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Yêu cầu chứng minh của đề chưa rõ bạn nhé!
\(\overline{ab}\times\overline{ab}-8557=0\\ \Rightarrow\left(\overline{ab}\right)^2=8557\)
Nhận xét:
\(\left(\overline{ab}\right)^2\) là số chính phương; 8557 không phải số chính phương
Do đó kết quả sai
Vậy...
\(3+x+2\times x=805\\ 3+3\times x=805\\ 3\times x=805-3\\ 3\times x=802\\ x=\dfrac{802}{3}\)
\(A=\left\{0,1,2,3,4,5,6,7\right\}\)
Quy luật: Số tiếp theo trong dãy bằng lập phương số thứ tự của nó
Số cần tìm là: \(5^3=125\)
\(24\cdot\left[\left(-12\right):8-2^2\right]+\left(-24\right):\left(-1\right)\\ =24\cdot\left(-\dfrac{3}{2}-4\right)+24\\ =24\cdot\left(-\dfrac{11}{2}+1\right)\\ =24\cdot\left(-\dfrac{9}{2}\right)\\ =-108\)
a)
\(248\times36+4\times64\times62\\ =248\times36+ \left(4\times62\right)\times64\\ =248\times36+248\times64\\ =248\times\left(36+64\right)\\ =248\times100\\ =24800\)
Xin lỗi mình ghi thiếu!
Diện tích tam giác ABC là:
\(\dfrac{AB\cdot BC}{2}=\dfrac{10\cdot12}{2}=60\left(dm^2\right)\)
Vậy diện tích tam giác ABC là 60 dm2
Theo đề bài ta có:
+) \(AB+AC+BC=37\left(dm\right)\)
+) \(AB=\dfrac{2}{3}AC\); \(BC=\dfrac{4}{5}AC\)
Thay vào \(AB+AC+BC=37\) được:
\(\dfrac{2}{3}AC+AC+\dfrac{4}{5}AC=\dfrac{37}{15}AC=37\)
\(\Rightarrow AC=37:\dfrac{37}{15}=15\left(dm\right)\)
Thay vào \(AB=\dfrac{2}{3}AC;BC=\dfrac{4}{5}AC\) được:
\(\left\{{}\begin{matrix}AB=\dfrac{2}{3}\cdot15=10\left(dm\right)\\BC=\dfrac{4}{5}\cdot15=12\left(dm\right)\end{matrix}\right.\)
Vậy...
\(67+135+33\\ =\left(67+33\right)+135\\ =100+135\\ =235\)
\(997+86+98+9999\\ =\left(997+86+98\right)+9999\\ =1181+9999\\ =11180\)
\(37\cdot38+62\cdot37\\ =37\cdot\left(38+62\right)\\ =37\cdot100\\ =3700\)
\(53\cdot39+47\cdot39-53\cdot21-47\cdot21\\ =39\cdot\left(53+47\right)-21\cdot\left(53+47\right)\\ =39\cdot100-21\cdot100\\ =100\cdot\left(39+21\right)\\ =100\cdot60\\ =6000\)
\(47\cdot29-13\cdot29-24\cdot29\\ =29\cdot\left(47-13-24\right)\\ =29\cdot10\\ =290\)
\(1754:17-74:17+20:17\\ =1754\cdot\dfrac{1}{17}-74\cdot\dfrac{1}{17}+20\cdot\dfrac{1}{17}\\ =\dfrac{1}{17}\cdot\left(1754-74+20\right)\\ =\dfrac{1}{17}\cdot\left[\left(1754+20\right)-74\right]\\ =\dfrac{1}{17}\cdot\left(1774-74\right)\\ =\dfrac{1}{17}\cdot1700\\ =100\)