a) | X + 1 | - 16 = -3
b) 12 - | X – 9 | = -1
c) | X + 1 | + 12 = 5
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a,(567-46)-(54+567)
=567-46+54-567
=567.(46+54)
=567.100
=56700
7 ( x – 9 ) – 5 ( 6 – x ) = -6 + 11x
7x - 7.9 - 5.6 + 5x = -6 + 11x
7x - 63 - 30 + 5x = -6 + 11x
7x + 5x - 63 - 30 - 11x = -6
7x + 5x - 11x = -6 + 63 + 30
7x + 5x - 11x = 87
x ( 7 + 5 -11 ) = 87
x . 1 = 87
x = 87
a, Ta có: \(|-n+8|\ge0\forall n\)
\(\Rightarrow|-n+8|-21\ge-21\forall n\)
Hay: \(A\ge-21\forall n\)
Vậy: Min A = -21 tại \(|-n+8|=0\) \(\Rightarrow n=8\)
b,Ta có: \(-3|2x+50|\le0\forall x\)
\(\Rightarrow-21-3|2x+50|\le-21\forall x\)
Hay: \(B\le-21\forall x\)
Vậy: Max B =-21 tại \(-3|2x+50|=0\) \(\Rightarrow x=-25\)
=.= hk tốt!!
\(124+\left(13-16\right)=162-\left(x+162\right).\)
\(124+13-16=162-\left(x+162\right)\)
\(121=162-\left(x+162\right)\)
\(41=x+162\)
\(x=41-162=\left(-121\right)\)
124 + ( 13 – 16 ) = 162 – ( x + 162 )
124 + (-3) = 162 - ( x + 162 )
121 = 162 - ( x + 162 )
\(\Rightarrow\)162 - ( x + 162 ) = 121
162 - x - 162 = 121
( 162 - 162 ) - x = 121
0 - x = 121
- x = 121
\(\Rightarrow\) x = -121
\(7\left(x-3\right)-5\left(3-x\right)=11x-5.\)
\(\left(7x-21\right)-\left(15-5x\right)=11x-5\)
\(7x-21-15+5x=11x-5\)
\(12x-36=11x-5\)
\(12x-11x=36-5\)
\(x=31\)
7 (x - 3) - 5 (3 - x) = 11x - 5
7x - 7.3 - 5.3 - 5x = 11x - 5
7x - 5x - 21 -15 = 11x - 5
2x - (21 + 15) = 11x - 5
2x - 36 = 11x - 5
2x - 11x = 36 - 5
-9x = 31
x = 31:(-9)
x = \(\frac{-31}{9}\)
a) \(|x+1|\)-16 = -3
\(|x+1|\) = -3 + 16
\(|x+1|\) = 13
=> \(|x+1|\)\(\in\left\{13;-13\right\}\)
TH1: x + 1 = 13
x = 12
TH2 : x + 1 = -13
x = -14
vậy x \(\in\left\{12;-14\right\}\)
\(a,\left|x+1\right|-16=-3\)
\(\Leftrightarrow\left|x+1\right|=13\)
\(\Leftrightarrow\orbr{\begin{cases}x+1=13\\x+1=-13\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=12\\x=-14\end{cases}}\)
\(b;12-\left|x-9\right|=-1\)
\(\Leftrightarrow\left|x-9\right|=13\)
\(\Leftrightarrow\orbr{\begin{cases}x-9=13\\x-9=-13\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=22\\x=-4\end{cases}}\)
\(c,\left|x+1\right|+12=5\)
\(\Leftrightarrow\left|x+1\right|=-7\)
Vì \(\left|x\right|\ge0\Rightarrow\left|x+1\right|=-7\left(loại\right)\)