15/19<x<67/15+56/15
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Dễ mà:
Ta gộp phần từ "19-15+19-15+19-15+19-15+19-15+19-15+19-15+19-15+19-15+19-15+19-15"
Rồi bắt đầu tính:
19+19+(19-15 +19-15 +19-15+19-15+19-15+19-15+19-15+19-15+19-15+19-15).
=19x2+[(19-15)+(19-15)+(19-15)+(19-15)+(19-15)+(19-15)+(19-15)+(19-15)+(19-15)+(19-15)]
=38+(4+4+4+4+4+4+4+4+4+4)
có 10 số 4
=38+4x10
=38+40=78
19 + 19 - 15 + 19 - 15 + 19 - 15 + 19 - 15 + 19 - 15 + 19 - 15 + 19 - 15 + 19 - 15 + 19 - 15 + 19 - 15 + 19 = 78
\(A=\frac{15}{19}\left(\frac{17}{23}+\frac{19}{23}-\frac{13}{23}\right)=\frac{15}{19}\left(\frac{17+19-13}{23}\right)=\frac{15}{19}\cdot\frac{23}{23}=\frac{15}{19}.1=\frac{15}{19}\)
Bài 1
a: 8/15; 11/15; 15/15; 16/15; 17/15; 19/15
b: 19/42; 19/35; 19/21; 19/19; 19/17
c: 8/10<6/7<16/14<37/35
15/19 . 17/19 + 15/19 . 10/9 - (-7/19)
= 15/19 . (17/19 + 10/19) + 7/19
= 15/19 . 27/19 + 7/19
= 405/361 + 7/19
= 538/361
a)\(\dfrac{8}{15}< \dfrac{11}{15}< \dfrac{15}{15}< \dfrac{16}{15}< \dfrac{17}{15}< \dfrac{19}{15}\)
b)\(\dfrac{19}{42}< \dfrac{19}{35}< \dfrac{19}{21}< \dfrac{19}{19}< \dfrac{19}{17}\)
c)\(\dfrac{8}{10}< \dfrac{6}{7}< \dfrac{27}{25}< \dfrac{16}{14}\)
a) 8/15 ; 11/15 ; 15/15 ; 16/15 ; 17/15 ; 19/15
b) 19/42 19/35 ; 19/21 ; 19/19 ; 19/17
c) 8/10 ; 6/7 ; 27/25 ; 16/14
\(A=\frac{108}{199}\)x\(\left(\frac{107}{211}+\frac{104}{211}\right)\)
\(A=\frac{108}{199}\)x \(\frac{211}{211}\)
\(A=\frac{108}{199}\)x 1
\(A=\frac{108}{199}\)
\(B=\frac{15}{19}\)x \(\left(\frac{27}{33}+\frac{19}{33}-\frac{13}{33}\right)\)
\(B=\frac{15}{19}\)x\(1\)
\(B=\frac{15}{19}\)
\(\frac{19}{35}+\frac{15}{19}+\frac{16}{35}+\frac{23}{19}+\frac{4}{15}+\frac{11}{15}\)
\(=\left(\frac{19}{35}+\frac{16}{35}\right)+\left(\frac{15}{19}+\frac{23}{19}\right)+\left(\frac{4}{15}+\frac{11}{15}\right)\)
\(=\frac{35}{35}+\frac{38}{19}+\frac{15}{15}\)
\(=1+2+1\)
\(=4\)
\(\frac{19}{35}+\frac{15}{19}+\frac{16}{35}+\frac{23}{19}+\frac{4}{15}+\frac{11}{15}\)
\(=\left(\frac{19}{35}+\frac{16}{35}\right)+\left(\frac{15}{19}+\frac{23}{19}\right)+\left(\frac{4}{15}+\frac{11}{15}\right)\)
\(=1+2+1\)
\(=4\)
Học tốt
Ta có : \(A=\frac{19^{30}+15}{19^{31}+15}\)
\(\Rightarrow19A=\frac{19^{31}+285}{19^{31}+15}=\frac{19^{31}+15+270}{19^{31}+15}=1+\frac{270}{19^{31}+15}\)
Lại có \(B=\frac{19^{31}+15}{19^{32}+15}\)
\(\Rightarrow19B=\frac{19^{32}+285}{19^{32}+15}=\frac{19^{32}+15+270}{19^{32}+15}=1+\frac{270}{19^{32}+15}\)
Vì \(\frac{270}{19^{32}+15}< \frac{270}{19^{31}+15}\Rightarrow1+\frac{270}{19^{32}+5}< 1+\frac{270}{19^{31}+15}\Rightarrow19B< 19A\Rightarrow B< A\)
= (26/15-7/15):19/45
=\(\dfrac{19}{15}:\dfrac{19}{45}\)
=\(\dfrac{19}{15}x\dfrac{45}{19}=\dfrac{45}{15}=3\)