Tìm x, biết
\(0,5x-\dfrac{2}{3}x=\dfrac{5}{12}\)
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a: =>3/2x=64/15
=>x=128/45
b: =>-1/6x=7/12
=>x=-7/2
c: =>11/2*x=1/2
=>x=1/2:11/2=1/11
a, \(\dfrac{x}{12}-\dfrac{5}{6}=\dfrac{1}{12}\)
\(\Rightarrow\dfrac{x}{12}=\dfrac{1}{12}+\dfrac{5}{6}\)
\(\Rightarrow\dfrac{x}{12}=\dfrac{11}{12}\)
\(\Rightarrow x=11\)
b, \(\dfrac{2}{3}-1\dfrac{4}{15}x=\dfrac{-3}{5}\)
\(\Rightarrow\dfrac{2}{3}-\dfrac{19}{15}x=\dfrac{-3}{5}\)
\(\Rightarrow\dfrac{19}{15}x=\dfrac{2}{3}+\dfrac{3}{5}\)
\(\Rightarrow\dfrac{19}{15}x=\dfrac{19}{15}\)
\(\Rightarrow x=1\)
c, \(-2^3+0,5x=1,5\)
\(\Rightarrow-8+\dfrac{1}{2}x=\dfrac{3}{2}\)
\(\Rightarrow\dfrac{1}{2}x=\dfrac{3}{2}+8\)
\(\Rightarrow\dfrac{1}{2}x=\dfrac{19}{2}\)
\(\Rightarrow x=19\)
1) \(\dfrac{x}{12}-\dfrac{5}{6}=\dfrac{1}{12}\) 2)\(\dfrac{2}{3}-1\dfrac{4}{15}x=\dfrac{-3}{5}\) \(\dfrac{x}{12}=\dfrac{1}{12}+\dfrac{5}{6}\) \(\dfrac{2}{3}-\dfrac{19}{15}x=\dfrac{-3}{5}\) \(\dfrac{x}{12}=\dfrac{11}{12}\) \(\dfrac{19}{15}x=\dfrac{2}{3}-\left(\dfrac{-3}{5}\right)\) => \(x=11\) \(\dfrac{19}{15}x=\dfrac{19}{15}\) => \(x=1\) 3) -23 + 0,5x = 1,5 -8 + 0,5x = 1,5 0,5x = 1,5 - (-8) 0,5x = 9,5 x = 9,5 : 0,5 x = 19
=>1/2:(0,5x-1,5)=0,2-0,35=-0,15=-3/20
=>0,5x-1,5=1/2:(-3/20)=-1/2*20/3=-10/3
=>0,5x=-10/3+3/2=-11/6
=>x=-11/3
\(\dfrac{5}{4}+\left(2x-\dfrac{1}{2}\right)=\dfrac{5}{6}\\ =>2x-\dfrac{1}{2}=\dfrac{5}{6}-\dfrac{5}{4}\\ =>2x-\dfrac{1}{2}=\dfrac{10}{12}-\dfrac{15}{12}\\ =>2x-\dfrac{1}{2}=-\dfrac{5}{12}\\ =>2x=-\dfrac{5}{12}+\dfrac{1}{2}\\ =>2x=-\dfrac{5}{12}+\dfrac{6}{12}\\ =>2x=\dfrac{1}{12}\\ =>x=\dfrac{1}{12}:2\\ =>x=\dfrac{1}{12}\cdot\dfrac{1}{2}\\ =>x=\dfrac{1}{24}\)
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\(\dfrac{3}{2}-\left(x+\dfrac{1}{4}\right)=\dfrac{5}{8}\\ =>x+\dfrac{1}{4}=\dfrac{3}{2}-\dfrac{5}{8}\\ =>x+\dfrac{1}{4}=\dfrac{12}{8}-\dfrac{5}{8}\\ =>x+\dfrac{1}{4}=\dfrac{7}{8}\\ =>x=\dfrac{7}{8}-\dfrac{1}{4}\\ =>x=\dfrac{7}{8}-\dfrac{2}{8}\\ =>x=\dfrac{5}{8}\)
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\(\dfrac{x}{3}=\dfrac{12}{x}\\ =>x^2=3\cdot12\\ =>x^2=36\\ =>x^2=6^2\\ =>x=\pm6\)
