3:4x8:2-2+8x2
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Bài 2:
b: \(=\left(x^2+x+4+3x\right)\left(x^2+x+4+5x\right)\)
\(=\left(x^2+4x+4\right)\left(x^2+6x+4\right)\)
\(=\left(x+2\right)^2\cdot\left(x^2+6x+4\right)\)
c: \(=25x^2-49y^2-\left(5x+7y\right)\)
=(5x+7y)(5x-7y-1)
d: \(8x^3-36x^2+54x-27=\left(2x-3\right)^3\)
\(\left(x-2\right)^3+\left(x+2\right)^3-x^3-8x^2+10\)
\(=x^3-6x^2+12x-8+x^3+6x^2+12x+8-x^3-8x^2+10\)
\(=x^3-2x^2+24x+10\)
\(\frac{3}{4}\cdot\frac{8}{5}\cdot\frac{5}{9}=\frac{2}{3}\)
\(\frac{3}{7}:\frac{3}{14}:\frac{1}{2}=4\)
\(\dfrac{7}{2}\times\dfrac{3}{4}+\dfrac{17}{8}\times\dfrac{2}{3}+\dfrac{3}{4}\times\dfrac{1}{2}+\dfrac{7}{8}\times\dfrac{3}{3}\)
\(=\dfrac{7\times3}{2\times4}+\dfrac{17\times2}{8\times3}+\dfrac{3\times1}{4\times2}+\dfrac{7}{8}\times1\)
\(=\dfrac{21}{8}+\dfrac{17}{12}+\dfrac{3}{8}+\dfrac{7}{8}\)
\(=\left(\dfrac{21}{8}+\dfrac{3}{8}+\dfrac{7}{8}\right)+\dfrac{17}{12}\)
\(=\dfrac{31}{8}+\dfrac{17}{12}\)
\(=\dfrac{31\times3}{8\times3}+\dfrac{17\times2}{12\times2}\)
\(=\dfrac{93}{24}+\dfrac{34}{24}\)
\(=\dfrac{127}{24}\)
Thu gọn và sắp xếp phải k ạ?
`F(x)= (x^4-x^4)+(5x^2-8x^2)-4x+x^5+3+2x^3+2`
`F(x) = -3x^2-4x+x^5+3+2x^3+2`
`F(x)= x^5+2x^3-3x^2-4x+3+2`
\(F\left(x\right)=x^4+5x^2-4x+x^5-x^4-8x^2+3+2x^3+2\)
\(F\left(x\right)=x^5+\left(x^4-x^4\right)+2x^3+\left(5x^2-8x^2\right)-4x+\left(3+2\right)\)
\(F\left(x\right)=x^5+2x^3-3x^2-4x+5\)
\(\text{Sửa đề : }A=\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+...+\frac{2}{292\times294}\)
\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{292}-\frac{1}{294}\)
\(=\frac{1}{2}-\frac{1}{294}\)
\(=\frac{73}{147}\)
\(\text{Vậy }A=\frac{73}{147}\)
= 17
**** cho mk nha
3:4x8:2-2+8x2=17