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a, -234-(123-234)
=-234-123+234
=(-234+234)-123
=0-123
-123
b, -24 . 33+ 40 . 24 +13 . 30 +13 . 46
= 24x(-33+40)+13(30+46)
=24.7+13.76
=98+988
=1086
c, 34 . (-84)+ 17 . (-32)
=34.(-84-16)
=34.-100
=-3400
a, -234-(123-234)
= -234-123+234
= (-234+234)-123
= 0-123
= -123
b, -24 . 33+ 40 . 24 +13 . 30 +13 . 46
= 24 . ( -33 ) + 40 . 24 + 13 . 30 + 13 . 46
= 24 . [ -33 + 40 ] + 13 . [ 30 + 46 ]
= 24 . 7 + 13 . 76
= 168 + 988
= 1156
a: \(\left(24-234\right)+\left(234-24-77\right)\)
\(=24-234+234-24-77\)
\(=\left(24-24\right)+\left(234-234\right)-77\)
=0+0-77
=-77
b: \(\left(13-135+49\right)-\left(13+49\right)\)
\(=13-135+49-13-49\)
\(=\left(13-13\right)+\left(49-49\right)-135\)
=0+0-135
=-135
c: \(159-524-\left(59-424\right)\)
\(=159-524-59+424\)
\(=\left(159-59\right)-\left(524-424\right)\)
=100-100
=0
d: \(\left(36+79\right)+\left(145-79-36\right)\)
\(=36+79+145-79-36\)
\(=\left(36-36\right)+\left(79-79\right)+145\)
=0+0+145
=145
e: \(334-\left(117+234\right)+\left(42+117\right)\)
\(=334-117-234+42+117\)
\(=\left(334-234\right)+\left(117-117\right)+42\)
=100+0+42
=142
f: \(271-\left[\left(-43\right)+271-\left(-17\right)\right]\)
\(=271+43-271+\left(-17\right)\)
\(=\left(271-271\right)+\left(43-17\right)\)
=0+26
=26
45-58+(-45)+(+58)-3=45-58-45+58-3=(45-45)+(58-58)-3=-3
(-57)-(-12)+3-(-57)=-57+12+3+57=(-57+57)+12+3=15
-(-24)-(-30)+(-24)-30+8=24+30-24-30+8=(24-24)+(30-30)+8=8
-(-12)+(+19)-(+12)+8-19=12+19-12+8-19=(12-12)+(19-19)+8=8
47-(-53)+(-47)-(+53)=47+53-47-53=(47-47)+(53-53)=0
-(+28)+32-(-28)+(-34)=-28+32+28-34=(-28+28)-(34-32)=-2
15-(+72)+(-15)+(+72)=15-72-15+72=(15-15)+(72-72)=0
20-(+46)+(-25)-(-46)=20-46-25+46=(20-25)+(46-46)=-5
28-(-32)+(-28)-32+5=28+32-28-32+5=(28-28)+(32-32)+5=5
-75+(-49)+(+75)+49-12=-75-49+75+49-12=(-75+75)+(49-49)-12=-12
\(...=45-58-45+58-3=-3\)
\(...=-57+12+3+57=15\)
\(...=24+30-24-30+8=8\)
\(...=12+19-12+8-19=8\)
\(...=47+53-47-53=0\)
\(...=-28+32+28-34=-2\)
\(...=15-72-15+72=0\)
\(...=20-46-25+46=-5\)
\(=...28+32-28-32+5=5\)
\(...=-75-49+75+49-12=-12\)
Có 16 = 2 4 ; 24 = 2 3 . 3 nên UCLN(16,24) = 2 3 = 8
Vậy UC(16,24) = {1;2;4;8}
b, Có 180 = 2 3 . 3 2 . 5 ; 234 = 2 . 3 2 . 13 nên UCLN(180,234) = 2.3 = 6
Vậy UC(180,234) = {1;2;3;6}
c, Có 60 = 2 2 . 3 . 5 ; 90 = 2 . 3 2 . 5 ; 135 = 3 3 . 5 nên UCLN(60,90,135) = 3.5 = 15
Vậy UC(60,90,135) = {1;3;5;15}
a) (-24) + 18 + 24 + (-28)
= (-24 + 24) + (18 - 28)
= 0 - 28
= -28
b) (-32) . 234 + 234
= 234 . (-32 + 1)
= 234 . (-31)
= -7254
a, (-24) + 18 + 24 +(-28)
= (-24) + 24 - (28 - 18)
= 0 - 10
= - 10
b, (-32) x 234 + 234
= - 234 x ( 32 - 1)
= -234 x 31
= - 7254