Tìm x:
a) \(\dfrac{5}{4}+\left(2x-\dfrac{1}{2}\right)=\dfrac{5}{6}\)
\(=>2x-\dfrac{1}{2}=\dfrac{5}{6}-\dfrac{5}{4}\)
\(=>2x-\dfrac{1}{2}=\dfrac{-5}{12}\)
\(=>2x=\dfrac{-5}{12}+\dfrac{1}{2}\)
\(=>2x=\dfrac{1}{12}\)
\(=>x=\dfrac{1}{12}:2\)
\(=>x=\dfrac{1}{24}\)
b) \(\dfrac{3}{2}-\left(x+\dfrac{1}{4}\right)=\dfrac{5}{8}\)
\(=>x+\dfrac{1}{4}=\dfrac{3}{2}-\dfrac{5}{8}\)
\(=>x+\dfrac{1}{4}=\dfrac{7}{8}\)
\(=>x=\dfrac{7}{8}-\dfrac{1}{4}\)
\(=>x=\dfrac{5}{8}\)
c) \(\dfrac{x}{3}=\dfrac{12}{x}\)
Ta có: \(x.x=3.12\)
\(\Rightarrow x^2=36\)
Vậy x = 6 hoặc x = -6
Chúc bạn học tốt
Bài 1 :
\(=\dfrac{2}{11}+\dfrac{4}{11}-\dfrac{6}{11}-\dfrac{3}{8}-\dfrac{5}{8}=0-1=-1\)
Bài 2 :
\(\Rightarrow3+x=8\Leftrightarrow x=5\)
Bài 3 :
\(\Leftrightarrow x-\dfrac{5}{11}=\dfrac{5}{4}\Leftrightarrow x=\dfrac{35}{44}\)
Bài 4 :
Trong 2 ngày An đọc được số quyên phần quyên sách
\(\dfrac{1}{11}+\dfrac{8}{11}=\dfrac{9}{11}\)( quyển sách )
đs : 9/11 quyển sách
=>0,2x+0,4-0,5x=0,25-0,5x+0,25
=>0,2x+0,4=0,5
=>0,2x=0,1
=>x=1/2
Ta có :
\(0,5\times x-\dfrac{2}{3}\times x=\dfrac{5}{12}\)
\(\Rightarrow\dfrac{1}{2}\times x-\dfrac{2}{3}\times x=\dfrac{5}{12}\)
\(\Rightarrow x\times\left(\dfrac{1}{2}-\dfrac{2}{3}\right)=\dfrac{5}{12}\)
\(\Rightarrow x\times\dfrac{-1}{6}=\dfrac{5}{12}\)
\(\Rightarrow x=\dfrac{-5}{2}\)
Vậy \(x=\dfrac{-5}{2}\) là giá trj cần tìm
~ Chúc bn học tốt ~
Tìm x:
a, x+30%=-1,3
<=> x+0,3=-1,3
<=> x=-1,3-0,3
<=> x=-1,6
Vậy x=-1,6
b, 0,5x-\(\dfrac{2}{3}x\) =\(\dfrac{7}{12}\)
<=>\(\dfrac{-1}{6}x\)=\(\dfrac{7}{12}\)
<=> x=\(\dfrac{-7}{2}\)
Vậy x=\(\dfrac{-7}{2}\)
\(0,5x-\dfrac{2}{3}x=\dfrac{5}{12}\)
\(\Rightarrow\dfrac{1}{2}x-\dfrac{2}{3}x=\dfrac{5}{12}\)
\(\Rightarrow x\left(\dfrac{1}{2}-\dfrac{2}{3}\right)=\dfrac{5}{12}\)
\(\Rightarrow x\dfrac{-1}{6}=\dfrac{5}{12}\)
\(\Rightarrow x=\dfrac{-5}{2}\)
Vậy .......
Ta có: 0,5x-\(\dfrac{2}{3}\)x =\(\dfrac{5}{12}\)
\(\Leftrightarrow\) \(x\left(0,5-\dfrac{2}{3}\right)=\dfrac{5}{12}\)
\(\Leftrightarrow-\dfrac{1}{6}x =\dfrac{5}{12}\)
\(\Leftrightarrow x=-\dfrac{5}{2}\)
Sao dốt thế