So sánh 5^31 và 9^19
:3 Làm nhanh giúp em đi các 13 pro max =)
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`2^(x+2) = 2^7`
`x = 5`
`x^3 = 46 + 18`
`x^3 = 64`
`x = 4`
`3(2x+1)^3 = 375`
`(2x+1)^3 = 125`
`2x + 1 = 5`
`x = 2`
`2^x .4 = 8^2 . 2`
`2^x . 4 =64.2`
`2^x .4 = 128`
`2^x = 128:4`
`2^x = 32`
`2^x=2^5`
`=> x=5`
___________________________
`x^3 - 6^2 : 2 = 46`
`x^3 - 18=46`
`x^3=46+18`
`x^3 = 64`
`x^3 = 4^3`
`=>x=4`
____________________
`25^2 - 3.(2x+1)^3 = 250`
`625 - 3.(2x+1)^3 = 250`
` 3.(2x+1)^3 =625-250`
`3.(2x+1)^3 =375`
`(2x+1)^3=375 : 3`
`(2x+1)^3 = 125`
`(2x+1)^3=5^3`
`2x+1=5`
`2x=5-1`
`2x=4`
`=>x=2`
`121-7.(x-1)=10`
`7.(x-1)=121-10`
`7.(x-1)=111`
`x-1=111:7`
`x-1=111/7`
`x=111/7 + 7/7`
`x=118/7`
Vậy `x=118/7`
\(121-7.\left(x-1\right)=10\)
\(7.\left(x-1\right)=121-10\)
\(7.\left(x-1\right)=111\)
\(x-1=111:7\)
\(x-1=\dfrac{111}{7}\)
\(x=\dfrac{111}{7}+1\)
\(x=\dfrac{187}{7}\)
3x^6-1=2
(=) 3x^6=2+1
(=) 3x^6=3
(=) x^6=3:3
(=)x^6=1
=> x=1
1. 324 + [ 112 - ( 112 + 324 ) ]
= 324 + ( 112 - 436)
= 324 + ( - 324 )
= 0
2. ( - 59 + 71 ) - ( - 83 - 59 )
= 12 - ( - 412 )
= 424
3. - 257 - [ ( - 257 + 156 ) - 56 ]
= - 257 - ( - 101 - 56 )
= - 257 - ( - 157 )
= - 100
`324 + [ 112 - ( 112 + 324 ) ]`
`= 324 + ( 112 - 436)`
`= 324 + ( - 324 )`
`=324-324`
`=0`
________________________________
` - 257 - [ ( - 257 + 156 ) - 56 ]`
`= - 257 - ( - 101 - 56 )`
`= - 257 - ( - 157 )`
`-257 + 157`
`= - 100`
_________________________
`-329 + (15-101)-(25-440)`
`=-329 + 15 - 101 - 25 + 440`
`=(-329 - 101) + (15-25)+440`
`=-430 + (-10)+440`
`=-430 - 10+440`
`=-440 +440`
`=0`
_____________________________________
`4524-(864 - 999) - (36 + 999)`
`=4524 - 864 + 999 - 36 - 999`
`=(4524 - 864 )+(999-999)-36`
`=3660 + 9 -36`
`=3624`
(62 +72 +82+92+102) - (12 +22 +32+42+52)=
(62 -12 ) +(72 - 22 )+( 82 - 32 )+( 92 - 42 )+(102 - 52 )=
(6 -1) x(6+1)+(7 - 2 )(7+2)+( 8 - 3 )(8+3)+( 9 - 4)(9+4)+(10 - 5 )(10+5)
= 5 (7+9+11+13+15)=5x55=275
Ta thấy: 5^31 > 5^30 ; 9^19 < 9^20
Ta có: 5^30 = (5^3)^10 = 125^10
9^20 = (9^2)^10 = 81^10
Mà: 125^10 > 81^10
Vậy: 5^31 > 9^19
Cảm ơn bạn HTN247 nhoa ~ :3