 34 = 5544 x 82 : 4 : 2 x 34
= 454 608 : 4 : 2 x 34
= 113 652 : 2 x 34
= 56 826 x 34
= 1 932 084
99 x 56 x 82 : 4 : 2 x 34
= 5544 x 82 : 4 : 2 x 34
= 454608: (4x2) x 34
= 56826 x 34
= 1932084
a) \(33\times4+5\times33+33\times3+33-99=33\times4+5\times33+33\times3+33\times1-33\times3\)
\(=33\times\left(4+5+3+1-3\right)=33\times10=330\)
b) \(256+347+453-147-56-253=\left(256-56\right)+\left(347-147\right)+\left(453-253\right)\)
\(=200+200+200=600\)
2 \(\times\) 3 \(\times\) 8 .... 45 - 5 \(\times\) 3
2 \(\times\) 3 \(\times\) 8 = 6 \(\times\) 8 = 48
\(45-5\times3\) = 45 - 15 = 30
Vì 48 > 40 nên
2 \(\times\) 3 \(\times\) 8 > 45 - 5 \(\times\) 3
b, 46 + 56 .... 56 - 5 \(\times\) 3
46 + 56 = 102
56 - 5 \(\times\) 3 = 56 - 15 = 41
Vì 102 > 41 nên
46 + 56 > 56 - 5 \(\times\) 6
56x5=280
99x2=198
x+3=9
=>x=9-3
x=6
56 x 5 = 280
99 x 2 = 198
x + 3 = 9
x = 9 - 3
x = 6
Vậy x = 6
#Hok tốt