1. 2$\dfrac{1}{3}$x $8\dfrac{2}{3}$= $3\dfrac{1}{3}$ 2. $\dfrac{1}{3}$ |x - 2|- $\dfrac{3}{7}$= $\dfrac{4}{5}$ 3. Cho M = $\dfrac{1}{2}$.$\dfrac{3}{4}$.$\dfrac{5}{6}$.......\(\df...

TL

Trần Linh Chi

19 tháng 4 2017

1. 2$\dfrac{1}{3}$x + $8\dfrac{2}{3}$= $3\dfrac{1}{3}$ 2. $\dfrac{1}{3}$ |x - 2|- $\dfrac{3}{7}$= $\dfrac{4}{5}$ 3. Cho M = $\dfrac{1}{2}$.$\dfrac{3}{4}$.$\dfrac{5}{6}$.......$\dfrac{99}{100}$và N = $\dfrac{100}{101}$. Tính tích M.N ? Giải hộ minh nhé...

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#Toán lớp 6

1

NL

Nguyễn Lê Phước Thịnh

15 tháng 5 2022

1: =>7/3x=3+1/3-8-2/3=-5-1/3=-16/3

=>x=-16/3:7/3=-7/16

2: =>1/3|x-2|=4/5+3/7=28/35+15/35=43/35

=>|x-2|=129/35

=>x-2=129/35 hoặc x-2=-129/35

=>x=199/35 hoặc x=-59/35

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NT

Nguyet Tran

21 tháng 4 2022

...

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#Toán lớp 4

2

NT

Nguyet Tran

21 tháng 4 2022

ét ô ét

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NM

Nguyễn Minh Dương

12 tháng 11 2022

a.25/27 b.0 c.0

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TT

Thu Trang Đinh Thị

11 tháng 7 2023 - olm

1,$\dfrac{3}{16}$- ( x - $\dfrac{5}{4}$ ) - ( $\dfrac{3}{4}$ + $\dfrac{-7}{8}$ - 1 ) = $2\dfrac{1}{2}$ 2,$\dfrac{1}{2}$ . ( $\dfrac{1}{6}$ - $\dfrac{9}{10}$ ) = $\dfrac{1}{5}$ - x + ( $\dfrac{1}{15}$ - $\dfrac{-1}{5}$ ) Giúp mik nhanh với ạ...

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#Toán lớp 7

2

NT

Nguyễn Thị Thương Hoài

Giáo viên VIP

11 tháng 7 2023

$\dfrac{3}{16}$ - ($x$ - $\dfrac{5}{4}$) - ( $\dfrac{3}{4}$ - $\dfrac{7}{8}$ - 1) = 2$\dfrac{1}{2}$

$\dfrac{3}{16}$ - $x$ + $\dfrac{5}{4}$ - $\dfrac{3}{4}$ + $\dfrac{7}{8}$ + 1 = $\dfrac{5}{2}$

$\dfrac{3}{16}$ - $x$ + ( $\dfrac{5}{4}$ - $\dfrac{3}{4}$) + ($\dfrac{7}{8}$ + 1) = $\dfrac{5}{2}$

$\dfrac{3}{16}$ - $x$ + $\dfrac{1}{2}$ + $\dfrac{15}{8}$ = $\dfrac{5}{2}$

( $\dfrac{3}{16}$ + $\dfrac{1}{2}$ + $\dfrac{15}{8}$) - $x$ = $\dfrac{5}{2}$

$\dfrac{41}{16}$ - $x$ = $\dfrac{5}{2}$

$x$ = $\dfrac{41}{16}$ - $\dfrac{5}{2}$

$x$ = $\dfrac{1}{16}$

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NT

Nguyễn Thị Thương Hoài

Giáo viên VIP

11 tháng 7 2023

2, $\dfrac{1}{2}$.( $\dfrac{1}{6}$ - $\dfrac{9}{10}$) = $\dfrac{1}{5}$ - $x$ + ( $\dfrac{1}{15}$ - $\dfrac{-1}{5}$)

