\(\Rightarrow32\left(2x+3\right)=24\left(3x-1\right)\)

\(\Rightarrow64x+96=72x-24\)

\(\Rightarrow96+24=72x-64x\)

\(\Rightarrow120=8x\)

\(\Rightarrow x=\frac{120}{8}\)

\(\Rightarrow x=15\)

Vậy x=15

\(\frac{2x+3}{24}=\frac{3x-1}{32}\)

\(\Leftrightarrow32\left(2x+3\right)=24\left(3x-1\right)\)

\(\Leftrightarrow64x+96=72x-24\)

\(\Leftrightarrow64x-72x=-96-24\)

\(\Leftrightarrow-8x=-120\)

\(\Leftrightarrow x=15\)

Vậy x = 15

\(\frac{x-1}{3}=\frac{x+3}{5}\)

\(\Leftrightarrow5\left(x-1\right)=3\left(x+3\right)\)

\(\Leftrightarrow5x-5=3x+9\)

\(\Leftrightarrow5x-3x=5+9\)

\(\Leftrightarrow2x=14\)

\(\Leftrightarrow x=7\)

Vậy x = 7

Ta có: \(\frac{x-1}{3}=\frac{x+3}{5}\)

=> \(5\left(x-1\right)=3\left(x+3\right)\)

=> \(5x-5=3x+9\)

=> \(5x-3x=9+5\)

=> \(2x=14\)

=> \(x=\frac{14}{2}=7\).

\(\frac{x+1}{x-2}=\frac{3}{4}\)=>\(4\left(x+1\right)=3\left(x-2\right)\)( Nhân chéo)

=> 4x + 4 = 3x - 6 

=> 4x - 3x = -6 - 4

=> x = -10

\(\frac{x+1}{x-2}=\frac{3}{4}\)​​x = 3-1 = 2

x = 4 +2 = 6

đề sai ak bn

mình sửa lại đề nhé

\(\frac{x-1}{2}=\frac{y-2}{3}\Rightarrow\frac{3\left(x-1\right)}{2}=y-2\Rightarrow y=\frac{3\left(x-1\right)}{2}+2=\frac{3\left(x-1\right)+4}{2}\)(1)

\(\frac{x-1}{2}=\frac{z-3}{4}\Rightarrow\frac{4\left(x-1\right)}{2}=z-3\Rightarrow z=\frac{4\left(x-1\right)}{2}+3=\frac{4\left(x-1\right)+6}{2}\)(2)

Từ (1) và (2) => 2x+3y-z=\(2x+3\left(\frac{3\left(x-1\right)+4}{2}\right)-\frac{4\left(x-1\right)+6}{2}=50\)

\(\Rightarrow\frac{4x}{2}+\frac{9\left(x-1\right)+12}{2}-\frac{4\left(x-1\right)+6}{2}=50\)

\(\Rightarrow\frac{4x+9x-9+12-4x+4-6}{2}=50\)

\(\Rightarrow9x+1=100\)

\(\Rightarrow9x=99\)

\(\Rightarrow x=11\)

Vì \(y=\frac{3\left(x-1\right)+4}{2}=\frac{3\left(11-1\right)+4}{2}=\frac{34}{2}=17\Leftrightarrow y=17\)

Vì \(z=\frac{4\left(x-1\right)+6}{2}=\frac{4\left(11-1\right)+6}{2}+\frac{46}{2}=23\Leftrightarrow z=23\)

Vậy   x=11

         y=17

         z=23

\(\Rightarrow\frac{2\left(x-1\right)}{2.2}=\frac{3\left(y-2\right)}{3.3}=\frac{z-3}{4}\) 

\(\Rightarrow\frac{2x-2}{4}=\frac{3y-6}{9}=\frac{z-3}{4}\) 

Áp dụng t/c dãy tỉ số = nhau

\(\Rightarrow\frac{2x-2}{4}=\frac{3y-6}{9}=\frac{z-3}{4}=\frac{2x-2+3y-6-z+3}{4+9-4}=\frac{50-2-6+3}{9}=\frac{45}{9}=5\) 

\(\Rightarrow\hept{\begin{cases}\frac{x-1}{2}=5\Rightarrow x-1=10\Rightarrow x=11\\\frac{y-2}{3}=5\Rightarrow y-2=15\Rightarrow y=17\\\frac{z-3}{4}=5\Rightarrow z-3=20\Rightarrow z=23\end{cases}}\)

AI GIÚP MIK VỚI MÀ T.T

\(\frac{3^4.5^7+3^3.5^8}{3^3.5^7}=\frac{3^3\left(3.5^7+5^8\right)}{3^3.5^7}=\frac{3.5^7+5^8}{5^7}\)= \(\frac{5^7\left(3+5\right)}{5^7}=3+5=8\)

tặng hình nhóe ; 

kết quả=51