tim x (5-2x)^2-16=0 mn giup e vs ak <3
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\(3\left(x-1\right)^2-3x\left(x-5\right)=1\)
\(\Leftrightarrow\)\(3x^2-6x+3-3x^2+15x=1\)
\(\Leftrightarrow\)\(9x=-2\)
\(\Leftrightarrow\)\(x=-\frac{2}{9}\)
Vậy...
\(x^2-2x+1=25\)
\(\Leftrightarrow\)\(x^2-2x-24=0\)
\(\Leftrightarrow\)\(\left(x+4\right)\left(x-6\right)=0\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x+4=0\\x-6=0\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=-4\\x=6\end{cases}}\)
Vậy...
\(x^2-2x+1=25\)
\(\Leftrightarrow\)\(\left(x+1\right)^2=25\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x+1=5\\x+1=-5\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=4\\x=-6\end{cases}}\)
Vậy...
\(3\left(x-1\right)^2-3x\left(x-5\right)=1\)
\(\Leftrightarrow\)\(3\left(x^2-2x+1\right)-\left(3x^2-15x\right)=1\)
\(\Leftrightarrow\)\(3x^2-6x+3-3x^2+15x=1\)
\(\Leftrightarrow\)\(9x=-2\)
\(\Leftrightarrow\)\(x=-\frac{2}{9}\)
Vậy....
\(x^2-2x+1=25\)
\(\Leftrightarrow\)\(\left(x-1\right)^2=25\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x-1=5\\x-1=-5\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=6\\x=-4\end{cases}}\)
Vậy....
b) \(3\left(x-1\right)^2-3x\left(x-5\right)=1\)
\(\Leftrightarrow\)\(3x^2-6x+3-3x^2+15x=1\)
\(\Leftrightarrow\)\(9x=-2\)
\(\Leftrightarrow\)\(x=-\frac{2}{9}\)
Vậy...
\(5\left(x+2\right)-x^2-2x=0\)
\(\Rightarrow5\left(x+2\right)-\left(x^2+2x\right)=0\)
\(\Rightarrow5\left(x+2\right)-x\left(x+2\right)=0\)
\(\Rightarrow\left(5-x\right)\left(x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}5-x=0\\x+2=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=5\\x=-2\end{cases}}\)
\(x\left(2-y\right)-y+2-2=5\)
\(\left(2-y\right)\left(x+1\right)=7\)
⇒ (x+1) và (2-y) ϵ {-1;1;-7;7}
⇒ (x;y) ϵ {(-2;5);(0;-5);(-8;3);(6;1)}
\(\left(2x+1\right)\left(x-5\right)=2x^2-9x-5=2\left(x^2-\frac{9}{2}x+\frac{81}{16}\right)-\frac{121}{8}=2\left(x-\frac{9}{4}\right)^2-\frac{121}{8}\ge-\frac{121}{8} \)
Vậy GTNN của biểu thức là \(-\frac{121}{8}\)khi x = \(\frac{9}{4}\)
a) =2x - 3 =0
x = 3/2
b) (5x -1)2 = 0
5x - 1 = 0
x = 1/5
c) = ( x +3)2 = 0
x+3 = 0
x = -3
d) =(13+y)(13-y) = 0
y = 13; -13
e) xem lại đề bài này
25 – 2x = 16 – 3x
-2x + 3x = 16 - 25
x = -9
Vậy x = -9
x - (47 - 22 ) = 5 + (10-4x)
x - 47 + 22 = 5 + 10 - 4x
x + 4x = 5 + 10 - 22 + 47
5x = 40
x = 40 : 5
x = 8
Vậy x = 8.
~ HOK TỐT ~
\(\text{25 – 2x = 16 – 3x}\)
\(2x+3x=16-25\)
\(5x=-9\)
\(\Rightarrow x=\frac{-9}{5}\)
\(\text{d) x – (47 – 22) = 5+ (10 – 4x)}\)
\(x-47+22=5+10-4x\)
\(x+4x=5+10-22+47\)
\(5x=40\)
\(\Rightarrow x=8\)
học tốt
\(\left(5-2x\right)^2-16=0\)
\(\Leftrightarrow\left(5-2x\right)^2-4^2=0\)
\(\Rightarrow\left(5-2x-4\right)\left(5-2x+4\right)=0\)
\(\Rightarrow\orbr{\begin{cases}5-2x-4=0\\5-2x+4=0\end{cases}\Leftrightarrow\orbr{\begin{cases}-2x=4-5\\-2x=-4-5\end{cases}}\Leftrightarrow\orbr{\begin{cases}-2x=-1\\-2x=-9\end{cases}}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{-1}{-2}=\frac{1}{2}\\x=\frac{-9}{-2}=\frac{9}{2}\end{cases}}\)
Vậy ................................
= 5^2 - 2.5.2x + (2x)\(^2\)- 16 = 0
=> x = 4,5