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xem lại đề hộ mk nhé
mk sửa đề thế này
x+ ( x+1)+(x+2)+....+(x+24)+(x+25) = 25
=> x+ x+1 + x + 2 +...+ x+ 24 + x + 25 = 25
=> 25x + 325 = 25
từ đây tính ra x
a: =>5(x+2)=170
=>x+2=34
=>x=32
b: =>x+2=5 hoặc x+2=-5
=>x=-7 hoặc x=3
c: =>x-2=1 hoặc x-2=-1
=>x=1 hoặc x=3
x + 25%x = \(\frac{1}{2}\)
x.1+\(\frac{1}{4}\)x = \(\frac{1}{2}\)
x.(\(1+\frac{1}{4}\)) = \(\frac{1}{2}\)
x . \(\frac{5}{4}\)= \(\frac{1}{2}\)
x = \(\frac{1}{2}\div\frac{5}{4}\)
x = \(\frac{2}{5}\)
Ta có : \(X+25\%.X=\frac{1}{2}\Leftrightarrow X+\frac{1}{4}.X=\frac{1}{2}\Leftrightarrow X.\left(1+\frac{1}{4}\right)=\frac{1}{2}\)\(\Leftrightarrow X.\frac{5}{4}=\frac{1}{2}\Leftrightarrow X=\frac{1}{2}:\frac{5}{4}\Leftrightarrow X=\frac{2}{5}\)
doi 25%=25/100=1/4
x=1/2+1/4*x
x=1/2+1/4
x=6/8=3/4
nho ****
\(a,25\%x=42,6-3,28\\ \Leftrightarrow\dfrac{1}{4}x=39,32\\ \Leftrightarrow x=157,28\)
\(b,x:40\%=7,25+6,75\\ \Leftrightarrow x:40\%=14\\ \Leftrightarrow x=5,6\)
\(c,\dfrac{7011}{25}:\left(x-42,6\right)=117,14-47,03\\ \Leftrightarrow\dfrac{7011}{25}:\left(x-42,6\right)=70,11\\ \Leftrightarrow x-42,6=4\\ \Leftrightarrow x=46,6\)
\(d,0,3\left(x+\dfrac{1}{3}\right)=\dfrac{1}{2}\cdot\left(0,81:27\right)\\ \Leftrightarrow0,3\left(x+\dfrac{1}{3}\right)=0,015\\ \Leftrightarrow x+\dfrac{1}{3}=0,05\\ \Leftrightarrow x=-\dfrac{17}{60}\)
1: =>x=8-35=-27
2: =>15-4+x=6
=>x+11=6
hay x=-5
3: =>-30+25-x=-1
=>x+5=1
hay x=-4
4: =>x-(-13)=-8
=>x+13=-8
hay x=-21
5: =>x-29-17+38=-9
=>x-8=-9
hay x=-1
\(x-25\%.x=\frac{1}{2}\)
\(x.1-25\%.x=\frac{1}{2}\)
\(x.\left(1-25\%\right)=\frac{1}{2}\)
\(x.\left(1-\frac{1}{4}\right)=\frac{1}{2}\)
\(x.\frac{3}{4}=\frac{1}{2}\)
\(x=\frac{1}{2}:\frac{3}{4}=\frac{1}{2}.\frac{4}{3}\)
\(x=\frac{2}{3}\)
\(\left(x+1\right)^2=25\)
\(\Rightarrow\left(x+1\right)^2=\left(\pm5\right)^2\)
\(\Rightarrow\left[{}\begin{matrix}x+1=5\\x+1=-5\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=5-1\\x=-5-1\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-6\end{matrix}\right.\)
\(\left(x+1\right)\cdot2=25\)
\(2x+2=25\)
\(2x=25-2=23\)
\(x=23:2=11,5\)