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( 48 x 0,75 - 240 : 10 ) - ( 16 x 0,5 - 16 : 4 )
= ( 36 - 24 ) - ( 8 - 4 )
= 12 - 4
= 8
#Donaa-Học tốt nha:3
=(2*24*0,75-24)-(4*4*0,5-4)=(1,5*24-24)-(2*4-4)=((1,5-1)*24)-((2-1)*4)=(0,5*24)-4=12-4=8
[Giải:]
107 + ( 210 + x ) = 317
210 + x = 317 - 107
210 + x = 210
x = 210 - 210
x = 0
2x + (0,5 + 25%) = 0,75
2x + (0,5 + 0,25) = 0,75
2x + 0,75 = 0,75
2x = 0,75 - 0,75
2x = 0
x = 0 : 2
x = 0
4221 : (x - 16 ) = 21
x - 16 = 4221 : 21
x - 16 = 201
x = 201 + 16
x = 217
50% + 0,75x = 0,5
0,5 + 0,75x = 0,5
0,75x = 0,5 - 0,5
0,75x = 0
x = 0 : 0,75
x = 0
| - Câu khác làm tương tự - |
[ Hoq chắc ]
a, 107 + ( 210 - x ) = 317
210 - x = 317 - 107
210 - x = 210
x = 210 - 210
x = 0
Vậy x = 0
b, 2x + ( 0,5 + 25% ) = 0,75
2x + 0,75 = 0,75
2x = 0,75 - 0,75
2x = 0
x = 0
Vậy x = 0
c, 4221 : ( x - 16 ) = 21
x - 16 = 4221 : 21
x - 16 = 201
x = 201 + 16
x = 217
Vậy x = 217
d, 156 - ( x + 61 ) = 21
x + 61 = 156 - 21
x + 61 = 135
x = 135 - 61
x = 74
Vậy x = 74
e, ( 235 - x ) - 81 = 54
235 - x = 54 + 81
235 - x = 135
x = 235 - 135
x = 100
Vậy x = 100
f, 50% + 0,75. x = 0,5
0,75. x = 0,5 - 50%
0,75. x = 0
x = 0
Vậy x = 0
a) \(\left(9^4.8+9^4.5\right):\left(9^2.\left(10-1\right)\right)\)
=\(9^4.13:9^3=13.9=117\)
b) 100-(75-25)=100-50=50
a) \(\frac{3x}{-4}=\frac{-9}{6}\)
=> \(\frac{-3x}{4}=\frac{-9}{6}\)
=> \(\frac{-3x}{4}=\frac{-3}{2}\)
=> \(\frac{-3x}{4}=\frac{-6}{4}\)
=> \(-3x=-6\)
=> \(x=\left(-6\right):\left(-3\right)=2\)
b) \(\frac{2}{x}=\frac{y}{10}=\frac{4}{-5}\)
=> \(\frac{2}{x}=\frac{y}{10}=\frac{-4}{5}\)
+) \(\frac{2}{x}=\frac{-4}{5}\)
=> \(\left(-4\right)\cdot x=2\cdot5\)
=> \(\left(-4\right)\cdot x=10\)
=> \(x=\frac{10}{-4}=\frac{-10}{4}=\frac{-5}{2}\)
+) \(\frac{y}{10}=\frac{-4}{5}\)
=> \(5\cdot y=-40\)
=> \(y=\left(-40\right):5=-8\)
Vậy \(x=-\frac{5}{2},y=-8\)
c) \(\frac{7}{-x}=\frac{5}{y}=\frac{2}{34}\)
=> \(\frac{-7}{x}=\frac{5}{y}=\frac{1}{17}\)
+) \(\frac{-7}{x}=\frac{1}{17}\Rightarrow x=\left(-7\right)\cdot17=-119\)
+) \(\frac{5}{y}=\frac{1}{17}\Rightarrow y=5\cdot17=85\)
Vậy \(x=-119,y=85\)
d) \(\frac{x^2}{4}=16\)
=> \(x^2=16\cdot4=64\)
=> \(x\in\left\{8;-8\right\}\)
e) \(\frac{3}{x^3}=\frac{4}{-36}\)
=> \(\frac{3}{x^3}=\frac{1}{-9}=\frac{-1}{9}\)
=> \(x^3=3:\left(-\frac{1}{9}\right)=-27\)
=> \(x=-3\)
Vậy x = -3
Đặt \(A=\frac{1.2+2.4+3.6+4.8+5.10}{4+6.8+9.12+12.16+15.20}\)
\(\Rightarrow A=\frac{1.\left(1+2\right)+2.\left(1+2\right)+3.\left(1+2\right)+4.\left(1+2\right)+5.\left(1+2\right)}{4+2.\left(3+4\right)+3.\left(3+4\right)+4.\left(3+4\right)+5.\left(3+4\right)}\)
\(\Rightarrow A=\frac{\left(1+2+3+4+5\right).\left(1+2\right)}{4+\left(2+3+4+5\right).\left(3+4\right)}\)
\(\Rightarrow A=\frac{\left(1+5\right).5:2.\left(1+2\right)}{4+\left(2+5\right).4:2.\left(3+4\right)}\)
\(\Rightarrow A=\frac{6.5:2.3}{4+7.4:2.7}=\frac{45}{4+98}=\frac{45}{102}=\frac{15}{34}\)
Vậy \(A=\frac{15}{34}\)
Chúc bn học tốt
\(\left(48.0,75-240:10\right)-\left(16.0,5-36:9\right)\)
\(=\left(48.\dfrac{3}{4}-24\right)-\left(16.\dfrac{1}{2}-4\right)=\left(36-24\right)-\left(8-4\right)=12-4=8\)
(36 - 24) - ( 8 - 4)
= 12 - 4
= 8