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\(2x\left(x-\frac{1}{7}\right)=0\)
\(\Rightarrow x=0\) (hoặc) \(x-\frac{1}{7}=0\)
\(\Rightarrow\) x = 0 hoặc x = \(\frac{1}{7}\)
a)\(\frac{11}{12}-\left(\frac{2}{5}+x\right)=\frac{2}{3}\)
<=>\(\frac{11}{12}-\frac{2}{5}-x=\frac{2}{3}\)
<=>\(-x=\frac{2}{3}-\frac{11}{12}+\frac{2}{5}\)
<=>\(-x=\frac{3}{20}\)
<=>\(x=-\frac{3}{20}\)
b)\(2x\left(x-\frac{1}{7}\right)=0\)
<=>2x=0 hoặc \(x-\frac{1}{7}=0\)
<=>x=0 hoặc x=\(\frac{1}{7}\)
c)\(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)
<=>\(\frac{1}{4}:x=\frac{2}{5}-\frac{3}{4}\)
<=>\(\frac{1}{4}:x=-\frac{7}{20}\)
<=>\(x=\frac{1}{4}:\left(-\frac{7}{20}\right)\)
<=>\(x=-\frac{5}{7}\)
1. 2/5 + x= 11/12 - 2/5
=> x= 31/60 - 2/5
=> x= 7/60
Vậy x= 7/60
2. 2x(x - 1/7)= 0
TH1: x=0
TH2: x= 0 + 1/7 = 1/7
Vậy x= 0 hoặc 1/7
3. 1/4 : x= 2/5 - 3/4
=> x= 1/4 : (-7/20)
=> x= -5/7
Vậy x= -5/7
1) \(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)
\(\Leftrightarrow\dfrac{11}{12}-\dfrac{2}{5}-x=\dfrac{2}{3}\)
\(\Leftrightarrow x=\dfrac{11}{12}-\dfrac{2}{5}-\dfrac{2}{3}\)
\(\Leftrightarrow x=-\dfrac{3}{20}\)
2) \(2x\left(x-\dfrac{1}{7}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2x=0\\x-\dfrac{1}{7}=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)
3) \(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
\(\Leftrightarrow\dfrac{1}{4x}=\dfrac{2}{5}-\dfrac{3}{4}\)
\(\Leftrightarrow\dfrac{1}{4x}=-\dfrac{7}{20}\)
\(\Leftrightarrow4x=-\dfrac{20}{7}\)
\(\Leftrightarrow x=-\dfrac{5}{7}\)
2x(x - 1/7) = 0
<=> 2x = 0 hoặc x - 1/7 = 0
<=> x = 0 hoặc x = 1/7