(\(\frac{1}{3}\)+\(\frac{3}{4}\) - \(\frac{13}{12}\) ) : (\(\frac{12}{13}\) + \(\frac{123}{234}\) +\(\frac{1234}{2345}\) )
Giải giúp mình với nhé
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a: \(A=\dfrac{63-48-70}{84}:\dfrac{-3\cdot84+4\cdot60+5\cdot70}{840}\cdot\dfrac{1-14}{12}\)
\(=\dfrac{-55}{84}\cdot\dfrac{840}{338}\cdot\dfrac{-13}{12}=\dfrac{55}{1}\cdot\dfrac{10}{338}\cdot\dfrac{13}{12}=\dfrac{275}{156}\)
b: \(=-234\cdot123+123\cdot4356-123\cdot2312+234\cdot123-234\cdot2312+2312\cdot234+2312\cdot123\)
\(=123\cdot4356-123\cdot2312+123\cdot2312=123\cdot4356=535788\)
\(\frac{12-\frac{12}{7}-\frac{12}{289}-\frac{12}{85}}{4-\frac{12}{7}-\frac{12}{289}-\frac{12}{85}}:\frac{3+\frac{3}{13}+\frac{3}{169}+\frac{3}{91}}{7+\frac{7}{13}+\frac{7}{169}+\frac{1}{91}}=\frac{12\left(\frac{1}{7}-\frac{1}{289}-\frac{1}{85}\right)}{4\left(\frac{1}{7}-\frac{1}{289}-\frac{1}{85}\right)}:\frac{3\left(\frac{1}{13}+\frac{1}{169}+\frac{1}{91}\right)}{7\left(\frac{1}{13}+\frac{1}{169}+\frac{1}{91}\right)}\)
\(=\frac{12}{4}:\frac{3}{7}\)
\(=3:\frac{3}{7}\)
\(=3.\frac{7}{3}\)
\(=7\)
mk nha bạn
\(B=\frac{1}{5}-\frac{3}{7}+\frac{5}{9}-\frac{2}{11}+\frac{7}{13}-\frac{9}{16}-\frac{7}{13}+\frac{2}{12}-\frac{5}{9}+\frac{3}{7}-\frac{1}{5}-\frac{1}{5}\)
\(B=\left(\frac{1}{5}-\frac{1}{5}\right)-\left(\frac{3}{7}-\frac{3}{7}\right)+\left(\frac{5}{9}-\frac{5}{9}\right)+\left(\frac{7}{13}-\frac{7}{13}\right)-\frac{2}{11}+\frac{2}{12}-\frac{9}{16}-\frac{1}{5}\)
\(B=0-0+0+0-\frac{2}{11}+\frac{2}{12}-\frac{9}{16}-\frac{1}{5}\)
\(B=\frac{-2}{11}+\frac{2}{12}-\frac{9}{16}-\frac{1}{5}\)
Đến đây chỉ còn cách quy đồng thôi
\(\left(\frac{1}{3}+\frac{3}{4}-\frac{13}{12}\right):\left(\frac{12}{13}+\frac{123}{234}+\frac{1234}{2345}\right)\)
\(=\left(\frac{4}{12}+\frac{9}{12}-\frac{13}{12}\right):\left(\frac{12}{13}+\frac{123}{234}+\frac{1234}{2345}\right)\)
\(=\left(\frac{4+9-13}{12}\right):\left(\frac{12}{13}+\frac{123}{234}+\frac{1234}{2345}\right)\)
\(=0:\left(\frac{12}{13}+\frac{123}{234}+\frac{1234}{2345}\right)\)
\(=0\)
Study well ! >_<
(13 +34 - 1312 ) : (1213 + 123234 +12342345 )
=\(\left(\frac{4}{12}+\frac{9}{12}-\frac{13}{12}\right):\left(\frac{12}{13}+\frac{123}{234}+\frac{1234}{2345}\right)\)
= \(\left(\frac{4+9-13}{12}\right):\left(\frac{12}{13}+\frac{123}{234}+\frac{1234}{2345}\right)\)
= \(0:\left(\frac{12}{13}+\frac{123}{234}+\frac{1234}{2345}\right)\)
\(=0\)