912 . 19 – 324 . 19
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2x+1 -2x-1 = 52 - 50
2x+1 - 2x-1 = 24
2x-1.(22-1) = 24
2x-1.3 = 24
2x-1 = 24 : 3
2x-1 = 8
2x-1 = 23
x - 1 = 3
x = 4
2x = 52
2x+1 -2x-1 = 52 - 50
2x+1 - 2x-1 = 24
2x-1.(22-1) = 24
2x-1.3 = 24
2x-1 = 24 : 3
2x-1 = 8
2x-1 = 23
x - 1 = 3
x = 4
2x = 52
Ta có:
\(A=2020^{2023}-2020^{2022}=2020^{2022}\left(2020-1\right)=2019.2020^{2022}\\ B=2020^{2022}-2020^{2021}=2020^{2021}\left(2020-1\right)=2019.2020^{2021}\)
\(A-B=2019.2020^{2022}-2019.2020^{2021}=2019.2020^{2021}\left(2020-1\right)>0\\ \Rightarrow A>B\)
\(\left\{132-\left[116-\left(16-8\right)\right]:2\right\}.5\)
\(=\left\{132-\left[116-8\right]:2\right\}.5\)
\(=\left\{132-108:2\right\}.5\)
\(=390\)
\(3.5^x-8=367\)
\(\Leftrightarrow3.5^x=375\)
\(\Leftrightarrow5^x=125\)
\(\Leftrightarrow x=3\)
`4^3 .125 - 125 . 5^2`
`= 64* 125 - 125* 25`
`= (64-25) * 125`
`= 39*125`
`=4875`
\(9^{12}.19-3^{24}.19\\ =\left(3^2\right)^{12}.19-3^{24}.19\\ =3^{24}.19-3^{24}.19=0\)
ét o ét