Ta có \(x+34⋮x+1\)

\(\Rightarrow\left(x+1\right)+33⋮x+1\)

\(\Rightarrow33⋮x+1\)

\(\Rightarrow x+1\in\text{Ư}\left(33\right)\)

\(\Rightarrow x+1\in\left\{1;-1;3;-3;11;-11;33;-33\right\}\text{ }\)

\(\Rightarrow x\in\left\{0;-2;2;-4;10;-12;31;-34\right\}\)

b, có nhiều nhất 70 HS

Theo mình thì khoảng cách sau gấp đôi khoảng cách trước

VD: 60 - 24 = 36

      24 - 6 = 18

36 gấp đôi 18

A=2+2²+2³+2⁴+...+2⁸

=> 2A=2²+2³+2⁴+2⁵+...+2⁹

=> 2A-A=2⁹-2

A=2⁹-2

A = 510

2A = 2( 2 + 2^2 + .. + 2^8)

2A = 2^2 + 2^3 + .. + 2^9

2A - A = ( 2^2 + 2^3 +.. + 2^9) - (2 + 2^2 + .. +2^8)

A = 2^2 + 2^3 +.. + 2^9 - 2 - 2^2 -...- 2^8

A = 2^9 - 2

\(10^{30}=\left(10^3\right)^{10}=1000^{10}< 1024^{10}=\left(2^{10}\right)^{10}=2^{100}\\ \)

10^30=(10^3)^10=1000^10

2^100=(2^10)^10=1024^10

Vì 1000^10<1024^10

=> 10^30 < 2^100

3x5=15

4x6=24

4x7=28

3x5=15

4x6=24

4x7=28

\(\frac{10}{15}=\frac{\frac{20}{3}}{10}\); \(\frac{12}{16}=\frac{7.5}{10}\); \(\frac{63}{72}=\frac{8.75}{10}\); \(\frac{80}{96}=\frac{\frac{25}{3}}{10}\)

= 2. 22.(-36) + 22.( - 28)

= 22( 2.(-36) + (-28)

= 22. (-72 - 28)

= 22. (-100)

= -2200

=22.2.(-36)+22.(-28)

=22.(-72)+22.(-28)

=22[(-72)+(-28)]

=22.(-100)

=-2200

c )D = 1 + 4 + 4^2 + 4^3 + ... + 4^69

D = ( 1 + 4 )  + ( 4^2 + 4^3 ) + (  4^4 + 4^5 ) + ... + ( 4^68 + 4^69 )

D = 5 + 4^2( 1 + 4 ) + 4^4( 1 + 4 ) + ... + 4^68( 1 + 4 )

D = 5 + 4^2 . 5 + 4^4 . 5 + ... + 4^68 . 5

D = 5( 1 + 4^2 + 4^4 + ... + 4^68 ) 

10x + 14x + x = 100

x(10 + 14 + 1) = 100

x. 25 = 100

x = 100 : 25

x = 4

10x + 14x + x = 100

10x + 14x + 1x = 100

( 10 + 14 + 1 ) x X = 100

25 x X = 100

x = 100 : 25 

x = 4

Vậy x = 4 

Tk hộ :v