$\dfrac{1}{2}$.(-$\dfrac{11}{15}$) = $\dfrac{1}{5}$ - $x$ + $\dfrac{1}{15}$ + $\dfrac{1}{5}$

- $\dfrac{11}{30}$ = ( $\dfrac{1}{5}$+ $\dfrac{1}{5}$+ $\dfrac{1}{15}$) - $x$

- $\dfrac{11}{30}$ = $\dfrac{7}{15}$ - $x$

$x$ = $\dfrac{7}{15}$ + $\dfrac{11}{30}$

$x$ = $\dfrac{5}{6}$

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NH

Nguyễn Hà Nội

5 tháng 3 2022

tìm x

$x-\dfrac{1}{2}=\dfrac{3}{4}$

$x+\dfrac{7}{8}=\dfrac{3}{4}$

$\dfrac{1}{2}.x-\dfrac{1}{4}=\dfrac{-1}{2}$

$\dfrac{1}{2}-\dfrac{5}{6}:x=\dfrac{2}{3}$

#Toán lớp 6

1

O

★彡✿ทợท彡★

5 tháng 3 2022

$x-\dfrac{1}{2}=\dfrac{3}{4}$

$x=\dfrac{3}{4}+\dfrac{1}{2}$

$x=\dfrac{5}{4}$

$x+\dfrac{7}{8}=\dfrac{3}{4}$

$x=\dfrac{3}{4}-\dfrac{7}{8}$

$x=\dfrac{-1}{8}$

$\dfrac{1}{2}\cdot x-\dfrac{1}{4}=\dfrac{-1}{2}$

$\dfrac{1}{2}\cdot x=\dfrac{-1}{2}+\dfrac{1}{4}$

$\dfrac{1}{2}\cdot x=\dfrac{-1}{4}$

$x=\dfrac{-1}{4}\div\dfrac{1}{2}$

$x=\dfrac{-1}{2}$

Câu D ko bt

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HT

Hoàng Thúy An

8 tháng 9 2017

tìm x

$\dfrac{5}{3}x-2\dfrac{1}{3}=-\dfrac{4}{3}.1\dfrac{1}{8}-\dfrac{2}{3}$

$2\dfrac{1}{6}:x-\dfrac{-5}{8}=\dfrac{-7}{15}:4\dfrac{1}{5}-\dfrac{-6}{7}$

$\left(\dfrac{5}{6}x-0,3\right):2\dfrac{1}{3}=25\%$

$\dfrac{4}{7}-\dfrac{2}{3}x=1,5+\dfrac{4}{5}x$

GIÚP MÌNH NHÉ

#Toán lớp 6

2

TT

thám tử

8 tháng 9 2017

a.$\dfrac{5}{3}x-2\dfrac{1}{3}=-\dfrac{4}{3}.1\dfrac{1}{8}-\dfrac{2}{3}$

$\dfrac{5}{3}x-2\dfrac{1}{3}=\dfrac{5}{6}$

$\dfrac{5}{3}x=\dfrac{5}{6}+2\dfrac{1}{3}$

$\dfrac{5}{3}x=\dfrac{19}{6}$

$x=\dfrac{19}{5}:\dfrac{5}{3}$

$x=\dfrac{19}{10}$

b. $2\dfrac{1}{6}:x-\dfrac{-5}{8}=\dfrac{-7}{15}:4\dfrac{1}{5}-\dfrac{-6}{7}$

$2\dfrac{1}{6}:x+\dfrac{5}{8}=\dfrac{47}{63}$

$2\dfrac{1}{6}:x=\dfrac{47}{63}-\dfrac{5}{8}$

$2\dfrac{1}{6}:x=\dfrac{61}{504}$

$x=2\dfrac{1}{6}:\dfrac{61}{504}$

$x=\dfrac{1092}{61}$

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DH

Đức Hiếu

8 tháng 9 2017

a, $\dfrac{5}{3}x-2\dfrac{1}{3}=-\dfrac{4}{3}.1\dfrac{1}{8}-\dfrac{2}{3}$

$\Rightarrow\dfrac{5}{3}x=-\dfrac{3}{2}-\dfrac{2}{3}+2\dfrac{1}{3}=-\dfrac{3}{2}+2=\dfrac{1}{2}$

