( x - 2018)mũ 3 = ( x -2018 ) mũ 2
tim x nha moi nguoi.
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\(x^3=13\times2+2018^0\)
\(\Rightarrow x^3=13\times2+1\)
\(\Rightarrow x^3=27\)
Mà ta thấy 33 = 27
=> x3 = 33
Vậy x = 3
(x-5)^2018>=0
y+1)^2018>=0
=>(x-5)^2018+(y+1)^2018>=0
dấu = xảy ra <=>x=5;y=-1
\(2^{x-3}=128\Leftrightarrow2^{x-3}=2^7\Rightarrow x-3=7\Leftrightarrow x=10\)
\(\left(x+6\right)^4=4096\Leftrightarrow\left(x+6\right)^4=2^{12}=\left(2^3\right)^4=8^4\Rightarrow x+6=8\Leftrightarrow x=2\)
\(2^{2018}=\left(2^4\right)^{504}.2^2==16^{504}.4< 16^{900}\\ \)
\(17^{20}>16^{20}=\left(4^2\right)^{20}=4^{40}\)
\(3^{444}=\left(3^4\right)^{111}=81^{111}>64^{111}=\left(4^3\right)^{111}=4^{333}\\ \)
\(\left(x+1\right)^3=27\)
\(\left(x+1\right)^3=3^3\)
\(\Rightarrow x+1=3\)
\(x=2\)
\(\left(x+1\right)^3=27\)
\(< =>\left(x+1\right)^3=3.3.3=3^3\)
\(< =>x+1=3< =>x=3-1=2\)
\(\left(2x+3\right)^3=9.81\)
\(< =>\left(2x+3\right)^3=9.9.9\)
\(< =>\left(2x+3\right)^3=9^3\)
\(< =>2x+3=9< =>2x=6\)
\(< =>x=\frac{6}{2}=3\)
Ta có:
\(\left(x-2018\right)^3=\left(x-2018\right)^2\)
\(\Rightarrow\left(x-2018\right)^2.\left(x-2018\right)=\left(x-2018\right)^2\)
\(\Rightarrow x-2018=1\)
\(\Rightarrow x=2019\)
\(\left(x-2018\right)^3=\left(x-2018\right)^2\)
\(\Rightarrow\left(x-2018\right)^3-\left(x-2018\right)^2=0\)
\(\Rightarrow\left(x-2018\right)^2\left[\left(x-2018\right)-1\right]=0\)
\(\Rightarrow\orbr{\begin{cases}x-2018=0\\x-2018=1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2018\\x=2019\end{cases}}\)