A=2¹⁰.3¹⁰-2¹⁰.3⁹/2¹⁰.3⁸+2¹⁰.3⁸.5

A=2^10.3^9(1.3-1.1)/2^10.3^8(1.1+1.1.5)

A=3.2/1.6

A=6/6=1

\(x+8⋮x-2\)

\(\Rightarrow x-2+10⋮x-2\)

      \(x-2⋮x-2\)

\(\Rightarrow10⋮x-2\)

\(\Rightarrow x-2\inƯ\left(10\right)\)

      \(x\in Z\Rightarrow x-2\in Z\)

\(\Rightarrow x-2\in\left\{-1;-2;-5;-10;1;2;5;10\right\}\)

\(\Rightarrow x\in\left\{1;0;-3;-8;3;4;7;12\right\}\)

Gọi d = ƯCLN _{( 16n + 3 ; 12n + 3 )} 

1. => 16n + 3 \(⋮\)d

12n + 3 \(⋮\)d

=> 3 ( 16n + 3 ) \(⋮\)d

4 ( 12n + 3 ) \(⋮\)d

=> 48n + 9 \(⋮\) \(⋮\)d

48n + 12 \(⋮\)d

=> 3 chia hết cho d

=> d = 1 hoặc d = 3

Sai đề rồi bạn ơi

TA CÓ: OI LÀ TIA NẰM GIỮA OA; OB

\(\Rightarrow\widehat{AOI}+\widehat{IOB}=\widehat{AOB}\)

MÀ: \(\widehat{AOI}=\frac{1}{4}\widehat{IOB}\)

THAY SỐ: \(\frac{1}{4}\widehat{IOB}+\widehat{IOB}=70^0\)

                 \(\Rightarrow\left(\frac{1}{4}+1\right)\widehat{IOB}=70^0\)

                 \(\frac{5}{4}\widehat{IOB}=70^0\)

                      \(\widehat{IOB}=70^0:\frac{5}{4}\)

\(\Rightarrow\widehat{IOB}=56^0\)

MÀ \(\widehat{AOI}=\frac{1}{4}\widehat{IOB}\)

THAY SỐ: \(\widehat{AOI}=\frac{1}{4}.56^0=14^0\)

\(\Rightarrow\widehat{AOI}=14^0\)

CHÚC BN HỌC TỐT!!!!!

\(M=\left|3x+1\right|+3x-49\)

\(M=\left|-3x-1\right|+3x-49\ge-3x-1+3x-49\)

\(M\ge-50\)

\(N=\left|x-7\right|+x-20=\left|7-x\right|+x-20\)

\(N\ge7-x+x-20=-13\)

\(C=\left|2x+5\right|+\left|x-1\right|+\left|2x-35\right|\)

\(C=\left|2x+5\right|+\left|35-2x\right|+\left|x-1\right|\)

\(C\ge\left|2x+5+35-2x\right|+\left|x-1\right|=40+\left|x-1\right|\ge40\)

ĐỂ : m.n -2m-2n =0=> m.n - (2m+2n) =0

=> m.n = 2m+2n

=> m.n = 2.(m+n)

=> m =0

HOẶC n =0

VẬY ..............

CHÚC BN HỌC TỐT!!!