$\Rightarrow x=\dfrac{1}{2}:\dfrac{5}{3}=\dfrac{3}{10}$

b, $2\dfrac{1}{6}:x-\dfrac{-5}{8}=\dfrac{-7}{15}:4\dfrac{1}{5}-\dfrac{-6}{7}$

$\Rightarrow\dfrac{13}{6}:x=-\dfrac{7}{15}:\dfrac{21}{5}+\dfrac{6}{7}-\dfrac{5}{8}$

$\Rightarrow\dfrac{13}{6}:x=\dfrac{61}{504}\Rightarrow x=\dfrac{1092}{61}$

c, $\left(\dfrac{5}{6}x-0,3\right):2\dfrac{1}{3}=25\%$

$\Rightarrow\dfrac{5}{6}x-0,3=\dfrac{1}{4}.\dfrac{7}{3}$

$\Rightarrow\dfrac{5}{6}x=\dfrac{7}{12}+0,3=\dfrac{53}{60}$

$\Rightarrow x=\dfrac{53}{60}:\dfrac{5}{6}=1,06$

d, $\dfrac{4}{7}-\dfrac{2}{3}x=1,5+\dfrac{4}{5}x$

$\Rightarrow\dfrac{4}{5}x+\dfrac{2}{3}x=\dfrac{4}{7}-1,5$

$\Rightarrow\dfrac{22}{15}x=-\dfrac{13}{14}\Rightarrow x=-\dfrac{195}{308}$

Chúc bạn học tốt!!!

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HA

Hoài An

20 tháng 2 2021

k) 8 - $\dfrac{x-2}{2}$ = $\dfrac{x}{4}$m) $\dfrac{3x+2}{2}$ - $\dfrac{3x+1}{6}$ = 2x + $\dfrac{5}{3}$n) $\dfrac{x+1}{7}$+ $\dfrac{x+2}{6}$ = $\dfrac{x+3}{5}$ + $\dfrac{x+4}{4}$o) $\dfrac{x+5}{6}$ + $\dfrac{x+6}{5}$ = x +...

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#Toán lớp 8

3

NT

Nguyễn Thành Trương

20 tháng 2 2021

$\begin{array}{l} n) \Leftrightarrow \dfrac{{x + 1}}{7} + 1 + \dfrac{{x + 2}}{6} + 1 = \dfrac{{x + 3}}{5} + 1 + \dfrac{{x + 4}}{4} + 1\\ \Leftrightarrow \dfrac{{x + 8}}{7} + \dfrac{{x + 8}}{6} - \dfrac{{x + 8}}{5} - \dfrac{{x + 8}}{4} = 0\\ \Leftrightarrow \left( {x + 8} \right)\underbrace {\left( {\dfrac{1}{7} + \dfrac{1}{8} - \dfrac{1}{5} - \dfrac{1}{6}} \right)}_{ < 0} = 0\\ \Leftrightarrow x + 8 = 0\\ \Leftrightarrow x = - 8 \end{array}$

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TM

Trần Mạnh

20 tháng 2 2021

k/

$8-\dfrac{x-2}{3}=\dfrac{x}{4}$

$\Leftrightarrow\dfrac{96}{12}-\dfrac{4\left(x-2\right)}{12}=\dfrac{3x}{12}$

$\Leftrightarrow96-4x+8=3x$

$\Leftrightarrow96-4x+8-3x=0$

$\Leftrightarrow104-7x=0$

$\Leftrightarrow7x=104$

$\Leftrightarrow x=104:7$

$\Leftrightarrow x=\dfrac{104}{7}$

Vậy tập nghiệm của phương trình là $S=\left\{\dfrac{104}{7}\right\}$

m/

$\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=2x+\dfrac{5}{3}$

$\Leftrightarrow\dfrac{3\left(3x+2\right)}{6}-\dfrac{3x+1}{6}=\dfrac{12x}{6}+\dfrac{10}{6}$

