a) 47 – [(45.24 – 52.12):14] b) 50 – [(20 – 23) : 2 + 34] c) 102 – [60 : (56 : 54 – 3.5)] d) 50 – [(50 – 23.5):2 + 3] e) 10 – [(82 – 48).5 + (23.10 + 8)] : 28 f) 8697 – [37 : 35 + 2(13 – 3)] g) 2011 + 5[300 – (17 – 7)2] h) 695 – [200 + (11 – 1)2] i) 129 – 5[29 – (6 – 1)2] |
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a, 75 + 58.50 – 58.25 = 3.25 + 58.(50 – 25) = 3.25 + 58.25 = 25.(3+58) = 25.61 = 1525
Ta có: 1525 = 5 2 . 61
b, 20: 2 2 – 5 9 : 5 8 = 20:4 – 5 = 5 – 5 = 0
c, 5 19 : 5 17 - 4 : 7 = 5 2 - 4 : 7 = (25 – 4):7 = 3
d, 47 - 45 . 2 4 - 5 2 . 12 : 14 = 47 – (45.16 – 25.12):14 = 47 – (720 – 300):14 = 47 – 420:14 = 47 – 30 = 17
e, 10 2 : 60 : 5 6 : 5 4 - 3 . 5 = 100 – 60: 5 2 - 15 = 100 – 60:(25 – 15) = 100 – 60:10 = 100 – 6 = 94
Ta có: 94 = 2.47
f, 2345 - 1000 : 19 - 2 21 - 18 2 = 2345 – 1000:(19 – 2. 3 2 ) = 2345 – 1000:(19 – 2.9) = 2345 – 1000:(19 – 18) = 2345 – 1000:1 = 2345 – 1000 = 1345
Ta có: 1345 = 3.269
g, 500 – {5.[409 – 2 3 . 3 - 21 2 ]+ 10 3 }:15 = 500 – {5.[409 – 8 . 3 - 21 2 ]+1000}:15 = 500 – {5.[409 – 3 2 ]+1000}:15 = 500 – {5.(409 – 9)+1000}:15 = 500 – {5.400+1000}:15 = 500 – (2000+1000):15 = 500 – 3000:15 = 500 – 200 = 300
Ta có: 300 = 2 2 . 3 . 5 2
h, 967 – [8 + 2 . 3 2 – 24:6 + 9 - 7 3 ].5 = 967 – [8+2.9 – 4+8].5 = 967 – 30.5 = 967 – 150 = 817
Ta có: 817 = 19.43
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a) 17. 85 + 15 . 17 = 300
= 17. 9 85 = 15) + 300
= 2000
b) 72. 121 + 27 .121 = 121
= 121 . ( 72 + 27 = 1)
= 12100
c) 32. 39 + 52 . 21 - 12 . 39 + 21 . 48
= ( 32 - 12).39 + 21. ( 52 + 48)
= 2880
d) 47 - ( 45.24 - 52.12) : 14
= 47 - ( 45 . 16 - 25.12) : 14
= 17
e) 102 - 60 : ( 54 : 52 - 3. 5)
= 100 - 60 : ( 25 - 15)
= 100 - 6
= 94
a,47-[(45×16-25×12):14]
=47-[(720-300):14]
=47-[420:14]
=47-30
=17
b,50-[(20-8):2+34]
=50-[12:2+34]
=50-[6+34]
=50-40
=10
c,100-[60:(5^2-15)]
=100-[60÷(25-15)]
=100-[60÷10]
=100-6
=94
d,50-[(50-8×5)÷2+3]
=50-[(50-40)÷2+3]
=50-[10÷2+3]
=50-[5+3]
=50-8
=42
e,10-[(64-48).5+(8×10+8)]÷28
=10-[16.5+(80+8)]÷28
=10-[80+88]÷28
=10-168÷28
=10-6
=4
( bạn tự viết đầu bài nhé)
a,47-[(45×16-25×12):14]
=47-[(720-300):14]
=47-[420:14]
=47-30
=17
b,50-[(20-8):2+34]
=50-[12:2+34]
=50-[6+34]
=50-40
=10
c,100-[60:(5^2-15)]
=100-[60÷(25-15)]
=100-[60÷10]
=100-6
=94
d,50-[(50-8×5)÷2+3]
=50-[(50-40)÷2+3]
=50-[10÷2+3]
=50-[5+3]
=50-8
=42
e,10-[(64-48).5+(8×10+8)]÷28
=10-[16.5+(80+8)]÷28
=10-[80+88]÷28
=10-168÷28
=10-6
=4
\(a)47-\left[\left(45.2^4-5^2.12\right):14\right]\)
\(=47-\left[\left(45.16-25.12\right):14\right]\)
\(=47-\left[\left(720-300\right):14\right]\)
\(=47-\left[420:14\right]\)
\(=47-30\)
\(=17\)
\(b)50-\left[\left(20-2^3\right):2+34\right]\)
\(=50-\left[\left(20-8\right)\right]:2+34\)
\(=50-\left[12:2+34\right]\)
\(=50-\left[6+34\right]\)
\(=50-40\)
\(=10\)
\(c)10^2-\left[60:\left(5^6:5^4-3,5\right)\right]\)
\(=10^2-\left[60:\left(5^2-3,5\right)\right]\)
\(=10^2-\left[60:\left(25-3,5\right)\right]\)
\(=10^2-\left[60:21,5\right]\)
\(=100-\dfrac{120}{43}\)
\(=\dfrac{4180}{43}\)
\(d)50-\left[\left(50-2^3.5\right):2+3\right]\)
\(=50-\left[\left(50-8.5\right):2+3\right]\)
\(=50-\left[\left(50-40\right):2+3\right]\)
\(=50-\left[10:2+3\right]\)
\(=50-5+3\)
\(=50-8\)
\(=42\)
\(e)10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]:28\)
\(=10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[16.5+\left(80+8\right)\right]:28\)
\(=10-\left[80+88\right]:28\)
\(=10-168:28\)
\(=10-6\)
\(=4\)
\(f)8697-\left[3^7:3^5+2.\left(13-3\right)\right]\)
\(=8697-\left[3^2+2.\left(13-3\right)\right]\)
\(=8697-\left[9+2.10\right]\)
\(=8697-9+20\)
\(=8697-29\)
\(=8668\)
\(g)2011+5\left[300-\left(17-7\right)^2\right]\)
\(=2011+5.\left[300-10^2\right]\)
\(=2011+5.\left[300-100\right]\)
\(=2011+5.200\)
\(=2011+1000\)
\(=3011\)
\(h)695-\left[200+\left(11-1\right)^2\right]\)
\(=695-\left[200+10^2\right]\)
\(=695-200+100\)
\(=695-300\)
\(=395\)
\(i)129-5\left[29-\left(6-1\right)^2\right]\)
\(=129-5\left[29-5^2\right]\)
\(=129-5\left[29-25\right]\)
\(=129-5.4\)
\(=129-20\)
\(=109\)
help me