Đặt \(B=\dfrac{5}{1\cdot2\cdot3}+\dfrac{5}{2\cdot3\cdot4}+...+\dfrac{5}{98\cdot99\cdot100}\)

=>\(B=5\left(\dfrac{1}{1\cdot2\cdot3}+\dfrac{1}{2\cdot3\cdot4}+...+\dfrac{1}{98\cdot99\cdot100}\right)\)

\(B=5A=\dfrac{-5\cdot4949}{19800}=-\dfrac{4949}{3960}\)

a: 15x8+8x6-5

=8x(15+6)-5

=8x21-5

=168-5=163

b: 18+9x3+45

=63+27

=90

Bài làm:

a, 15x8+8x6-5

= 8x(15+6)-5

=8x21-5 

nhân chia trước công trừ sau, tính trong ngoặc trước

=168-5

=163

b, 18+9x3+45

=9x2+9x3+9x5

=9x(2+3+5)

=9x10

=90

Chúc bạn học tốt!

\(C=5\dfrac{9}{10}:\dfrac{3}{2}-\left(2\dfrac{1}{3}\cdot4\dfrac{1}{2}-2\cdot2\dfrac{1}{3}\right):\dfrac{7}{4}\)

\(=\dfrac{59}{10}\cdot\dfrac{2}{3}-\left(\dfrac{7}{3}\cdot\dfrac{9}{2}-2\cdot\dfrac{7}{3}\right)\cdot\dfrac{4}{7}\)

\(=\dfrac{59}{15}-\dfrac{7}{3}\cdot\dfrac{5}{2}\cdot\dfrac{4}{7}\)

\(=\dfrac{59}{15}-\dfrac{10}{3}=\dfrac{9}{15}=\dfrac{3}{5}\)

\(\dfrac{27^4\cdot4^3}{9^5\cdot8^2}=\dfrac{\left(3^3\right)^4\cdot2^6}{\left(3^2\right)^5\cdot2^6}=\dfrac{3^{12}}{3^{10}}=3^2=9\)

a: \(x^3+xy^2-y^2-1\)

\(=\left(x^3-1\right)+y^2\left(x-1\right)\)

\(=\left(x-1\right)\left(x^2+x+1\right)+y^2\left(x-1\right)\)

\(=\left(x-1\right)\left(x^2+x+1+y^2\right)\)

b: \(12x^2+4x-6xy-2y\)

\(=4x\left(3x+1\right)-2y\left(3x+1\right)\)

\(=\left(3x+1\right)\left(4x-2y\right)=2\left(2x-y\right)\left(3x+1\right)\)

\(42\cdot40+6\cdot8\cdot21-22\cdot96\)

\(=42\cdot40+24\cdot42-22\cdot96\)

\(=42\left(40+24\right)-22\cdot1,5\cdot64\)

\(=64\cdot42-64\cdot33=64\cdot9=576\)

\(250=5^3\cdot2\)

=>\(Ư\left(250\right)=\left\{1;-1;2;-2;5;-5;10;-10;25;-25;50;-50;125;-125;250;-250\right\}\)

\(Ư\left(250\right)\)\(=\left\{1;2;5;10;25;50;125;250\right\}\)

@Chu Gia Hân

bạn hỏi gì vậy???