$\Leftrightarrow9x+6-3x-1-12x-10=0$

$\Leftrightarrow-6x-5=0$

$\Leftrightarrow-6x=5$

$\Leftrightarrow x=-\dfrac{5}{6}$

Vậy tập nghiệm của phương trình là $S=\left\{-\dfrac{5}{6}\right\}$

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C

chuche

1 tháng 10 2021

3$\dfrac{1}{3}$+$\dfrac{5}{6}$ 4$\dfrac{5}{7}$-2$\dfrac{11}{21}$ 3$\dfrac{1}{4}$x$\dfrac{2}{5}$ 4$\dfrac{7}{8}$:$\dfrac{1}{4}$

#Toán lớp 5

1

TN

Tử Nguyệt Hàn

1 tháng 10 2021

$3\dfrac{1}{3}+\dfrac{5}{6}=\dfrac{10}{3}+\dfrac{5}{6}=\dfrac{20}{6}+\dfrac{5}{6}=\dfrac{25}{6}$
$4\dfrac{5}{7}-2\dfrac{11}{21}=\dfrac{33}{7}-\dfrac{53}{21}=\dfrac{99}{21}-\dfrac{53}{21}=\dfrac{46}{21}$
$3\dfrac{1}{4}x\dfrac{2}{5}=\dfrac{13}{3}x\dfrac{2}{5}=\dfrac{26}{15}$
$4\dfrac{7}{8}:\dfrac{1}{4}=\dfrac{39}{8}.4=\dfrac{39}{2}$

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C

chuche

1 tháng 10 2021

mơn nha cậu

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HQ

Hạ Quỳnh

20 tháng 12 2020

Bài 2:Tìm x...

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#Toán lớp 6

1

NL

Nguyễn Lê Phước Thịnh

20 tháng 12 2020

a) Ta có: $\dfrac{1}{7}+x=-\dfrac{2}{3}$

$\Leftrightarrow x=-\dfrac{2}{3}-\dfrac{1}{7}=\dfrac{-14}{21}-\dfrac{3}{21}$

hay $x=-\dfrac{17}{21}$

Vậy: $x=-\dfrac{17}{21}$

b) Ta có: $\dfrac{-2}{3}:x=\dfrac{-5}{6}$

$\Leftrightarrow x=\dfrac{-2}{3}:\dfrac{-5}{6}=\dfrac{-2}{3}\cdot\dfrac{6}{-5}=\dfrac{-12}{-15}=\dfrac{4}{5}$

Vậy: $x=\dfrac{4}{5}$

c) Ta có: $\left(\dfrac{3}{5}-2x\right)\cdot\dfrac{5}{8}=1$

$\Leftrightarrow\left(\dfrac{3}{5}-2x\right)=1:\dfrac{5}{8}=\dfrac{8}{5}$

$\Leftrightarrow-2x=\dfrac{8}{5}-\dfrac{3}{5}=1$

hay $x=-\dfrac{1}{2}$

Vậy: $x=-\dfrac{1}{2}$

d) Ta có: $\dfrac{3}{4}+\dfrac{2}{5}x=\dfrac{29}{60}$

$\Leftrightarrow x\cdot\dfrac{2}{5}=\dfrac{29}{60}-\dfrac{3}{4}=\dfrac{29}{60}-\dfrac{45}{60}=\dfrac{-16}{60}=\dfrac{-4}{15}$

hay $x=\dfrac{-4}{15}:\dfrac{2}{5}=\dfrac{-4}{15}\cdot\dfrac{5}{2}=\dfrac{-20}{30}=-\dfrac{2}{3}$

