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\(1-\frac{7}{9}=\frac{9}{9}-\frac{7}{9}=\frac{2}{9}\)
\(\frac{7}{9}+\frac{9}{12}=\frac{28}{36}+\frac{27}{36}=\frac{55}{36}\)
\(12:\frac{2}{3}=12x\frac{3}{2}=\frac{36}{2}=18\)
\(\frac{9}{12}:3=\frac{9}{12}x\frac{1}{3}=\frac{9}{36}=\frac{1}{4}\)
a] 4/12 ; 5/12 ; 11/2 ; 1/4
b] 1 ; 9/12; 12/5 ; 11/3
c] 8/21; 6/11;8/7
d] 2/3 ;2/7 15/2
a]1/3 5/12 11/2 1/4
b]1 3/4 12/5 33/9
c]8/21 6/11 8/7
d]2/3 2/7 15/2
1.a,=(54+45+1).113
=100.113
=11300
b,=(3/7+8/14)+(4/9+10/18)
=1+1
=2
2.a,=13/10+1/3
=49/30
b,=12/9.(1/12+1/6)
=12/9.1/4
=1/3
c,=3/4.3/2
=9/8
d,=3/2-1/3
=7/6
1:tính bằng cách thuận tiện nhất:
a)54 x 113 + 45 x 113 + 113
= 54 x 113 + 45 x 113 + 113x1
=113 x(54+45+1)
= 113x100
=1300
b)3/7 + 4/9 + 8/14 + 10/18
=(3/7+8/14)+(4/9+10/18)
= 1 + 1
=2
a: =(21/11+12/11)-(9/19+3/19+6/19)=3-18/19=39/19
b: =(2/3+4/3)+(3/4+7/4)+(4/5+16/5)
=2+4+10/4
=6+5/2
=17/2
a: =7/12+6/36
=7/12+2/12=9/12=3/4
b: =8/9-2/3=8/9-6/9=2/9
c: \(=\dfrac{7\cdot2+5\cdot3}{18}\cdot\dfrac{3}{5}=\dfrac{29}{18}\cdot\dfrac{3}{5}=\dfrac{87}{90}=\dfrac{29}{30}\)
a) \(\dfrac{7}{12}+\dfrac{3}{4}\times\dfrac{2}{9}=\dfrac{7}{12}+\dfrac{6}{36}=\dfrac{7}{12}+\dfrac{2}{12}=\dfrac{9}{12}=\dfrac{3}{4}\)
b) \(\dfrac{8}{9}-\dfrac{4}{15}:\dfrac{2}{5}=\dfrac{8}{9}-\dfrac{4}{15}\times\dfrac{5}{2}=\dfrac{8}{9}-\dfrac{2}{3}=\dfrac{8}{9}-\dfrac{6}{9}=\dfrac{2}{9}\)
c) \(\left(\dfrac{7}{9}+\dfrac{5}{6}\right)\times\dfrac{3}{5}=\dfrac{29}{18}\times\dfrac{3}{5}=\dfrac{87}{90}=\dfrac{29}{30}\)
a: 4/3=32/24
5/8=15/24
b: 4/5=36/45
5/9=25/45
c: 4/9=16/36
7/12=21/36
d: 1/2=6/12
2/3=8/12
7/12=7/12
4/3 và 5/8
\(\dfrac{4}{3}=\dfrac{4x8}{3x8}=\dfrac{32}{24}\)
\(\dfrac{5}{8}=\dfrac{5x3}{8x3}=\dfrac{15}{24}\)
4/5 và 5/9
\(\dfrac{4}{5}=\dfrac{4x9}{5x9}=\dfrac{36}{45}\)
\(\dfrac{5}{9}=\dfrac{5x5}{9x5}=\dfrac{25}{45}\)
4/9 và 7/12
\(\dfrac{4}{9}=\dfrac{4x12}{9x12}=\dfrac{48}{108}\)
\(\dfrac{7}{12}=\dfrac{7x9}{12x9}=\dfrac{63}{108}\)
1/2 ; 2/3 và 7/12
\(\dfrac{1}{2}=\dfrac{1x6}{2x6}=\dfrac{6}{12}\)
\(\dfrac{2}{3}=\dfrac{2x4}{3x4}=\dfrac{8}{12}\)
\(\dfrac{7}{12}=\dfrac{7x1}{12x1}=\dfrac{7}{12}\)
1/12
\(\dfrac{9}{12}\) - \(\dfrac{2}{3}\) = \(\dfrac{9}{12}\) - \(\dfrac{8}{12}\) =\(\dfrac{1}{12}\)