a,-13x=39 b,2x-(-17)=15
c,-7-2x=37-(-24) d,-2(2x+1)=-5(x+1)
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a, 127 - 18 ( 5+6 ) =127 - 18 x11 = -71
b, 26 + 7(4-12) = 26 + 7 x (-8) =-30
TK nha!
a) 127 - 18.(5+6)
= 127 - 18.11
= 127 - 198
= -71
b) 26 + 7.(4-12)
= 26 + 7.(-8)
= 26 + (-56)
= -30
So sánh
ta có: 2433 < 24313
=> \(\frac{1}{243^4}>\frac{1}{243^{13}}\)
#
a ) Ta có
\(\frac{29}{33}>\frac{29}{37}\)( đồng tử khác mẫu )
\(\frac{22}{37}< \frac{29}{37}\)( đồng mẫu khác tử )
=> \(\frac{29}{33}>\frac{29}{37}>\frac{22}{37}\)
b ) \(\frac{163}{257}< \frac{163}{221}\)
\(\frac{162}{257}>\frac{149}{257}\)
\(\Rightarrow\frac{163}{221}>\frac{163}{257}>\frac{149}{257}\)
a) ta có: \(\frac{22}{37}< \frac{29}{37}\)
\(\frac{29}{33}>\frac{29}{37}\)
\(\Rightarrow\frac{22}{37}< \frac{29}{37}< \frac{29}{33}\)
b) ta có: \(\frac{163}{257}>\frac{149}{257}\)
\(\frac{163}{221}>\frac{163}{257}\)
\(\Rightarrow\frac{163}{221}>\frac{163}{257}>\frac{149}{257}\)
a) \(\frac{3}{3}-\left(x-\frac{7}{3}\right)=-\frac{3}{4}-\frac{9}{8}\)
\(1-\left(x-\frac{7}{3}\right)=-\frac{15}{8}\)
\(x-\frac{7}{3}=1--\frac{15}{8}\)
\(x-\frac{7}{3}=\frac{23}{8}\)
\(x=\frac{23}{8}+\frac{7}{3}=\frac{125}{24}\)
b) \(3-\left(\frac{8}{3}-x+\frac{5}{4}\right)=1-\left(\frac{7}{6}-\frac{5}{12}\right)\)
\(3-\left(\frac{8}{3}-x+\frac{5}{4}\right)=\frac{1}{4}\)
\(\frac{8}{3}-x+\frac{5}{4}=1-\frac{1}{4}\)
\(-x=1-\frac{1}{4}-\frac{8}{3}-\frac{5}{4}\)
\(-x=-\frac{19}{6}\)
\(\Rightarrow x=\frac{19}{6}\)
a) -13x = 39
=> x = 39 : (-13)
x= -3
b) 2x - (-17) = 15
=> 2x = 15 + (-17)
2x = -2
x = -1
c) -7-2x = 37-(-24)
-7-2x = 61
2x = -7-61
2x = -68
x = -34
d) -2.(2x+1) = -5.(x+1)
-4x - 2 = -5x - 5
=> -4x + 5x = -5 + 2
x = -3