520:(515.6+515.19)
718:716+22.33
59.73-302+27.59
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\(151-2^{91}:2^{88}+1^2\cdot3\\ =151-2^{91-88}+3\\ =154-2^3\\ =154-8\\ =146\)
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\(2^{38}:2^{36}+5^1\cdot3^2-7^2\\ =2^{38-36}+5\cdot9-49\\ =2^2+45-49\\ =4-4\\ =0\)
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\(7^{91}:7^{89}+5\cdot5^2-124\\ =7^{91-89}+5^3-124\\ =7^2+125-124\\ =49+1\\ =50\)
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\(4\cdot15+28:7-6^{20}:6^{18}\\ =60+4-6^{20-18}\\ =64-6^2\\ =64-36\\ =28\)
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\(\left(3^2+2^3\cdot5\right):7\\ =\left(9+8\cdot5\right):7\\ =\left(9+40\right):7\\ =49:7\\ =7\)
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\(11^{25}:11^{23}-3^5:\left(1^{10}+2^3\right)-60\\ =11^{25-23}-3^5:\left(1+8\right)-60\\ =11^2-3^5:9-60\\ =121-3^5:3^2-60\\ =61-3^3\\ 61-27\\ =34\)
\(a)71-\left(33+x\right)=26\\ 33+x=71-26=45\\ x=45-33\\ x=12\\ b)97-\left(64-x\right)=44\\ 64-x=97-44\\ 64-x=53\\ x=64-53\\ x=11\\ c)x-36:18=12\\ x-2=12\\ x=2+12\\ x=14\\ d)3636:\left(12\cdot x-91\right)=36\\ 12\cdot x-91=3636:36\\ 12\cdot x-91=101\\ 12\cdot x=101+91\\ 12\cdot x=192\\ x=\dfrac{192}{12}\\ x=16\\ e)\left(x:23+45\right)\cdot67=8911\\ x:23+45=8911:67\\ x:23+45=133\\ x:23=133-45=88\\ x=88\cdot23\\ x=2024\)
Con coi châu Phi nặng 6 125 kg
Con hươu cao cổ nặng 1 687 kg
Con tê giác trắng nặng 2 287 kg
\(x^2\) + 6\(x\) + 9 = 25
\(x^2\) + 6\(x\) + 9 - 25 = 0
\(x^2\) + 6\(x\) + (9 - 25) = 0
\(x^2\) + 6\(x\) - 16 = 0
\(x^2\) - 2\(x\) + 8\(x\) - 16 = 0
(\(x^2\) - 2\(x\)) + (8\(x\) - 16) = 0
\(x\)(\(x\) - 2) + 8(\(x-2\)) = 0
(\(x\) - 2)(\(x\) + 8) = 0
\(\left[{}\begin{matrix}x-2=0\\x+8=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=2\\x=-8\end{matrix}\right.\)
Vậy \(x\) \(\in\) {2; - 8}
b; \(\dfrac{242}{363}\) + \(\dfrac{160}{210}\) = \(\dfrac{2}{7}\) x \(x\)
\(\dfrac{2}{3}\) + \(\dfrac{16}{21}\) = \(\dfrac{2}{7}\) x \(x\)
\(\dfrac{14}{21}\) + \(\dfrac{16}{21}\) = \(\dfrac{2}{7}\) x \(x\)
\(\dfrac{30}{21}\) = \(\dfrac{2}{7}\) x \(x\)
\(\dfrac{10}{7}\) = \(\dfrac{2}{7}\) x \(x\)
\(x\) = \(\dfrac{10}{7}\) : \(\dfrac{2}{7}\)
\(x\) = \(\dfrac{10}{7}\) x \(\dfrac{7}{2}\)
\(x\) = 5
\(\dfrac{242}{363}+\dfrac{160}{210}=\dfrac{2}{7}\times x\\ \dfrac{2}{3}+\dfrac{16}{21}=\dfrac{2}{7}\times x\\ \dfrac{2}{7}\times x=\dfrac{14}{21}+\dfrac{16}{21}\\ \dfrac{2}{7}\times x=\dfrac{20}{21}\\ x=\dfrac{20}{21}:\dfrac{2}{7}\\ x=\dfrac{10}{3}\)
\(5^{20}:\left(5^{15}\cdot6+5^{15}\cdot19\right)\\ =5^{20}:\left[5^{15}\cdot\left(6+19\right)\right]\\ =5^{20}:\left(5^{15}\cdot25\right)\\ =5^{20}:5^{17}\\ =5^3\\ =125\)
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\(7^{18}:7^{16}+2^2\cdot3^3\\ =7^{18-16}+4\cdot27\\ =7^2+108\\ =49+108\\ =157\)
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\(59\cdot73-30^2+27\cdot59\\ =59\cdot\left(73+27\right)-30^2\\ =59\cdot100-30^2\\ =5900-900\\ =5000\)
125
157
5000