Vậy: $x=-\dfrac{2}{3}$

e) Ta có: $\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}$

$\Leftrightarrow\dfrac{1}{4}:x=\dfrac{2}{5}-\dfrac{3}{4}=\dfrac{8}{20}-\dfrac{15}{20}=\dfrac{-7}{20}$

hay $x=-\dfrac{1}{4}:\dfrac{7}{20}=\dfrac{-1}{4}\cdot\dfrac{20}{7}=\dfrac{-20}{28}=\dfrac{-5}{7}$

Vậy: $x=-\dfrac{5}{7}$

f) Ta có: $\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}$

$\Leftrightarrow-x+\dfrac{11}{12}-\dfrac{2}{5}-\dfrac{2}{3}=0$

$\Leftrightarrow-x+\dfrac{55}{60}-\dfrac{24}{60}-\dfrac{40}{60}=0$

$\Leftrightarrow-x-\dfrac{9}{60}=0$

$\Leftrightarrow-x=\dfrac{9}{60}=\dfrac{3}{20}$

hay $x=-\dfrac{3}{20}$

Vậy: $x=-\dfrac{3}{20}$

g) Ta có: $\left|x+\dfrac{1}{3}\right|-4=\dfrac{-1}{2}$

$\Leftrightarrow\left|x+\dfrac{1}{3}\right|=\dfrac{-1}{2}+4=\dfrac{-1}{2}+\dfrac{8}{2}=\dfrac{7}{2}$

$\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=\dfrac{7}{2}\\x+\dfrac{1}{3}=-\dfrac{7}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}-\dfrac{1}{3}=\dfrac{21}{6}-\dfrac{2}{6}=\dfrac{19}{6}\\x=-\dfrac{7}{2}-\dfrac{1}{3}=\dfrac{-21}{6}-\dfrac{2}{6}=\dfrac{-23}{6}\end{matrix}\right.$

