Tìm x
5^x * 5^x+1 * 5^x+2 < 100...0 (có 18 c/s 0) : 2^18
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Đặt A=(2+x)5(3x-1)7
khai triển ta có:A=(\(_{k=0}^5\Sigma C_5^k2^{5-k}x^k\)).(\(^7_{i=0}\Sigma C_7^i\left(3x\right)^i\))
=\(\left(_{k=0}^5\Sigma\right)\left(_{i=0}^7\Sigma\right)\left(C_5^kC^i_7\right)\left(x^k.\left(3x\right)^i\right)\)
=số hạng\(\left(C_5^kC^i_7\right)\left(x^k.\left(3x\right)^i\right)\)chứa x5 tại k+i=5
có k\(\in\){0,1,2,...5},i\(\in\){0,1,2,...7}
=>(k,i)={(0,5);(1,4);(2,3);(3,2);(4,1);(5,0)}
=>Hệ số của x5 là:\(\left(C_5^0C^5_7\right)3^5\)+\(\left(C_5^1C^4_7\right)\left(3^4\right)\)+\(\left(C_5^2C^3_7\right)\left(3^3\right)\)+\(\left(C_5^3C^2_7\right)\left(3^2\right)\)+
\(\left(C_5^4C^1_7\right)\left(3^1\right)\)+\(\left(C_5^5C^0_7\right)3^0\)=30724
Hok tốt!!!
a, y \(\times\) \(\dfrac{4}{3}\) = \(\dfrac{16}{9}\)
y = \(\dfrac{16}{9}\) : \(\dfrac{4}{3}\)
y = \(\dfrac{4}{3}\)
b, ( y - \(\dfrac{1}{2}\)) + 0,5 = \(\dfrac{3}{4}\)
y - 0,5 + 0,5 = \(\dfrac{3}{4}\)
y = \(\dfrac{3}{4}\)
c, \(\dfrac{4}{5}-\dfrac{2}{5}y\) = 0,2
0,8 - 0,4y = 0,2
0,4y = 0,8 - 0,2
0,4y = 0,6
y = 1,5
d, (y + \(\dfrac{3}{4}\)) \(\times\) \(\dfrac{5}{7}\) = \(\dfrac{10}{9}\)
y + \(\dfrac{3}{4}\) = \(\dfrac{10}{9}\) : \(\dfrac{5}{7}\)
y + \(\dfrac{3}{4}\) = \(\dfrac{14}{9}\)
y = \(\dfrac{14}{9}\) - \(\dfrac{3}{4}\)
y = \(\dfrac{29}{36}\)
e, y : \(\dfrac{5}{4}\) = \(\dfrac{9}{5}\) + \(\dfrac{1}{2}\)
y : \(\dfrac{5}{4}\) = \(\dfrac{23}{10}\)
y = \(\dfrac{23}{10}\)
y = \(\dfrac{23}{8}\)
f, y \(\times\) \(\dfrac{1}{2}\) + \(\dfrac{3}{2}\) \(\times\) y = \(\dfrac{4}{5}\)
y \(\times\) ( \(\dfrac{1}{2}+\dfrac{3}{2}\)) = \(\dfrac{4}{5}\)
2y = \(\dfrac{4}{5}\)
y = \(\dfrac{2}{5}\)
\(\left(x-12,5\right):\frac{3}{4}=\frac{8}{5}\)
\(x-12,5=\frac{8}{5}.\frac{3}{4}\)
\(x-12,5=\frac{6}{5}\)
\(x=\frac{6}{5}+12,5\)
\(x=\frac{137}{10}\)
\(\left(x-\frac{2}{5}\right)\times\frac{5}{11}=\frac{75}{22}\)
\(x-\frac{2}{5}=\frac{75}{22}:\frac{5}{11}\)
\(x-\frac{2}{5}=\frac{15}{2}\)
\(x=\frac{15}{2}+\frac{2}{5}\)
\(x=\frac{79}{10}\)
\(\Rightarrow5^{3x+2}< 10^{18}\div2^{18}\)
\(\Rightarrow5^{3x+2}< 5^{18}\)
\(3x+2< 18\)
\(x< \frac{16}{3}\)
a: \(=\dfrac{3}{5}\cdot\dfrac{5}{4}+\dfrac{1}{2}\cdot\dfrac{2}{3}=\dfrac{3}{4}+\dfrac{1}{3}=\dfrac{9+4}{12}=\dfrac{13}{12}\)
b: \(\Leftrightarrow x\cdot\dfrac{5}{4}=\dfrac{5}{8}\)
hay x=1/2
100..0(có 18 cs 0):2^18
=10^18:2/18
=(10:2)^18
=5^18
ta có 5^x+5^x+1+5^x+2 bé hoặc bằng 17
5^x.3+(1+2) bé hoặc bằng 17
suy ra ta có: 3.x bé hoặc bằng 14
suy ra x= 0;1;2;3;4
t i c k cho mình nha bạn