a) Ta có : 24:x; 36:x; 150:x và x lớn nhất

⇒x là ƯCLN ( 24;36;150)

24=2³.3

36=2².3²

150=2.3.5²

UCLN (24;36;160)=2 . 3 = 6

\(71\dfrac{23}{45}+\left(43\dfrac{22}{45}+1\dfrac{1}{6}\right)\)

\(=\dfrac{3218}{45}+\left(\dfrac{1957}{45}+\dfrac{7}{6}\right)\)

\(=\dfrac{3218}{45}+\dfrac{1957}{45}+\dfrac{7}{6}\)

\(=115+\dfrac{7}{6}\) \(=\dfrac{697}{6}\)

x: (2x -1) . (5x+3/4) =0  đk x # 1/2

⇔ x = 0 hoăc 5x + 3/4 = 0⇒ x = -3/4: 5 = -3/20

vậy x = {-3/20; 0}

`(2/3x - 1) . (5x + 3/4) = 0`

`=>` \(\left[{}\begin{matrix}\dfrac{2}{3}x-1=0\\5x+\dfrac{3}{4}=0\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}\dfrac{2}{3}x=0+1\\5x=0-\dfrac{3}{4}\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}\dfrac{2}{3}x=1\\5x=-\dfrac{3}{4}\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}x=1:\dfrac{2}{3}\\x=-\dfrac{3}{4}:5\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=-\dfrac{3}{20}\end{matrix}\right.\)

Vậy......

Help

no

Có: \(28=2^2.7\)

\(56=2^4.7\)

\(72=2^3.3^2\)

\(ƯCLN\left(28;56;72\right)=2^2=4\)

2x-2=x

2x=x+2

2x-x=x+2-x

x=2

đúng thì tick cho mình nhé

`|-x+5|=35`

`@TH1:`

`-x+5=35`

`=> -x = 35-5`

`=> -x=-40`

Vậy `-x=-40`

`@TH2:`

`-x+5=35`

`=> -x=35-5`

`=> -x=30(loại)`

Vậy `x = -40`

\(\overline{abc}.\overline{abca}=\overline{abcabc}\)

\(\Rightarrow\overline{abc}.\left(10.\overline{abc}+a\right)=\overline{abc}.1001\)

\(\Rightarrow10.\overline{abc}+a=1001\)

\(\Rightarrow10.\overline{abc}=1001-a⋮10\Rightarrow a=1\)

\(\Rightarrow10.\overline{1bc}=1000\)

\(\Rightarrow10.\left(100+\overline{bc}\right)=1000\)

\(\Rightarrow1000+10.\overline{bc}=100\Rightarrow\overline{bc}=0\)

\(\Rightarrow\overline{abc}=100\)