học giỏi như Hân mà cũng phải hỏi á

\(a.\left(2x+5\right)⋮\left(x+1\right)\)

\(\Rightarrow\left(x+x+1+1+3\right)⋮\left(x+1\right)\)

\(\Rightarrow3⋮\left(x+1\right)\)

\(\Rightarrow x+1\inƯ\left(3\right)\)

\(Ư\left(3\right)=\left\{1;3\right\}\)

\(\Rightarrow x\in\left\{0;2\right\}\)

\(b.\left(2x+8\right)⋮\left(2x+1\right)\)

\(\Rightarrow\left(2x+1+7\right)⋮\left(2x+1\right)\)

\(\Rightarrow7⋮\left(2x+1\right)\)

\(\Rightarrow2x+1\inƯ\left(7\right)\)

\(Ư\left(7\right)=\left\{1;7\right\}\)

\(\Rightarrow x\in\left\{0;3\right\}\)

+) \(A=2+2^2+...+2^{60}\)

\(A=\left(2+2^2\right)+...+\left(2^{59}+2^{60}\right)\)

\(A=2\left(1+2\right)+...+2^{59}\left(1+2\right)\)

\(A=2\cdot3+...+2^{59}\cdot3\)

\(A=3\cdot\left(2+...+2^{59}\right)⋮3\left(đpcm\right)\)

+) \(A=2+2^2+2^3+...+2^{60}\)

\(A=\left(2+2^2+2^3+2^4\right)+...+\left(2^{57}+2^{58}+2^{59}+2^{60}\right)\)

\(A=2\left(1+2+2^2+2^3\right)+...+2^{57}\left(1+2+2^2+2^3\right)\)

\(A=2\cdot15+...+2^{57}\cdot15\)

\(A=15\cdot\left(2+...+2^{57}\right)⋮15\left(đpcm\right)\)

dễ quá bạn ơi'

(7x - 11 )^3 = 32*25+200

(7x - 11 ) ^3 = 1000 

(7x-11)^3 = 10^3 

=> 7x - 11 = 10 => 7x = 11 + 10 = 21 => x = 21 : 7 => x = 3 

bạn ơi là 2^5va5^2 bạn 

(4x-3)^3= -125

(4x-3)^3=(-5)^3

4x-3=-5

4x=-2

x=-1/2

 \(\left(4x-3\right)^3=-125\)

\(\left(4x-3\right)^3=\left(-5\right)^3\)

\(4x-3=-5\)

\(x=-\frac{1}{2}\)

3.2^x - 3 = 45

3.2^x = 48

2^x= 16

2^x= 2⁴

x=4

Lồn Olinemaths trừ điểm hỏi đáp của tao

Lồn Cặc chó OLM lloooon OLM cặc shit OLM

\(3^{299}< 3^{300}=\left(3^3\right)^{100}=27^{100}\)

\(2^{502}>2^{500}=\left(2^5\right)^{100}=32^{100}\)

Vì \(27^{100}< 32^{100}\)nên \(3^{299}< 27^{100}< 32^{100}< 2^{502}\)

thank you