\(=\frac{15}{16}-log_a\left[\left(\left(a^{\frac{1}{4}}\right)^{\frac{1}{4}}\right)^{10+1}\right]\)

\(=\frac{15}{16}-log_aa^{\frac{11}{16}}=\frac{15}{16}-\frac{11}{16}=\frac{1}{4}\)

A= một con số nào đó

b la dap an dung

Trả lời:

Đáp án C. 116

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3 nhó cái cho mk

1+2=3

đúng luôn còn gì :)))

đáp án A

đáp án B

trời tưởng gì =0 vì có 0x..... ở khuc sau

tính E(300)=300/log2(300), E(90000)=90000/log2(90000)

Vì độ hiệu quả tỉ lệ thuận với thời gian thực hiện

nên ta có tỉ số 0,02/E(300)=x/E(90000) (x là giá trị cần tìm).

Từ đó tính được x=3