Tìm x biết
a) 2x - 138 = \(2^3\) : \(\left(-3\right)^2\)
b) 10 + 2x = \(\left(-4\right)^5\) : \(\left(-4\right)^3\)
c) \(3^2\) x -60. ( x - 7 ) = - \(5^2\) - \(^{\left(-7\right)^2}\)
d) Tìm x \(\in\) N để:
1) 27 - 5x \(⋮\)x - 2
2) 2x + 3 \(⋮\)x - 2
3) 3x + 1 \(⋮\)11 - 2x
\(a,2x-138=2^3:\left(-3\right)^2\)
\(\Rightarrow2x-138=8:9\)
\(\Rightarrow2x=\frac{8}{9}+138\)
\(\Rightarrow2x=\frac{1250}{9}\)
\(\Rightarrow x=\frac{626}{9}\)
\(10+2x=\left(-4\right)^5:\left(-4\right)^3\)
\(10+2x=-1024:\left(-64\right)\)
\(10+2x=16\)
\(2x=16-10\)
\(2x=6\)
\(x=6:2=3\)