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\(\frac{8,5-8,2}{16}\)=\(\frac{0,3}{16}\)= \(\frac{3}{160}\)=0,01875
\(\frac{11,4-11}{2-13}\)=\(\frac{0,4}{-11}\)=\(\frac{-2}{55}\)
học tốt
a. \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{3}{160}\)
b. \(\dfrac{2\cdot14}{7\cdot8}=\dfrac{1\cdot2}{1\cdot4}=\dfrac{2}{4}=\dfrac{1}{2}\)
c. \(\dfrac{11\cdot4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{1\cdot3}{-1}=-3\)
d. \(\dfrac{49+7\cdot49}{49}=\dfrac{49\cdot\left(1+7\right)}{49}=\dfrac{8}{1}=8\)
*Rút gọn :
`(8.5-8.2)/16=(8.(5-2))/(8.2)=(8.3)/(8.2)=3/2`
`(11.4-11)/(2-13)=(11.(4-1))/(-11)=(11.3)/(-1.11)=3/(-1)=-3`
*Quy đồng :
- Ta có : `-3=(-3)/1`
UCLN(2,1)=2
$\to\begin{cases} \dfrac32=\dfrac32\\\dfrac{-3}1=\dfrac{-6}2\end{cases}$
\(\dfrac{-63}{72}=\dfrac{-7}{8}\)
\(\dfrac{20}{-140}=\dfrac{-1}{7}\)
\(\dfrac{3.10}{5.24}=\dfrac{30}{120}=\dfrac{1}{4}\)
\(\dfrac{3.7.11}{22.9}=\dfrac{231}{198}=\dfrac{7}{6}\)
\(\dfrac{8.5-8.2}{16}=\dfrac{24}{16}=\dfrac{3}{2}\)
\(\dfrac{11.4-11}{2-13}=\dfrac{33}{-11}=-3\)
Giải:
h) \(\left(-\dfrac{1}{2}\right)^2.13\dfrac{9}{11}-25\%.6\dfrac{2}{11}\)
\(=\dfrac{1}{4}.\dfrac{152}{11}-\dfrac{1}{4}.\dfrac{68}{11}\)
\(=\dfrac{1}{4}\left(\dfrac{152}{11}-\dfrac{68}{11}\right)\)
\(=\dfrac{1}{4}.\dfrac{84}{11}=\dfrac{21}{11}\)
Vậy ...
i) \(57\%+1\dfrac{2}{15}:\dfrac{68}{25}-2,82\)
\(=\dfrac{57}{100}+\dfrac{17}{15}:\dfrac{68}{25}-\dfrac{141}{50}\)
\(=\dfrac{57}{100}+\dfrac{2}{15}-\dfrac{141}{50}\)
\(=\dfrac{-127}{60}\)
Vậy ...
h. \(\left(-\dfrac{1}{2}\right)^2\times13\dfrac{9}{11}-25\%\times6\dfrac{2}{11}\)
= \(\dfrac{1}{4}\times\dfrac{150}{11}-\dfrac{1}{4}\times34\)
= \(\dfrac{75}{22}-\dfrac{17}{2}\)
= \(\dfrac{75}{22}-\dfrac{187}{22}\)
= \(-\dfrac{56}{11}\)
i. \(57\%+1\dfrac{2}{15}\div\dfrac{68}{25}-2,82\)
= \(\dfrac{57}{100}+\dfrac{17}{15}\div\dfrac{68}{25}-\dfrac{282}{100}\)
= \(\dfrac{57}{100}+\dfrac{17}{15}\times\dfrac{25}{68}-\dfrac{282}{100}\)
= \(\dfrac{57}{100}+\dfrac{5}{3}-\dfrac{282}{100}\)
=\(\dfrac{5}{3}-\left(\dfrac{57}{100}-\dfrac{282}{100}\right)\)
= \(\dfrac{5}{3}-\left(-\dfrac{215}{100}\right)\)
= \(\dfrac{5}{3}-\left(-\dfrac{43}{20}\right)\)
= \(\dfrac{5}{3}+\dfrac{43}{30}\)
= \(\dfrac{50}{30}+\dfrac{43}{30}\)
= \(\dfrac{31}{10}\)
\(\dfrac{\dfrac{3}{7}-\dfrac{3}{11}+\dfrac{3}{13}}{\dfrac{5}{7}-\dfrac{5}{11}+\dfrac{5}{13}}+\dfrac{\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{4}}{\dfrac{5}{4}-\dfrac{5}{6}+\dfrac{5}{8}}\)
\(=\dfrac{3\left(\dfrac{1}{7}-\dfrac{1}{11}+\dfrac{1}{13}\right)}{5\left(\dfrac{1}{7}-\dfrac{1}{11}+\dfrac{1}{13}\right)}+\dfrac{2(\dfrac{1}{4}-\dfrac{1}{6}+\dfrac{1}{8})}{5\left(\dfrac{1}{4}-\dfrac{1}{6}+\dfrac{1}{8}\right)}\)
\(=\dfrac{3}{5}+\dfrac{2}{5}\)
\(=1\)
Ta có: \(\dfrac{8.5-8.2}{16}=\dfrac{8\left(5-2\right)}{16}=\dfrac{8.3}{16}=\dfrac{3}{2}\)
\(\dfrac{11.4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{11.3}{-11}=-3\)