Vậy: $x\in\left\{\dfrac{19}{6};-\dfrac{23}{6}\right\}$

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HQ

Hạ Quỳnh

20 tháng 12 2020

cảm ơn cậu cutee gì đó ơi nha

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LH

Lưu huỳnh ngọc

11 tháng 8 2021

1/ $\dfrac{5x+1}{8}-\dfrac{x-2}{4}=\dfrac{1}{2}$

2/ $\dfrac{x+3}{4}+\dfrac{1-3x}{3}=\dfrac{-x+1}{18}$

3/ $\dfrac{x+2}{4}-\dfrac{5x}{6}=\dfrac{1-x}{3}$

4/ $\dfrac{x-3}{2}-\dfrac{x+1}{10}=\dfrac{x-2}{5}$

5/ $\dfrac{4x+1}{4}-\dfrac{9x-5}{12}+\dfrac{x-2}{3}=0$

#Toán lớp 8

2

NL

Nguyễn Lê Phước Thịnh

11 tháng 8 2021

1: Ta có: $\dfrac{5x+1}{8}-\dfrac{x-2}{4}=\dfrac{1}{2}$

$\Leftrightarrow5x+1-2\left(x-2\right)=4$

$\Leftrightarrow5x+1-2x+4=4$

$\Leftrightarrow3x=-1$

hay $x=-\dfrac{1}{3}$

2: Ta có: $\dfrac{x+3}{4}+\dfrac{1-3x}{3}=\dfrac{-x+1}{18}$

$\Leftrightarrow9x+27+12-36x=-2x+2$

$\Leftrightarrow-27x+2x=2-39$

hay $x=\dfrac{37}{25}$

3: Ta có: $\dfrac{x+2}{4}-\dfrac{5x}{6}=\dfrac{1-x}{3}$

$\Leftrightarrow3x+6-10x=4-4x$

$\Leftrightarrow-7x+4x=4-6=-2$

hay $x=\dfrac{2}{3}$

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NL

Nguyễn Lê Phước Thịnh

11 tháng 8 2021

4: Ta có: $\dfrac{x-3}{2}-\dfrac{x+1}{10}=\dfrac{x-2}{5}$

$\Leftrightarrow5x-15-x-1=2x-4$

$\Leftrightarrow4x-2x=-4+16=12$

hay x=6

5: Ta có: $\dfrac{4x+1}{4}-\dfrac{9x-5}{12}+\dfrac{x-2}{3}=0$

$\Leftrightarrow12x+3-9x+5+4x-8=0$

$\Leftrightarrow7x=0$

hay x=0

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TD

Thầy Đức Anh

Giáo viên VIP

27 tháng 4 2022 - olm

Tìm $x$, biết :
a) $\left(\dfrac{1}{2}+1,5\right) \cdot x=\dfrac{1}{5}$
b) $\left(-1 \dfrac{3}{5}+x\right): \dfrac{12}{13}=2 \dfrac{1}{6}$
c) $\left(x: 2 \dfrac{1}{3}\right) \cdot \dfrac{1}{7}=\dfrac{-3}{8}$
d) $\dfrac{-4}{7} \cdot x+\dfrac{7}{5}=\dfrac{1}{8}:\left(-1 \dfrac{2}{3}\right)$

#Toán lớp 7

13

YN

Yen Nhi

21 tháng 6 2022

$a)\left(\dfrac{1}{2}+1,5\right)x=\dfrac{1}{5}$

$\Rightarrow2x=\dfrac{1}{5}$

$\Rightarrow x=\dfrac{1}{10}$

$b)\left(-1\dfrac{3}{5}+x\right):\dfrac{12}{13}=2\dfrac{1}{6}$

$\Leftrightarrow-\dfrac{8}{5}+x=\dfrac{13}{6}.\dfrac{12}{13}$

$\Leftrightarrow-\dfrac{8}{5}+x=2$

$\Leftrightarrow x=\dfrac{18}{5}$

$c)\left(x:2\dfrac{1}{3}\right).\dfrac{1}{7}=-\dfrac{3}{8}$

$\Leftrightarrow x:\dfrac{7}{3}=-\dfrac{3}{8}:\dfrac{1}{7}$

$\Leftrightarrow x=-\dfrac{21}{8}.\dfrac{7}{3}$

$\Leftrightarrow x=-\dfrac{49}{8}$

$d)-\dfrac{4}{7}x+\dfrac{7}{5}=\dfrac{1}{8}:\left(-1\dfrac{2}{3}\right)$

$\Leftrightarrow-\dfrac{4}{7}x+\dfrac{7}{5}=-\dfrac{3}{40}$

$\Leftrightarrow-\dfrac{4}{7}x=-\dfrac{59}{40}$

$\Leftrightarrow x=\dfrac{413}{160}$

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T

TINH

13 tháng 7 2022

a) $\left(\dfrac{1}{2}+1,5\right) \cdot x=\dfrac{1}{5}$

$\cdot x=\dfrac{1}{5}$

$x=\dfrac{1}{5}: 2$

$x=\dfrac{1}{10}$
b) $\left(-1 \dfrac{3}{5}+x\right): \dfrac{12}{13}=2 \dfrac{1}{6}$

$\dfrac{3}{5}+x=\dfrac{13}{6} \cdot \dfrac{12}{13}$
$\dfrac{3}{5}$

$\dfrac{3}{5}$
c) $\left(x: 2 \dfrac{1}{3}\right) \cdot \dfrac{1}{7}=\dfrac{-3}{8}$

$\cdot \dfrac{3}{7} \cdot \dfrac{1}{7}=\dfrac{-3}{8}$

$x=\dfrac{-3}{8}: \dfrac{3}{49}$
$x=\dfrac{-49}{8}=-6 \dfrac{1}{8}$
d) $\dfrac{-4}{7} \cdot x+\dfrac{7}{5}=\dfrac{1}{8}:\left(-1 \dfrac{2}{3}\right)$

$\dfrac{-4}{7} x+\dfrac{7}{5}=\dfrac{1}{8} \cdot \dfrac{-3}{5}$
$-\dfrac{4}{7} x=\dfrac{-3}{40}-\dfrac{7}{5} \\ x=\dfrac{-59}{40}: \dfrac{-4}{7}=\dfrac{413}{160}=2 \dfrac{93}{160}$