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a,\(xy+3x-7y-21\)
\(=x\left(y+3\right)-7\left(y+3\right)\)
\(=\left(y+3\right)\left(x-7\right)\)
\(b,2xy-15-6x+5y\)
\(=\left(2xy-6x\right)+\left(-15+5y\right)\)
\(=2x\left(y-3\right)-5\left(3-y\right)\)
\(=2x\left(y-3\right)+5\left(y-3\right)\)
\(=\left(y-3\right)\left(2x+5\right)\)
a/ 5x2y - 2xy
= xy.(5x-2)
b/ x2 - 6x + 9
= x2 - 2.3.x + 32
= (x-3)2
c/ 8x3 - 27
= (2x)3 - 33
= (2x - 3).[(2x)2 - 2x.3 + 32]
= (2x-3).(4x2 - 6x + 9)
d/ x2 - 2x - 25y2 + 1
= (x2 - 2x + 1) - 25y2
= (x-1)2 - (5y)2
= (x-1-5y).(x-1+5y)
e/ 6x2 - x - 5
= 6x2 + 6x - 5x - 5
= 6x.(x+1) - 5.(x+1)
= (x+1).(6x-5)
f/ (2x -y).(x+3) - 5.(y-2x)
= (2x-y).(x+3) + 5.(2x-y)
= (2x-y).(x+3+5)
= (2x-y).(x+8)
g/ (x+y)2 - z2
= (x+y-z).(x+y+z)
k/ x3 - 4x2 + 4x
= x.(x2 - 4x + 4)
= x.(x2 - 2.x.2 + 22)
= x.(x-2)2
m/ 5x2 - x + y - 5y2
= 5x2 - 5y2 - (x-y)
= 5.(x2 - y2) - (x-y)
= 5.(x+y).(x-y) - (x-y)
= (x-y).[5(x+y) - 1]
i/ x2 + 9x - 10
= x2 - x + 10x - 10
= x.(x-1) + 10.(x-1)
= (x-1).(x+10)
a)5x2y-2xy=xy(5x-2)
b)x2-6x+9=x2-2.x.3+32=(x-3)2
c)8x3-27=(2x)3-33=(2x-3)(4x2+6x+9)
d)x2-2x-25y2+1=(x2-2x+1)-25y2=(x-1)2-25y2
=(x-1-5y)(x-1+5y)
e)6x2-x-5=6x2-6x+5x-5=(6x2-6x)+(5x-5)=6x(x-1)+5(x-1)=(x-1)(6x+5)
f)(2x-y)(x+3)-5(y-2x)=(2x-y)(x+3)-5(2x-y)=(2x-y)(x+3-5)=(2x-y)(x-2)
g)(x+y)2-z2=(x+y+z)(x+y-z)
k)x3-4x2+4x=x(x2-4x+4)=x(x-2)2
m)5x2-x+y-5y2=(5x2-5y2)-(x-y)=5(x2-y2)-(x-y)=5(x-y)(x+y)-(x-y)
=5(x-y)(x+y+1)
i)x2+9x-10=x2-x+10x-10=(x2-x)+(10x-10)=x(x-1)+10(x-1)=(x-1)(x+10)
a) \(x^6-y^6=\left(x^3\right)^2-\left(y^3\right)^2\)
\(=\left(x^3+y^3\right)\left(x^3-y^3\right)\)
\(=\left(x+y\right)\left(x-y\right)\left(x^2+xy+y^2\right)\left(x^2-xy+y^2\right)\)
b) sửa đề nhé!
\(6x-9-x^2=-\left(x^2-6x+9\right)\)
\(=-\left(x-3\right)^2\)
a) \(x^4-2x^2+1=\left(x^2-1\right)^2=\left(x-1\right)^2\left(x+1\right)^2\)
b) \(x^2-y^2-5x+5y=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)=\left(x-y\right)\left(x+y-5\right)\)
c) \(2x^3-x^2-8x+4\)
\(=x^2\left(2x-1\right)-4\left(2x-1\right)\)
\(=\left(x-1\right)\left(x+1\right)\left(2x-1\right)\)
d) \(x\left(x-y\right)^2+y\left(x-y\right)^2-xy+x^2\)
\(=\left(x+y\right)\left(x-y\right)^2+x\left(x-y\right)\)
\(=\left(x-y\right)\left(x^2-y^2+x\right)\)
e) \(2x^2-5x+2\)
\(=\left(2x^2-x\right)-\left(4x-2\right)\)
\(=x\left(2x-1\right)-2\left(2x-1\right)\)
\(=\left(x-2\right)\left(2x-1\right)\)
\(a,=x\left(x-2\right)\\ b,=2b\left(x-3y\right)+a\left(x-3y\right)=\left(a+2b\right)\left(x-3y\right)\\ c,=x\left(x^2+2xy+y^2-4\right)=x\left[\left(x+y\right)^2-4\right]=x\left(x+y+2\right)\left(x+y-2\right)\\ d,=4-\left(x+y\right)^2=\left(2-x-y\right)\left(2+x+y\right)\\ đ,=5\left(x-y\right)\left(x+y\right)+3\left(x+y\right)^2=\left(x+y\right)\left(5x-5y+3x+3y\right)\\ =\left(x+y\right)\left(8x-2y\right)=2\left(4x-y\right)\left(x+y\right)\\ e,=3x\left(2xy-3\right)\\ b,=x\left(4x^2-4xy+y^2-4\right)=x\left[\left(2x-y\right)^2-4\right]=x\left(2x-y-2\right)\left(2x-y+2\right)\\ f,=\left(x+y\right)^2-z^2=\left(x+y-z\right)\left(x+y+z\right)\)