tính C= \(9.\left(\frac{13-\frac{13}{7}-\frac{13}{289}}{4-\frac{4}{7}-\frac{4}{289}}:\frac{39+\frac{39}{5}+\frac{39}{139}+\frac{39}{31}}{16+\frac{16}{5}+\frac{16}{139}+\frac{16}{31}}\right).\frac{158158}{164164}\)
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HQ
Hà Quang Minh
Giáo viên
18 tháng 9 2023
\(\begin{array}{l}a)\frac{{17}}{{11}} - \left( {\frac{6}{5} - \frac{{16}}{{11}}} \right) + \frac{{26}}{5}\\ = \frac{{17}}{{11}} - \frac{6}{5} + \frac{{16}}{{11}} + \frac{{26}}{5}\\ = (\frac{{17}}{{11}} + \frac{{16}}{{11}}) + (\frac{{26}}{5} - \frac{6}{5})\\ = \frac{{33}}{{11}} + \frac{{20}}{5}\\ = 3 + 4\\ = 7\\b)\frac{{39}}{5} + \left( {\frac{9}{4} - \frac{9}{5}} \right) - \left( {\frac{5}{4} + \frac{6}{7}} \right)\\ = \frac{{39}}{5} + \frac{9}{4} - \frac{9}{5} - \frac{5}{4} - \frac{6}{7}\\ = (\frac{{39}}{5} - \frac{9}{5}) + (\frac{9}{4} - \frac{5}{4}) - \frac{6}{7}\\ = \frac{{30}}{5} + \frac{4}{4} - \frac{6}{7}\\ = 6 + 1 - \frac{6}{7}\\ = 7 - \frac{6}{7}\\ = \frac{{49}}{7} - \frac{6}{7}\\ = \frac{{43}}{7}\end{array}\)
D
25 tháng 5 2020
a)(1/4+3/4)-(5/13+8/13)+2/11=1-1+2/11=2/11
b)(21/31+10/31)-16/7+(44/53+9/53)=1+1-16/7=14/7-16/7=-2/7
25 tháng 8 2020
15: Tính
a) Ta có: \(\frac{3^6\cdot45^4-15^{13}\cdot5^{-9}}{27^4\cdot25^3+45^6}\)
\(=\frac{3^6\cdot3^4\cdot15^4-15^{13}\cdot\frac{1}{5^9}}{9^4\cdot3^4\cdot5^6+9^6\cdot5^6}\)
\(=\frac{3^6\cdot45^4-\frac{5^{13}\cdot3^{13}}{5^9}}{9^4\cdot5^6\left(3^4+9^2\right)}\)
\(=\frac{45^4\cdot3^6-5^4\cdot3^{13}}{45^4\cdot5^2\cdot2\cdot9^2}\)
\(=\frac{5^4\cdot3^6\left(9^4-3^7\right)}{5^2\cdot3^4\cdot45^4\cdot2}\)
\(=\frac{5^2\cdot3^2\cdot\left(3^8-3^7\right)}{45^4\cdot2}\)
\(=\frac{5^2\cdot3^9\cdot\left(3-1\right)}{5^4\cdot3^8\cdot2}\)
\(=\frac{1}{5^2}\cdot3\)
\(=\frac{3}{25}\)
\(C=9\cdot\left(\frac{\frac{26299}{2023}-\frac{3757}{2023}-\frac{91}{2023}}{\frac{8092}{2023}-\frac{1156}{2023}-\frac{28}{2023}}\right):\left(\frac{\frac{840255}{21545}+\frac{168051}{21545}+\frac{6045}{21545}+\frac{27105}{21545}}{\frac{344720}{21545}+\frac{68944}{21545}+\frac{2480}{21545}+\frac{11120}{21545}}\right)\cdot\frac{158158}{164164}\)
\(C=9\cdot\left(\frac{\frac{22451}{2023}}{\frac{6908}{2023}}\div\frac{\frac{1041456}{21545}}{\frac{427264}{21545}}\right)\cdot\frac{158158}{164164}\)
\(C=9\cdot\left(\frac{13}{4}\div\frac{39}{16}\right)\cdot\frac{158158}{164164}\)
\(C=9\cdot\frac{4}{3}\cdot\frac{2\cdot79\cdot2\cdot79}{2\cdot82\cdot2\cdot82}=9\cdot\frac{4}{3}\cdot\frac{79}{82}\)
\(C=\frac{474}{41}\)