A = 290 - 18 X 1 + 567 : 17
B = 1/7 x 3 va 1/11 - 1/7 x 9/11 -1/7
tim a va b
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Trả lời:
A = 290 - 18 + 567 : 27
A = 290 - 18 + 21
A = 272 + 21
A = 293
B = 1/7 x 31/11 - 1/7 x 9/11 - 1/7
B = 1/7 x ( 31/11 - 9/11 ) - 1/7
B = 1/7 x 2/1 - 1/7
B = 2/7 - 1/7
B = 1/7
CHÚC BẠN HỌC TỐT!!!!
a=290-18+567:27
a=290-18+21
a=272+21
a=293
b=1/7×31/11-1/7×9/11-1/7
b=1/7×(31/11-9/11-1)
b=1/7×1
b=1/7
mình cũng đang làm câu đó nghĩ ra rồi nhưng ko biết có đúng ko
1:
a: =8/7-5/88=669/616
b: \(=1+\dfrac{2}{9}\cdot\dfrac{3}{7}-\dfrac{10}{7}=1+\dfrac{2}{21}-\dfrac{10}{7}\)
\(=\dfrac{21+2-30}{21}=\dfrac{-7}{21}=\dfrac{-1}{3}\)
c: \(=\dfrac{11}{3}-\dfrac{6}{7}+4=\dfrac{77-18+84}{21}=\dfrac{143}{21}\)
Bài 2:
a: =>9/4-x=5/11*2=10/11
=>x=9/4-10/11=59/44
b: =>2/9:x=19/21
=>x=2/9:19/21=14/57
1.
b) \(3^x+3^{x+2}=2430\)
\(\Rightarrow3^x.1+3^x.3^2=2430\)
\(\Rightarrow3^x.\left(1+3^2\right)=2430\)
\(\Rightarrow3^x.10=2430\)
\(\Rightarrow3^x=2430:10\)
\(\Rightarrow3^x=243\)
\(\Rightarrow3^x=3^5\)
\(\Rightarrow x=5\)
Vậy \(x=5.\)
c) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\Rightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)
\(\Rightarrow\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\)
\(\Rightarrow\left[{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15\right)^2=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=15\\2x-15=\pm1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=15:2\\2x-15=1\\2x-15=-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{15}{2}\\2x=16\\2x=14\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{15}{2}\\x=8\\x=7\end{matrix}\right.\)
Vậy \(x\in\left\{\frac{15}{2};8;7\right\}.\)
Chúc bạn học tốt!
a.-1,75-(-\(\dfrac{1}{9}\)-2\(\dfrac{1}{8}\))
-1,75-\(\dfrac{1}{9}+\dfrac{17}{8}\)
\(-\dfrac{7}{4}-\dfrac{1}{9}+\dfrac{17}{8}\)
\(\dfrac{-126}{72}-\dfrac{8}{72}+\dfrac{153}{72}\)
=\(\dfrac{19}{72}\)
b.\(\dfrac{-1}{12}-\left(2\dfrac{5}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\left(\dfrac{21}{8}-\dfrac{1}{3}\right)\)
\(\dfrac{-1}{12}-\dfrac{21}{8}+\dfrac{1}{3}\)
\(\dfrac{-2}{24}-\dfrac{63}{24}+\dfrac{64}{24}\)
=\(\dfrac{-1}{24}\)
a)
\(\frac{x}{18}=\frac{y}{15},x-y=-30\)
\(\frac{x}{18}=\frac{y}{15}\)
\(\frac{x}{18}-\frac{y}{15}=0\)
\(-\frac{6y-5x}{90}=0\)
\(6y-5x=0\)
\(x-y=-30\)
\(-\left(y-x-30\right)=0\)
\(y-x-30=0\)
\(\Rightarrow x=-180;y=-150\)
\(A=290-18\times1+567:17\)
\(A=290-18+\frac{567}{17}\)
\(A=272+\frac{567}{17}\)
\(A=\frac{4624}{17}+\frac{567}{17}\)
\(A=\frac{5191}{17}\).
\(B=\frac{1}{7}\times3\frac{1}{11}-\frac{1}{7}\times\frac{9}{11}-\frac{1}{7}\)
\(B=\frac{1}{7}\times\frac{34}{11}-\frac{1}{7}\times\frac{9}{11}-\frac{1}{7}\)
\(B=\left(\frac{34}{11}-\frac{9}{11}-1\right)\times\frac{1}{7}\)
\(B=\left(\frac{25}{11}-1\right)\times\frac{1}{7}\)
\(B=\frac{14}{11}\times\frac{1}{7}\)
\(B=\frac{87}{77}\)
Chúc bạn hok tốt !